Conic Sections Practice Test

In an orbital ellipse, $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$ where $(h,k)$ is the center. Refer to the equation provided in the passage: which ordered pair is the center of $\frac{(x+3)^2}{16}+\frac{(y-5)^2}{25}=1$?​

In astronomy, Kepler described planetary orbits as ellipses. Consider the standard form $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$ with $a>b>0$, where $(h,k)$ is the center. Based on the conic section described, how does increasing $a$ affect the ellipse’s horizontal extent?