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Change in Linear and Exponential Functions Practice Test
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Q1
A car is worth $V_0=$24{,}000$. Linear depreciation: $V_L(t)=24{,}000-1{,}800t$, where $t$ is years and $$1{,}800$/year is lost. Exponential depreciation: $V_E(t)=24{,}000(0.90)^t$, where value drops 10% per year. Values are in dollars. Linear change subtracts the same amount yearly, while exponential change multiplies by the same factor yearly. In the context of this scenario, which model predicts a greater decrease after 3 years?
A car is worth $V_0=$24{,}000$. Linear depreciation: $V_L(t)=24{,}000-1{,}800t$, where $t$ is years and $$1{,}800$/year is lost. Exponential depreciation: $V_E(t)=24{,}000(0.90)^t$, where value drops 10% per year. Values are in dollars. Linear change subtracts the same amount yearly, while exponential change multiplies by the same factor yearly. In the context of this scenario, which model predicts a greater decrease after 3 years?