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AP Precalculus Quiz

AP Precalculus Quiz: Sine And Cosine Function Values

Practice Sine And Cosine Function Values in AP Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

The point P(−522,522)P(-\frac{5\sqrt{2}}{2}, \frac{5\sqrt{2}}{2})P(−252​​,252​​) is on a circle of radius 5 centered at the origin. Which of the following could be the angle θ\thetaθ in standard position corresponding to point PPP?

Select an answer to continue

What this quiz covers

This quiz focuses on Sine And Cosine Function Values, giving you a quick way to practice the rules, question types, and explanations that matter most for AP Precalculus.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

The point P(−522,522)P(-\frac{5\sqrt{2}}{2}, \frac{5\sqrt{2}}{2})P(−252​​,252​​) is on a circle of radius 5 centered at the origin. Which of the following could be the angle θ\thetaθ in standard position corresponding to point PPP?

  1. 3π4\frac{3\pi}{4}43π​ (correct answer)
  2. π4\frac{\pi}{4}4π​
  3. 5π4\frac{5\pi}{4}45π​
  4. 7π4\frac{7\pi}{4}47π​

Explanation: The coordinates are given by x=rcos⁡θx = r\cos\thetax=rcosθ and y=rsin⁡θy = r\sin\thetay=rsinθ. We have r=5r=5r=5, x=−522x = -\frac{5\sqrt{2}}{2}x=−252​​, and y=522y = \frac{5\sqrt{2}}{2}y=252​​. So, cos⁡θ=xr=−52/25=−22\cos\theta = \frac{x}{r} = \frac{-5\sqrt{2}/2}{5} = -\frac{\sqrt{2}}{2}cosθ=rx​=5−52​/2​=−22​​ and sin⁡θ=yr=52/25=22\sin\theta = \frac{y}{r} = \frac{5\sqrt{2}/2}{5} = \frac{\sqrt{2}}{2}sinθ=ry​=552​/2​=22​​. An angle with a negative cosine and a positive sine must be in Quadrant II. The angle in [0,2π)[0, 2\pi)[0,2π) that satisfies these conditions is θ=3π4\theta = \frac{3\pi}{4}θ=43π​.

Question 2

A point P(x,y)P(x,y)P(x,y) on a circle of radius 8 corresponds to an angle θ\thetaθ in standard position. If sin⁡θ=34\sin\theta = \frac{3}{4}sinθ=43​ and the terminal ray of θ\thetaθ is in Quadrant II, what are the coordinates of point PPP?

  1. (−27,6)(-2\sqrt{7}, 6)(−27​,6) (correct answer)
  2. (27,6)(2\sqrt{7}, 6)(27​,6)
  3. (6,−27)(6, -2\sqrt{7})(6,−27​)
  4. (−27,34)(-2\sqrt{7}, \frac{3}{4})(−27​,43​)

Explanation: The coordinates are (rcos⁡θ,rsin⁡θ)(r\cos\theta, r\sin\theta)(rcosθ,rsinθ). We are given r=8r=8r=8 and sin⁡θ=34\sin\theta = \frac{3}{4}sinθ=43​. The y-coordinate is y=rsin⁡θ=8(34)=6y = r\sin\theta = 8(\frac{3}{4}) = 6y=rsinθ=8(43​)=6. To find the x-coordinate, we use the identity sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1. This gives (34)2+cos⁡2θ=1(\frac{3}{4})^2 + \cos^2\theta = 1(43​)2+cos2θ=1, so cos⁡2θ=1−916=716\cos^2\theta = 1 - \frac{9}{16} = \frac{7}{16}cos2θ=1−169​=167​. Since θ\thetaθ is in Quadrant II, cos⁡θ\cos\thetacosθ is negative, so cos⁡θ=−74\cos\theta = -\frac{\sqrt{7}}{4}cosθ=−47​​. The x-coordinate is x=rcos⁡θ=8(−74)=−27x = r\cos\theta = 8(-\frac{\sqrt{7}}{4}) = -2\sqrt{7}x=rcosθ=8(−47​​)=−27​. The coordinates of P are (−27,6)(-2\sqrt{7}, 6)(−27​,6).

Question 3

The terminal ray of an angle θ=2π3\theta = \frac{2\pi}{3}θ=32π​ intersects the unit circle at a point PPP. What are the coordinates of point PPP?

  1. (−12,32)(-\frac{1}{2}, \frac{\sqrt{3}}{2})(−21​,23​​) (correct answer)
  2. (12,−32)(\frac{1}{2}, -\frac{\sqrt{3}}{2})(21​,−23​​)
  3. (−32,12)(-\frac{\sqrt{3}}{2}, \frac{1}{2})(−23​​,21​)
  4. (32,−12)(\frac{\sqrt{3}}{2}, -\frac{1}{2})(23​​,−21​)

Explanation: For a point on the unit circle, the coordinates are given by (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta)(cosθ,sinθ). The angle θ=2π3\theta = \frac{2\pi}{3}θ=32π​ is in Quadrant II, where the x-coordinate (cosine) is negative and the y-coordinate (sine) is positive. The reference angle is π3\frac{\pi}{3}3π​. Thus, cos⁡(2π3)=−cos⁡(π3)=−12\cos(\frac{2\pi}{3}) = -\cos(\frac{\pi}{3}) = -\frac{1}{2}cos(32π​)=−cos(3π​)=−21​ and sin⁡(2π3)=sin⁡(π3)=32\sin(\frac{2\pi}{3}) = \sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2}sin(32π​)=sin(3π​)=23​​. The coordinates of PPP are (−12,32)(-\frac{1}{2}, \frac{\sqrt{3}}{2})(−21​,23​​).

Question 4

The terminal ray of an angle θ=−7π4\theta = -\frac{7\pi}{4}θ=−47π​ intersects a circle of radius r=22r=2\sqrt{2}r=22​ at point PPP. What are the coordinates of PPP?

  1. (2,2)(2, 2)(2,2) (correct answer)
  2. (2,2)(\sqrt{2}, \sqrt{2})(2​,2​)
  3. (−2,2)(-2, 2)(−2,2)
  4. (2,−2)(2, -2)(2,−2)

Explanation: The coordinates are given by (rcos⁡θ,rsin⁡θ)(r\cos\theta, r\sin\theta)(rcosθ,rsinθ). The angle θ=−7π4\theta = -\frac{7\pi}{4}θ=−47π​ is coterminal with π4\frac{\pi}{4}4π​, which is in Quadrant I. Thus, \cos(-\frac{7\pi}{4}}) = \cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} and \sin(-\frac{7\pi}{4}}) = \sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}. The coordinates of PPP are (22⋅22,22⋅22)=(2⋅22,2⋅22)=(2,2)(2\sqrt{2} \cdot \frac{\sqrt{2}}{2}, 2\sqrt{2} \cdot \frac{\sqrt{2}}{2}) = (2 \cdot \frac{2}{2}, 2 \cdot \frac{2}{2}) = (2, 2)(22​⋅22​​,22​⋅22​​)=(2⋅22​,2⋅22​)=(2,2).

Question 5

The terminal ray of an angle θ\thetaθ intersects a circle of radius r=29r = \sqrt{29}r=29​ at the point (−2,5)(-2, 5)(−2,5). What are the values of cos⁡θ\cos\thetacosθ and sin⁡θ\sin\thetasinθ?

  1. cos⁡θ=−229\cos\theta = -\frac{2}{\sqrt{29}}cosθ=−29​2​ and sin⁡θ=529\sin\theta = \frac{5}{\sqrt{29}}sinθ=29​5​ (correct answer)
  2. cos⁡θ=529\cos\theta = \frac{5}{\sqrt{29}}cosθ=29​5​ and sin⁡θ=−229\sin\theta = -\frac{2}{\sqrt{29}}sinθ=−29​2​
  3. cos⁡θ=−2\cos\theta = -2cosθ=−2 and sin⁡θ=5\sin\theta = 5sinθ=5
  4. cos⁡θ=−25\cos\theta = -\frac{2}{5}cosθ=−52​ and sin⁡θ=1\sin\theta = 1sinθ=1

Explanation: The coordinates of a point (x,y)(x,y)(x,y) on a circle of radius rrr are related to the angle θ\thetaθ by x=rcos⁡θx = r\cos\thetax=rcosθ and y=rsin⁡θy = r\sin\thetay=rsinθ. We are given the point (−2,5)(-2, 5)(−2,5) and radius r=29r = \sqrt{29}r=29​. Therefore, cos⁡θ=xr=−229\cos\theta = \frac{x}{r} = -\frac{2}{\sqrt{29}}cosθ=rx​=−29​2​ and sin⁡θ=yr=529\sin\theta = \frac{y}{r} = \frac{5}{\sqrt{29}}sinθ=ry​=29​5​. We can verify that the given radius is correct: r=(−2)2+52=4+25=29r = \sqrt{(-2)^2 + 5^2} = \sqrt{4+25} = \sqrt{29}r=(−2)2+52​=4+25​=29​.

Question 6

The terminal ray of an angle θ=5π4\theta = \frac{5\pi}{4}θ=45π​ intersects a circle centered at the origin with radius r=6r=6r=6. What are the coordinates of the point of intersection?

  1. (−32,−32)(-3\sqrt{2}, -3\sqrt{2})(−32​,−32​) (correct answer)
  2. (32,−32)(3\sqrt{2}, -3\sqrt{2})(32​,−32​)
  3. (−33,−3)(-3\sqrt{3}, -3)(−33​,−3)
  4. (−22,−22)(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2})(−22​​,−22​​)

Explanation: The coordinates are (rcos⁡θ,rsin⁡θ)(r\cos\theta, r\sin\theta)(rcosθ,rsinθ). With r=6r=6r=6 and θ=5π4\theta=\frac{5\pi}{4}θ=45π​, the point is in Quadrant III. The reference angle is π4\frac{\pi}{4}4π​. Both cosine and sine are negative. cos⁡(5π4)=−22\cos(\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2}cos(45π​)=−22​​ and sin⁡(5π4)=−22\sin(\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2}sin(45π​)=−22​​. The coordinates are (6(−22),6(−22))=(−32,−32)(6(-\frac{\sqrt{2}}{2}), 6(-\frac{\sqrt{2}}{2})) = (-3\sqrt{2}, -3\sqrt{2})(6(−22​​),6(−22​​))=(−32​,−32​).

Question 7

A sound wave’s displacement is modeled by y=sin⁡(θ)y=\sin(\theta)y=sin(θ), where θ\thetaθ is the phase angle on the unit circle. At a particular time, the phase is θ=90∘=π/2\theta=90^\circ=\pi/2θ=90∘=π/2, measured counterclockwise from the positive xxx-axis. The unit circle has radius 1, so sine equals the yyy-coordinate. Use an exact value consistent with standard special angles. What is the sine of an angle measuring π/2\pi/2π/2 radians on the unit circle?

  1. 000
  2. 111 (correct answer)
  3. −1-1−1
  4. 1/21/21/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine values represent the y-coordinate on the unit circle where the angle intersects. In this problem, the angle θ = π/2 (90°) is given for a sound wave model, requiring students to find its sine value. Choice B (1) is correct because at π/2 radians, the point on the unit circle is at (0, 1), making sin(π/2) = 1. Choice A (0) is incorrect as this is the cosine value at π/2, showing confusion between x and y coordinates at this quadrantal angle. Students should memorize the four quadrantal angles (0°, 90°, 180°, 270°) and their exact trigonometric values. Visualizing the unit circle helps students see that π/2 points straight up, giving maximum sine value.

Question 8

An AC circuit has a phase angle θ=45∘=π/4\theta=45^\circ=\pi/4θ=45∘=π/4 between voltage and current, modeled on the unit circle. The cosine of θ\thetaθ represents the in-phase component magnitude for a 1-unit signal. Angles are measured in radians for computation, but the setup also states degrees. Use standard unit-circle exact values, not rounded approximations. Using the unit circle, what is the cosine value for π/4\pi/4π/4?

  1. 2/2\sqrt{2}/22​/2 (correct answer)
  2. 3/2\sqrt{3}/23​/2
  3. −2/2-\sqrt{2}/2−2​/2
  4. 0.7070.7070.707

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Cosine values represent the x-coordinate on the unit circle where the angle intersects. In this problem, the angle θ = π/4 (45°) is given in an AC circuit context, requiring students to find its cosine value. Choice A (√2/2) is correct because at π/4 radians, the point on the unit circle has coordinates (√2/2, √2/2), making cos(π/4) = √2/2. Choice D (0.707) is incorrect as it's a decimal approximation when the problem specifically asks for exact values, showing students must distinguish between exact and approximate forms. Students should memorize that at 45°, both sine and cosine equal √2/2. Using the isosceles right triangle with hypotenuse 1 helps derive this value exactly.

Question 9

A sound wave model uses y=cos⁡(θ)y=\cos(\theta)y=cos(θ), where θ\thetaθ is a phase angle on the unit circle. At a specific instant, θ=180∘=π\theta=180^\circ=\piθ=180∘=π, placing the point on the negative xxx-axis. The cosine equals the xxx-coordinate, so it can be read exactly from the unit circle. Use exact values and standard angle positions within 0≤θ≤2π0\le\theta\le2\pi0≤θ≤2π. Using the unit circle, what is the cosine value for π\piπ?

  1. 111
  2. 000
  3. −1-1−1 (correct answer)
  4. −0-0−0

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Cosine values represent the x-coordinate on the unit circle where the angle intersects. In this problem, the angle θ = π (180°) is given for a sound wave model, requiring students to find its cosine value at this quadrantal angle. Choice C (-1) is correct because at π radians, the point on the unit circle is at (-1, 0), making cos(π) = -1. Choice B (0) is incorrect as this is the sine value at π, showing confusion between x and y coordinates at quadrantal angles. Students should memorize that π radians points directly left on the unit circle, giving the most negative cosine value. Understanding quadrantal angles as multiples of π/2 helps students quickly identify their exact trigonometric values.

Question 10

An AC generator is analyzed with a phase angle θ\thetaθ on the unit circle, linking cosine to the real component. The measured value is cos⁡θ=−3/5\cos\theta=-3/5cosθ=−3/5, and the phase lies in Quadrant II, consistent with angles like 150∘=5π/6150^\circ=5\pi/6150∘=5π/6. Use sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1sin2θ+cos2θ=1 to compute sine exactly, then apply the quadrant sign rule. Degrees and radians are both referenced, but the identity is purely algebraic. Find sin⁡(θ)\sin(\theta)sin(θ) given cos⁡(θ)\cos(\theta)cos(θ) and θ\thetaθ is in quadrant II.

  1. 4/54/54/5 (correct answer)
  2. −4/5-4/5−4/5
  3. 3/53/53/5
  4. 5/45/45/4

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. The Pythagorean identity sin²θ + cos²θ = 1 connects sine and cosine values on the unit circle. In this problem, cos(θ) = -3/5 with θ in Quadrant II, requiring students to find sin(θ) using the identity. Choice A (4/5) is correct because sin²θ = 1 - cos²θ = 1 - (-3/5)² = 1 - 9/25 = 16/25, so sin(θ) = 4/5 (positive in Quadrant II). Choice B (-4/5) is incorrect as it has the wrong sign, forgetting that sine is positive in Quadrant II. Students must carefully apply both the Pythagorean identity and quadrant sign rules. The ASTC mnemonic reminds us that sine is positive in Quadrants I and II.

Question 11

A Ferris wheel position uses h=H+Rcos⁡(θ)h=H+R\cos(\theta)h=H+Rcos(θ), where θ\thetaθ is an angle on the unit circle. At a checkpoint, the rotation is θ=120∘=2π/3\theta=120^\circ=2\pi/3θ=120∘=2π/3. Cosine gives the horizontal coordinate, matching the signed ratio for the height offset. Using the unit circle, what is the cosine value for 120∘120^\circ120∘?

  1. 1/21/21/2
  2. −1/2-1/2−1/2 (correct answer)
  3. −3/2-\sqrt{3}/2−3​/2
  4. 3/2\sqrt{3}/23​/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as 120° or 2π/3 radians, requiring students to locate or calculate its trigonometric value. Choice B is correct because cos(120°) = cos(2π/3) = -1/2, which accurately reflects the cosine value for this angle in the second quadrant where cosine is negative. Choice C (-√3/2) is incorrect because it confuses the cosine value with the sine value at this angle, a common mistake when students mix up coordinates. Encourage students to memorize key unit circle values and practice identifying which coordinate corresponds to sine versus cosine. Highlight the importance of using reference angles correctly.

Question 12

A satellite’s position uses x=rcos⁡(θ)x=r\cos(\theta)x=rcos(θ), where θ\thetaθ is measured from the positive xxx-axis. Suppose θ=330∘=11π/6\theta=330^\circ=11\pi/6θ=330∘=11π/6 at a particular observation time. The cosine value gives the satellite’s horizontal fraction of its orbital radius. Calculate the exact value of cos⁡(θ)\cos(\theta)cos(θ) for θ=11π/6\theta=11\pi/6θ=11π/6.

  1. 3/2\sqrt{3}/23​/2 (correct answer)
  2. −3/2-\sqrt{3}/2−3​/2
  3. 1/21/21/2
  4. −1/2-1/2−1/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as 330° or 11π/6 radians, requiring students to locate or calculate its trigonometric value. Choice A is correct because cos(330°) = cos(11π/6) = √3/2, which accurately reflects the cosine value for this angle in the fourth quadrant where cosine is positive. Choice B (-√3/2) is incorrect due to a quadrant sign error, a common mistake when students overlook that cosine is positive in the fourth quadrant. Encourage students to memorize key unit circle values and practice identifying quadrant signs. Highlight the importance of recognizing that cosine is positive in quadrants I and IV.

Question 13

A Ferris wheel rider reaches angle θ=60∘=π/3\theta=60^\circ=\pi/3θ=60∘=π/3 from the center, modeling height with cosine. Using the unit circle, the radius is 1 unit and the adjacent coordinate gives cos⁡θ\cos\thetacosθ. All angles are measured counterclockwise from the positive xxx-axis, with 0≤θ≤2π0\le\theta\le2\pi0≤θ≤2π. Use exact trigonometric values rather than decimals. Calculate the exact value of cos⁡(θ)\cos(\theta)cos(θ) for θ=π/3\theta=\pi/3θ=π/3.

  1. 3/2\sqrt{3}/23​/2
  2. 1/21/21/2 (correct answer)
  3. −1/2-1/2−1/2
  4. 0.50.50.5

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Cosine values represent the x-coordinate on the unit circle where the angle intersects. In this problem, the angle θ = π/3 (60°) is given, requiring students to locate its cosine value on the unit circle. Choice B (1/2) is correct because at π/3 radians, the point on the unit circle has coordinates (1/2, √3/2), making cos(π/3) = 1/2. Choice A (√3/2) is incorrect as this is the sine value at π/3, a common mistake when students confuse x and y coordinates. Students should memorize the special angles (30°, 45°, 60°) and their exact trigonometric values. Drawing the unit circle and marking these key points helps reinforce which coordinate corresponds to sine versus cosine.

Question 14

A satellite is tracked from Earth’s center using a unit circle of radius 1 for direction. The line of sight makes θ=120∘=2π/3\theta=120^\circ=2\pi/3θ=120∘=2π/3 with the positive xxx-axis, placing it in Quadrant II. The xxx-coordinate equals cos⁡θ\cos\thetacosθ, which must be an exact value. Degrees and radians are provided to reinforce equivalence within 0≤θ≤2π0\le\theta\le2\pi0≤θ≤2π. Calculate the exact value of cos⁡(θ)\cos(\theta)cos(θ) for θ=2π/3\theta=2\pi/3θ=2π/3.

  1. 1/21/21/2
  2. −1/2-1/2−1/2 (correct answer)
  3. −3/2-\sqrt{3}/2−3​/2
  4. 3/2\sqrt{3}/23​/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Cosine values represent the x-coordinate on the unit circle where the angle intersects. In this problem, the angle θ = 2π/3 (120°) places the terminal side in Quadrant II, requiring students to determine both the value and sign of cosine. Choice B (-1/2) is correct because 2π/3 is the reference angle π/3 in Quadrant II, where cosine is negative, giving cos(2π/3) = -cos(π/3) = -1/2. Choice D (√3/2) is incorrect as it has the wrong sign, showing students forgot that cosine is negative in Quadrant II. Students must remember that in Quadrant II, sine is positive but cosine is negative. Using reference angles and the ASTC (All Students Take Calculus) mnemonic helps determine the correct signs.

Question 15

An AC generator current is modeled as i(t)=Isin⁡(θ)i(t)=I\sin(\theta)i(t)=Isin(θ), where θ\thetaθ is a unit-circle angle. Measurements indicate cos⁡θ=12/13\cos\theta=12/13cosθ=12/13, and the phase is in quadrant I. Using sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1sin2θ+cos2θ=1, determine the corresponding sine ratio. Find sin⁡(θ)\sin(\theta)sin(θ) given cos⁡(θ)\cos(\theta)cos(θ) and θ\thetaθ is in quadrant I.

  1. 5/135/135/13 (correct answer)
  2. −5/13-5/13−5/13
  3. 25/13\sqrt{25}/1325​/13
  4. 1/131/131/13

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. The Pythagorean identity sin²θ + cos²θ = 1 relates sine and cosine values on the unit circle. In this problem, cos(θ) = 12/13 and θ is in quadrant I, requiring students to calculate the corresponding sine value. Choice A is correct because sin²θ = 1 - cos²θ = 1 - (12/13)² = 1 - 144/169 = 25/169, so sin(θ) = 5/13 (positive in quadrant I). Choice B (-5/13) is incorrect due to a sign error, as sine is positive in the first quadrant. Encourage students to practice using the Pythagorean identity systematically. Highlight the importance of simplifying fractions and maintaining proper signs based on quadrant location.

Question 16

A pendulum’s height change can be written using cos⁡(θ)\cos(\theta)cos(θ) from a right-triangle projection. At an instant, the angle satisfies cos⁡θ=3/5\cos\theta=3/5cosθ=3/5, with θ\thetaθ between 0∘0^\circ0∘ and 90∘90^\circ90∘ (quadrant I). Use the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1sin2θ+cos2θ=1 to relate the ratios. Based on the scenario, what is the sine of θ\thetaθ if cos⁡θ=3/5\cos\theta=3/5cosθ=3/5?

  1. 4/54/54/5 (correct answer)
  2. 3/43/43/4
  3. −4/5-4/5−4/5
  4. 2/52/52/5

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. The Pythagorean identity sin²θ + cos²θ = 1 relates sine and cosine values on the unit circle. In this problem, cos(θ) = 3/5 and θ is in quadrant I, requiring students to calculate the corresponding sine value. Choice A is correct because sin²θ = 1 - cos²θ = 1 - (3/5)² = 1 - 9/25 = 16/25, so sin(θ) = 4/5 (positive in quadrant I). Choice C (-4/5) is incorrect due to a sign error, as sine is positive in the first quadrant. Encourage students to practice using the Pythagorean identity and to always consider quadrant signs. Highlight the importance of checking whether the calculated value makes sense given the quadrant.

Question 17

A satellite’s horizontal coordinate is x=rcos⁡(θ)x=r\cos(\theta)x=rcos(θ) with θ\thetaθ measured from the positive xxx-axis. At one observation, the central angle is θ=300∘=5π/3\theta=300^\circ=5\pi/3θ=300∘=5π/3. The cosine value provides the exact horizontal fraction of the orbital radius. Calculate the exact value of cos⁡(θ)\cos(\theta)cos(θ) for θ=300∘\theta=300^\circθ=300∘.

  1. 3/2\sqrt{3}/23​/2
  2. −3/2-\sqrt{3}/2−3​/2
  3. 1/21/21/2 (correct answer)
  4. −1/2-1/2−1/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as 300° or 5π/3 radians, requiring students to locate or calculate its trigonometric value. Choice C is correct because cos(300°) = cos(5π/3) = 1/2, which accurately reflects the cosine value for this angle in the fourth quadrant where cosine is positive. Choice D (-1/2) is incorrect due to a quadrant sign error, a common mistake when students overlook that cosine is positive in the fourth quadrant. Encourage students to memorize key unit circle values and practice identifying quadrant signs. Highlight the importance of using reference angles and recognizing that 300° has a reference angle of 60°.

Question 18

A Ferris wheel rider’s height uses h=H+Rsin⁡(θ)h=H+R\sin(\theta)h=H+Rsin(θ), where θ\thetaθ is measured from the positive xxx-axis. At a certain time, the wheel has rotated to θ=45∘=π/4\theta=45^\circ=\pi/4θ=45∘=π/4. The unit circle value of sine determines the vertical coordinate. Using the unit circle, what is the sine of θ\thetaθ?

  1. 1/21/21/2
  2. 2/2\sqrt{2}/22​/2 (correct answer)
  3. −2/2-\sqrt{2}/2−2​/2
  4. 0.7070.7070.707

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as 45° or π/4 radians, requiring students to locate or calculate its trigonometric value. Choice B is correct because sin(45°) = sin(π/4) = √2/2, which accurately reflects the sine value for this standard angle in the first quadrant. Choice D (0.707) is incorrect because while it's a decimal approximation of √2/2, the question asks for the exact value using the unit circle, making the radical form necessary. Encourage students to memorize key unit circle values and practice converting between degrees and radians. Highlight the importance of using exact values rather than decimal approximations when working with special angles.

Question 19

A pendulum swings so its string makes angle θ=60∘=π/3\theta=60^\circ=\pi/3θ=60∘=π/3 from the vertical at maximum displacement. Model the bob’s horizontal offset as x=Lsin⁡θx=L\sin\thetax=Lsinθ using a right-triangle projection. The triangle’s hypotenuse is the string length LLL, and the opposite side gives xxx. Based on the scenario, find the exact value of sin⁡(θ)\sin(\theta)sin(θ).

  1. 3/2\sqrt{3}/23​/2 (correct answer)
  2. 1/21/21/2
  3. −3/2-\sqrt{3}/2−3​/2
  4. 0.8660.8660.866

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as 60° or π/3 radians, requiring students to locate or calculate its trigonometric value. Choice A is correct because sin(60°) = sin(π/3) = √3/2, which accurately reflects the sine value for this standard angle in the first quadrant. Choice D (0.866) is incorrect because while it's a decimal approximation of √3/2, the question asks for the exact value, making the radical form necessary. Encourage students to memorize key unit circle values and practice converting between degrees and radians. Highlight the importance of distinguishing between exact values and decimal approximations in trigonometric problems.

Question 20

A sound wave is modeled by p(t)=Psin⁡(θ)p(t)=P\sin(\theta)p(t)=Psin(θ), where θ\thetaθ is a unit-circle angle in radians. During testing, the phase is set to θ=π/2\theta=\pi/2θ=π/2, which corresponds to 90∘90^\circ90∘. The sine value equals the vertical coordinate on the unit circle at that angle. What is the sine of an angle measuring π/2\pi/2π/2 radians on the unit circle?

  1. 000
  2. 111 (correct answer)
  3. −1-1−1
  4. 2/2\sqrt{2}/22​/2

Explanation: This question tests AP Precalculus skills: understanding sine and cosine function values in context. Sine and cosine values represent the coordinates on the unit circle where the angle intersects. In this problem, the angle θ is given as π/2 radians (90°), requiring students to locate or calculate its trigonometric value. Choice B is correct because sin(π/2) = sin(90°) = 1, which accurately reflects the sine value at the top of the unit circle where the point is (0, 1). Choice A (0) is incorrect because it represents the cosine value at π/2, not the sine value, a common mistake when students confuse x and y coordinates. Encourage students to memorize the four quadrantal angles and their trigonometric values. Highlight the importance of visualizing the unit circle to avoid coordinate confusion.