AutoCAD Quiz: Basic Drawing Objects
10 questions · exam conditions
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Basic Drawing ObjectsQuestion 1 of 10

During the RECTANG command, a drafter specifies the first corner as (120,80)(120,80) and enters @-40,25 for the opposite corner.

Which description correctly identifies the resulting rectangle?

Corners span (80,80)(80,80) to (120,105)(120,105), with dimensions 4040 by 2525
Corners span (120,80)(120,80) to (160,105)(160,105), with dimensions 4040 by 2525
Corners span (−40,25)(-40,25) to (120,80)(120,80), with dimensions 160160 by 5555
Corners span (80,55)(80,55) to (120,80)(120,80), with dimensions 4040 by 2525
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AutoCAD Quiz

AutoCAD Quiz: Basic Drawing Objects

Practice Basic Drawing Objects in AutoCAD with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Basic Drawing Objects, giving you a quick way to practice the rules, question types, and explanations that matter most for AutoCAD.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

During the RECTANG command, a drafter specifies the first corner as (120,80)(120,80) and enters @-40,25 for the opposite corner.

Which description correctly identifies the resulting rectangle?

  1. Corners span (80,80)(80,80) to (120,105)(120,105), with dimensions 4040 by 2525 (correct answer)
  2. Corners span (120,80)(120,80) to (160,105)(160,105), with dimensions 4040 by 2525
  3. Corners span (−40,25)(-40,25) to (120,80)(120,80), with dimensions 160160 by 5555
  4. Corners span (80,55)(80,55) to (120,80)(120,80), with dimensions 4040 by 2525
Explanation: Whenever you see the @ symbol in AutoCAD coordinate entry, your brain should immediately switch into relative coordinate mode — meaning the values that follow describe a displacement from the last point, not a fixed location on the drawing. Here, the first corner is (120,80)(120, 80). The entry @-40,25 tells AutoCAD to move 40 units in the negative X direction and 25 units in the positive Y direction from that point. Calculating the opposite corner: 120+(−40)=80120 + (-40) = 80 for X, and 80+25=10580 + 25 = 105 for Y. The opposite corner lands at (80,105)(80, 105), giving you a rectangle spanning (80,80)(80, 80) to (120,105)(120, 105) with dimensions 40×2540 \times 25. That confirms A is correct. B is wrong because it adds +40+40 instead of −40-40, landing at (160,105)(160, 105) — a common sign error when students drop the negative from the X displacement. C confuses relative entry with absolute coordinates entirely, treating @-40,25 as if it means the literal point (−40,25)(-40, 25) on the drawing — that's the trap of ignoring the @ symbol. D subtracts 25 from the Y-coordinate instead of adding it, producing (80,55)(80, 55) — a sign error on the Y value this time. A reliable study tip: always read @x,y as "from here, go x in X and y in Y." Write out the addition explicitly — 120+(−40)120 + (-40) and 80+2580 + 25 — to avoid dropping negative signs, which is the most frequent mistake on coordinate entry questions.

Question 2

A drafter runs ARC, specifies the start point as (10,0)(10,0), chooses the Center option and enters (0,0)(0,0), then specifies the endpoint as (0,−10)(0,-10). No direction override is used.

Which arc does AutoCAD create?

  1. A 270∘270^{\circ} counterclockwise arc with radius 1010 (correct answer)
  2. A 90∘90^{\circ} clockwise arc with radius 1010
  3. A 90∘90^{\circ} counterclockwise arc with radius 1010
  4. A 270∘270^{\circ} clockwise arc with radius 1010
Explanation: Whenever you work with AutoCAD's ARC command, the single most important rule to internalize is this: by default, AutoCAD always draws arcs counterclockwise (CCW). This is the positive direction in standard mathematical convention, and AutoCAD honors it unless you explicitly override it. Here, the drafter uses the Start, Center, End method. The start point is (10,0)(10, 0), the center is (0,0)(0, 0), and the endpoint is (0,−10)(0, -10). The radius is clearly 102=10\sqrt{10^2} = 10 for both points, which checks out. Now ask yourself: traveling counterclockwise from (10,0)(10, 0) around the origin, where does (0,−10)(0, -10) fall? Moving CCW from the positive x-axis, you pass through (0,10)(0, 10) at 90°90°, then (−10,0)(-10, 0) at 180°180°, then (0,−10)(0, -10) at 270°270°. So AutoCAD sweeps a 270°270° CCW arc — making A the correct answer. B is wrong because the arc is not clockwise; AutoCAD defaults to CCW. C is wrong on two counts — the direction is still CCW (correct), but a 90°90° sweep from (10,0)(10,0) CCW would end at (0,10)(0, 10), not (0,−10)(0, -10). D is wrong because, while 270°270° is the right angular span, the direction is CCW, not clockwise — a 270°270° CW arc would actually trace the short path instead. Your takeaway: on any AutoCAD arc question, immediately ask "which direction is CCW from the start point, and how far must I travel to reach the endpoint?" That single habit eliminates most arc direction errors.

Question 3

While drawing with PLINE, a drafter specifies the first point, selects Width, enters a starting width of 22 and an ending width of 66, and then draws two consecutive line segments without changing the width again.

How are the widths applied to the two segments?

  1. The first tapers from 66 to 22; the second remains uniformly at 22
  2. Both segments taper independently from 22 to 66 along their lengths
  3. The first remains uniformly at 22; the second remains uniformly at 66
  4. The first tapers from 22 to 66; the second remains uniformly at 66 (correct answer)
Explanation: When using PLINE with the Width option, you set a starting width and an ending width for the next segment you draw. Here's the key behavior to internalize: once that segment is drawn, AutoCAD automatically promotes the ending width to become the new starting width for all subsequent segments — and holds it there uniformly until you explicitly change the width again. So in this scenario, you set a starting width of 22 and an ending width of 66. The first segment tapers from 22 to 66 along its length. When you begin the second segment without changing the width, AutoCAD sets both the starting and ending width to 66 — the value the previous segment ended with — making the second segment a uniform width of 66. That's exactly what answer D describes, making it correct. Answer A gets the taper direction backwards — the first segment would go from 22 to 66, not 66 to 22. Answer B suggests both segments taper independently from 22 to 66, which would only be true if you re-entered the width settings before each segment — AutoCAD does not reset widths automatically between segments. Answer C implies both segments are uniform with no taper at all, ignoring the width transition entirely. A useful memory trick: think of the ending width as being "handed off" to the next segment like a baton. Whatever width the previous segment ends at, that value locks in as the uniform width going forward. On exam questions about PLINE width, always trace that handoff carefully.

Question 4

A drafter starts PLINE, draws one line segment, switches to Arc mode and draws one arc segment, switches back to Line mode and draws another line segment, and then uses Close.

What object structure results when the command is completed?

  1. One closed polyline containing two line segments and two arc segments, because Close adds an arc
  2. Four separate objects — three individual lines and one independent arc — each selectable on its own
  3. One closed polyline containing three line segments and one arc segment, all part of a single object (correct answer)
  4. One region containing three straight edges and one curved edge, created automatically upon closing
Explanation: When working with PLINE in AutoCAD, the critical concept to understand is that everything drawn within a single PLINE command — regardless of how many times you switch between Line and Arc modes — becomes one single polyline object. The command never splits its output into separate objects mid-session. In this scenario, the drafter draws: line segment → arc segment → line segment, then uses Close. The Close option automatically adds a straight line segment back to the starting point (not an arc), completing the shape. That gives you three line segments and one arc segment, all fused into a single closed polyline. That's exactly what C describes, making it the correct answer. A is wrong because Close always closes with a straight line, not an arc. It doesn't detect or match the geometry you last drew — it simply connects the current endpoint to the start point in a straight line. B reflects a fundamental misunderstanding of how PLINE works. Individual line and arc segments drawn within PLINE are not separate objects. They're welded together into one entity. If you want separate objects, you'd use LINE and ARC as individual commands. D is a trap for students who confuse PLINE with REGION. A region is a 2D surface object created via the REGION command (or BOUNDARY). PLINE never automatically produces a region — it produces a polyline, which is a path, not a filled surface. Your study tip: remember that PLINE is a single-object command — one command execution, one object, always. If a question asks about object count after PLINE, the answer is almost always one.

Question 5

Using a single invocation of LINE, a drafter specifies four corner points of an outline in sequence and then enters Close to connect the fourth point back to the first.

How will the completed outline differ from an equivalent outline created with one closed PLINE command?

  1. It consists of three separate lines because the closing edge is not retained
  2. It becomes one closed polyline because Close automatically joins all line segments
  3. It consists of four separate line objects rather than one closed polyline object (correct answer)
  4. It becomes one region because the final edge produces a closed boundary
Explanation: When working with AutoCAD drawing commands, one of the most important distinctions to understand is the difference between object types, not just visual outcomes. A LINE command and a PLINE (polyline) command can produce shapes that look identical on screen, but they create fundamentally different objects in the drawing database. When you use a single LINE command to draw four corners and enter Close, AutoCAD draws the closing segment back to the first point — so visually you get a complete four-sided shape. However, each segment created during a LINE command is stored as an independent line object. Four segments means four separate objects, which is exactly what answer C describes. This matters enormously when you try to select, offset, or edit the shape later. Answer A is wrong because Close does draw the fourth segment — it doesn't drop it. You end up with all four sides present, not three. Answer B describes what happens with PLINE, not LINE — the Close option within a LINE command does not merge segments into a polyline. It simply draws the final connecting segment and ends the command. Answer D is incorrect because a region is a separate object type created with the REGION command; closing a LINE sequence doesn't automatically produce one. A reliable study tip: whenever a question contrasts LINE and PLINE, ask yourself "how many objects result?" LINE always produces one object per segment; PLINE produces one unified object regardless of how many vertices you specify. This single distinction drives many AutoCAD exam questions.

Question 6

A circle must have the points (2,4)(2,4) and (10,10)(10,10) at opposite ends of its diameter. The drafter uses the 2P option of the CIRCLE command and selects those points.

What center and radius will the resulting circle have?

  1. Center (6,7)(6,7) and radius 55 drawing units (correct answer)
  2. Center (6,7)(6,7) and radius 1010 drawing units
  3. Center (4,3)(4,3) and radius 55 drawing units
  4. Center (8,6)(8,6) and radius 1010 drawing units
Explanation: When AutoCAD's CIRCLE command uses the 2P option, the two points you select define the diameter — not the radius. This means the circle is fully determined by those two endpoints, and your job is to extract the center and radius from them using basic geometry. The center of any circle defined by two diameter endpoints is simply the midpoint of those two points. For (2,4)(2,4) and (10,10)(10,10): Center=(2+102, 4+102)=(6, 7)\text{Center} = \left(\frac{2+10}{2},\ \frac{4+10}{2}\right) = (6,\ 7) The radius is half the diameter. The diameter length comes from the distance formula: d=(10−2)2+(10−4)2=64+36=100=10d = \sqrt{(10-2)^2 + (10-4)^2} = \sqrt{64 + 36} = \sqrt{100} = 10 So the radius is 10÷2=510 \div 2 = 5. That confirms answer A — center (6,7)(6,7) and radius 55 drawing units. Answer B gets the center right but uses the full diameter length (1010) as the radius — a classic trap when students forget to halve the distance. Answer C uses incorrect midpoint math, arriving at (4,3)(4,3), which would result from subtracting rather than averaging the coordinates. Answer D compounds errors by producing both a wrong center and the unhalved diameter as the radius. Study tip: Whenever you see 2P in a CIRCLE question, mentally flag it: "These are diameter points, not radius points." Always find the midpoint for the center and divide the full distance by two for the radius — skipping that division is the most common mistake on this type of question.

Question 7

In the current UCS, a drafter starts the LINE command, enters the first point as 20,15, and enters the next point as @30<90.

At which coordinate does the new line segment end?

  1. (20,45)(20,45), because the relative displacement is 3030 units along the positive Y-axis (correct answer)
  2. (50,15)(50,15), because the relative displacement is 3030 units along the positive X-axis
  3. (30,90)(30,90), because the values are interpreted as an absolute Cartesian coordinate
  4. (20,30)(20,30), because the second value replaces the original Y-coordinate
Explanation: When you see polar coordinate notation in AutoCAD, the key is parsing the @ symbol and the < symbol correctly. The @ means relative (offset from the last point), and < separates the distance from the angle in degrees, measured counterclockwise from the positive X-axis. So @30<90 means: "move 30 units at an angle of 90° from the last point." Since 90° points straight up the positive Y-axis, this is a pure vertical displacement. Starting from (20,15)(20, 15), you add 30 to the Y-coordinate and leave X unchanged: (20,15+30)=(20,45)(20, 15+30) = (20, 45). Answer A is correct. Answer B is wrong because it treats the angle as if it were 0° (along the positive X-axis), adding 30 to X instead of Y, yielding (50,15)(50, 15). That would be the result of @30<0, not @30<90. Answer C is wrong because it ignores the @ prefix entirely and reads 30,90 as an absolute Cartesian coordinate. Without @, AutoCAD would treat a comma-separated entry as absolute — but the < symbol signals polar format, not Cartesian, so this misreads both the syntax and the prefix. Answer D is wrong because it confuses the angle value (90) with the new Y-coordinate, as if AutoCAD replaces rather than offsets. No such behavior exists in polar input. A reliable tip: memorize the four common angles — 0°=right, 90°=up, 180°=left, 270°=down — so you can instantly convert any @distance<angle entry into its X/Y displacement on exam day.

Question 8

Two parallel lines are exactly 1212 drawing units apart. A drafter starts CIRCLE, chooses TTR, selects the two lines, and specifies a radius of 55.

What is the expected result?

  1. One circle is created with radius 55 and is tangent to only one line
  2. No circle is created because tangency to both lines requires radius 66 (correct answer)
  3. One circle is created after AutoCAD automatically changes the radius to 66
  4. Two circles are created with radius 55 between the selected parallel lines
Explanation: When using the TTR (Tangent, Tangent, Radius) command in AutoCAD, the geometry of your specified radius must be physically possible given the two selected objects. This is a pure geometry constraint — AutoCAD cannot override it. Here's the key insight: for a circle to be tangent to two parallel lines simultaneously, it must fit perfectly between them, touching each line at exactly one point. That means the circle's diameter must equal the distance between the lines. With lines 1212 drawing units apart, the required diameter is 1212, so the only valid radius is 122=6\frac{12}{2} = 6. A radius of 55 produces a diameter of 1010, which is smaller than the gap — the circle would simply float between the lines without touching either one. Because no valid tangent solution exists, AutoCAD displays an error and creates no circle at all. This confirms that B is correct. Choice A is wrong because TTR either satisfies tangency to both objects or fails entirely — it never produces a circle tangent to only one of the selected lines. Choice C describes behavior AutoCAD does not have; the software will not silently modify your specified radius to make geometry work. Choice D is tempting if you confuse TTR with commands that can produce multiple solutions, but parallel lines with a geometrically impossible radius yield zero results, not two. Study tip: Always ask yourself whether your specified radius is geometrically feasible before running TTR. A quick mental check — does my diameter match or exceed the gap between the objects? — will save you from mysterious "no solution" errors on both the exam and the drafting floor.

Question 9

In the current UCS, a drafter starts RECTANG at (0,0)(0,0), sets its rotation to 30∘30^{\circ}, and uses the Dimensions option to specify a length of 4040 and a width of 2020. The width extends counterclockwise from the length direction.

Approximately where is the diagonally opposite corner?

  1. (40.00,20.00)(40.00,20.00), after applying dimensions without the rotation angle
  2. (34.64,20.00)(34.64,20.00), after rotating only the rectangle's length vector
  3. (37.32,24.64)(37.32,24.64), after interchanging the resulting X and Y components
  4. (24.64,37.32)(24.64,37.32), after combining the rotated length and width vectors (correct answer)
Explanation: When AutoCAD's RECTANG command applies a rotation angle with the Dimensions option, it treats the rectangle's local axes as rotated vectors — meaning both the length direction and the width direction are rotated by that angle. To find the diagonally opposite corner from (0,0)(0,0), you must add the rotated length vector to the rotated width vector (which runs perpendicular, 90° counterclockwise from the length). With a 30°30° rotation, the length vector of 40 contributes 40cos⁡30°=34.6440\cos30° = 34.64 in X and 40sin⁡30°=20.0040\sin30° = 20.00 in Y. The width direction is perpendicular — rotated 30°+90°=120°30° + 90° = 120° — so the width vector of 20 contributes 20cos⁡120°=−10.0020\cos120° = -10.00 in X and 20sin⁡120°=17.3220\sin120° = 17.32 in Y. Summing both vectors gives the opposite corner: (34.64+(−10.00), 20.00+17.32)=(24.64, 37.32)(34.64 + (-10.00),\ 20.00 + 17.32) = (24.64,\ 37.32), confirming D is correct. Choice A ignores the rotation entirely, treating the dimensions as simple axis-aligned offsets — a fundamental misunderstanding of the rotation parameter. Choice B rotates only the length vector and ignores the rotated width altogether, producing an incomplete result. Choice C takes the correct components but swaps X and Y, which is a careless arithmetic error that produces a plausible-looking but geometrically wrong point. As a strategy, whenever RECTANG involves both rotation and dimensions, always decompose both edges into their X and Y components using trigonometry, then sum them. Think of it like vector addition — the opposite corner is the tip of two combined arrows, not just one.

Question 10

A drafter uses RECTANG with a fillet radius of 1010 to create a rectangle whose overall dimensions are 100100 by 6060. Assume zero polyline width.

What is the total length of the resulting rounded boundary?

  1. 320320, because filleting does not change the original rectangular perimeter
  2. 240+20π240+20\pi, because the four corner arcs form one full circle (correct answer)
  3. 240+10π240+10\pi, because the four corner arcs form one semicircle
  4. 280+20π280+20\pi, because only two straight sides are shortened
Explanation: When the RECTANG command applies a fillet radius, it trims each corner of the rectangle, replacing it with a quarter-circle arc. Understanding what happens to both the straight segments and the corner arcs is the key to this problem. With a fillet radius of r=10r = 10, each corner arc spans 90°90°, or one-quarter of a full circle. Four corners × one-quarter circle each = exactly one complete circle. The circumference of that full circle is 2πr=2π(10)=20π2\pi r = 2\pi(10) = 20\pi. Now for the straight segments: each fillet trims r=10r = 10 from both ends of a corner, so each straight side loses 2×10=202 \times 10 = 20 from its original length. The two long sides become 100−20=80100 - 20 = 80 each, and the two short sides become 60−20=4060 - 20 = 40 each. Total straight length: 2(80)+2(40)=160+80=2402(80) + 2(40) = 160 + 80 = 240. The full perimeter is therefore 240+20π240 + 20\pi, confirming B. Choice A is wrong because filleting absolutely does change the perimeter — it shortens the straight sides and adds curved arcs. Choice C incorrectly treats the four quarter-circles as summing to a semicircle (πr\pi r) rather than a full circle (2πr2\pi r) — a classic arithmetic slip. Choice D is wrong because it assumes only two sides are shortened; in reality, all four sides lose material at both ends, so every straight segment is affected. As a study tip, always account for both changes a fillet makes: arcs are added and straight segments are shortened by rr at each end.