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AP Precalculus Quiz

AP Precalculus Quiz: Change In Arithmetic And Geometric Sequences

Practice Change In Arithmetic And Geometric Sequences in AP Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 13

0 of 13 answered

Bacteria doubles hourly in a geometric sequence with a1=200a_1=200a1​=200 and r=2r=2r=2: 200; 400; 800. Using the given terms, what is the nnnth term of the sequence?

Select an answer to continue

What this quiz covers

This quiz focuses on Change In Arithmetic And Geometric Sequences, giving you a quick way to practice the rules, question types, and explanations that matter most for AP Precalculus.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Bacteria doubles hourly in a geometric sequence with a1=200a_1=200a1​=200 and r=2r=2r=2: 200; 400; 800. Using the given terms, what is the nnnth term of the sequence?

  1. an=200na_n=200nan​=200n
  2. an=200⋅2n−1a_n=200\cdot 2^{n-1}an​=200⋅2n−1 (correct answer)
  3. an=200⋅2na_n=200\cdot 2^{n}an​=200⋅2n
  4. an=200+(n−1)2a_n=200+(n-1)2an​=200+(n−1)2

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 200 bacteria, doubling each hour (ratio of 2). Choice B is correct because it accurately represents the geometric sequence formula: aₙ = a₁ × r^(n-1) = 200 × 2^(n-1). Choice C (200 × 2ⁿ) is incorrect due to using n instead of (n-1) as the exponent, a common mistake when students forget that the first term uses r⁰. To help students: Remember that geometric sequences use r^(n-1) because the first term has no multiplication by r. Practice writing out the first few terms to verify the formula pattern.

Question 2

A salary follows an arithmetic sequence with a1=30,000a_1=30{,}000a1​=30,000 and d=1,000d=1{,}000d=1,000: 30,000; 31,000; 32,000. Based on the sequence, calculate the total change after 10 terms.

  1. 9,0009{,}0009,000 (correct answer)
  2. 10,00010{,}00010,000
  3. 8,0008{,}0008,000
  4. 11,00011{,}00011,000

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 30,000, changing by a difference of 1,000 each term. Choice A is correct because the total change after 10 terms means finding the difference between a₁₀ and a₁: a₁₀ = 30,000 + 9(1,000) = 39,000, so the change is 39,000 - 30,000 = 9,000. Choice B (10,000) is incorrect due to confusing the number of terms with the number of differences, a common mistake when students forget that reaching the 10th term requires only 9 steps. To help students: Remember that the change from term 1 to term n involves (n-1) differences. Draw out the first few terms to visualize the pattern.

Question 3

Bacteria doubles hourly in a geometric sequence with a1=50a_1=50a1​=50 and r=2r=2r=2: 50; 100; 200. Using the given terms, how does the sequence change from term 3 to term 6?

  1. Increases by 1,4001{,}4001,400 (correct answer)
  2. Increases by 200200200
  3. Decreases by 1,4001{,}4001,400
  4. Increases by 700700700

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50 bacteria, doubling each hour. Choice A is correct because it accurately calculates the change: a_3 = 200 and a_6 = 50 × 2^5 = 50 × 32 = 1,600, giving an increase of 1,600 - 200 = 1,400. Choice B is incorrect with only 200, likely confusing the value of a_3 with the change between terms. To help students: Practice finding specific terms before calculating differences. Emphasize the importance of reading carefully to identify which terms are being compared.

Question 4

A salary follows an arithmetic sequence with a1=50,000a_1=50{,}000a1​=50,000 and d=2,000d=2{,}000d=2,000: 50,000; 52,000; 54,000. Based on the sequence, what is the nnnth term ana_nan​?

  1. an=50,000+2,000na_n=50{,}000+2{,}000nan​=50,000+2,000n
  2. an=50,000(2,000)n−1a_n=50{,}000(2{,}000)^{n-1}an​=50,000(2,000)n−1
  3. an=50,000+2,000(n−1)a_n=50{,}000+2{,}000(n-1)an​=50,000+2,000(n−1) (correct answer)
  4. an=50,000+1,000(n−1)a_n=50{,}000+1{,}000(n-1)an​=50,000+1,000(n−1)

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, changing by a difference of 2,000 each term. Choice C is correct because it accurately applies the arithmetic sequence formula a_n = a_1 + d(n-1), giving a_n = 50,000 + 2,000(n-1). Choice A is incorrect due to using n instead of (n-1), a common mistake when students forget that the first term already includes a_1. To help students: Practice identifying the correct formula structure for arithmetic sequences. Emphasize that (n-1) represents the number of times we add the common difference, starting from the first term.

Question 5

A salary follows an arithmetic sequence with a1=50,000a_1=50{,}000a1​=50,000 and d=2,000d=2{,}000d=2,000: 50,000; 52,000; 54,000. Based on the sequence, determine the sum of the first 5 terms.

  1. 260,000260{,}000260,000
  2. 270,000270{,}000270,000 (correct answer)
  3. 280,000280{,}000280,000
  4. 156,000156{,}000156,000

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, changing by a difference of 2,000 each term. Choice B is correct because it accurately applies the arithmetic series formula: S₅ = 5/2 × (2a₁ + 4d) = 5/2 × (100,000 + 8,000) = 5/2 × 108,000 = 270,000. Choice A (260,000) is incorrect due to miscalculating the sum formula, a common mistake when students forget to properly apply the arithmetic series formula. To help students: Practice using the sum formula S_n = n/2 × (2a₁ + (n-1)d) systematically. Emphasize verifying calculations by adding the first few terms manually as a check.

Question 6

Bacteria doubles hourly in a geometric sequence with a1=200a_1=200a1​=200 and r=2r=2r=2: 200; 400; 800. Using the given terms, what is a7a_7a7​?

  1. 12,80012{,}80012,800 (correct answer)
  2. 6,4006{,}4006,400
  3. 1,4001{,}4001,400
  4. 25,60025{,}60025,600

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 200 bacteria, doubling (ratio of 2) each hour. Choice A is correct because it accurately applies the geometric sequence formula a_n = a_1 × r^(n-1), giving a_7 = 200 × 2^6 = 200 × 64 = 12,800. Choice B is incorrect due to calculating 2^5 instead of 2^6, a common mistake when students forget that the exponent is (n-1). To help students: Practice counting the number of multiplications needed to reach the nth term. Emphasize that for the 7th term, we multiply by r exactly 6 times.

Question 7

A city’s population declines geometrically with a1=50,000a_1=50{,}000a1​=50,000 and r=0.95r=0.95r=0.95: 50,000; 47,500; 45,125. Based on the sequence, what is the nnnth term ana_nan​?

  1. an=50,000+0.95(n−1)a_n=50{,}000+0.95(n-1)an​=50,000+0.95(n−1)
  2. an=50,000(0.95)n−1a_n=50{,}000(0.95)^{n-1}an​=50,000(0.95)n−1 (correct answer)
  3. an=50,000(1.05)n−1a_n=50{,}000(1.05)^{n-1}an​=50,000(1.05)n−1
  4. an=50,000−0.95(n−1)a_n=50{,}000-0.95(n-1)an​=50,000−0.95(n−1)

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, declining by a ratio of 0.95 each term. Choice B is correct because it accurately applies the geometric sequence formula a_n = a_1 × r^(n-1), giving a_n = 50,000(0.95)^(n-1). Choice A is incorrect due to treating this as an arithmetic sequence with a difference of 0.95, a common mistake when students see a decimal and assume subtraction. To help students: Practice identifying sequence types from the given terms. Emphasize that ratios less than 1 still indicate geometric sequences, not arithmetic ones.

Question 8

A salary follows an arithmetic sequence with a1=30,000a_1=30{,}000a1​=30,000 and d=1,000d=1{,}000d=1,000: 30,000; 31,000; 32,000. Based on the sequence, how does the sequence change from term 2 to term 8?

  1. Increases by 5,0005{,}0005,000
  2. Increases by 6,0006{,}0006,000 (correct answer)
  3. Increases by 7,0007{,}0007,000
  4. Decreases by 6,0006{,}0006,000

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 30,000, increasing by 1,000 each term. Choice B is correct because in an arithmetic sequence, the change from term 2 to term 8 is 6 times the common difference: 6 × 1,000 = 6,000. Choice C is incorrect with 7,000, likely from counting 7 steps instead of 6, a common mistake when students include both endpoints. To help students: Practice counting the number of steps between terms carefully. Emphasize that from term 2 to term 8, there are exactly 6 steps (8 - 2 = 6).

Question 9

A city’s population declines geometrically with a1=100,000a_1=100{,}000a1​=100,000 and r=0.95r=0.95r=0.95: 100,000; 95,000; 90,250. Using the given terms, what is a5a_5a5​?

  1. 81,450.6381{,}450.6381,450.63 (correct answer)
  2. 85,737.5085{,}737.5085,737.50
  3. 77,378.0977{,}378.0977,378.09
  4. 814,506.25814{,}506.25814,506.25

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 100,000, changing by a ratio of 0.95 each term (representing a 5% decline). Choice A is correct because it accurately applies the geometric sequence formula: a₅ = a₁ × r⁴ = 100,000 × (0.95)⁴ = 100,000 × 0.81450625 = 81,450.63. Choice C (77,378.09) is incorrect due to using r⁵ instead of r⁴, a common mistake when students confuse the term number with the exponent. To help students: Remember that for the nth term, use r^(n-1) as the exponent. Practice calculating several terms to build confidence with the pattern.

Question 10

A savings account grows geometrically with a1=500a_1=500a1​=500 and r=1.10r=1.10r=1.10: 500; 550; 605. Based on the sequence, what is a6a_6a6​?

  1. 805.26805.26805.26 (correct answer)
  2. 732.05732.05732.05
  3. 885.78885.78885.78
  4. 80.5380.5380.53

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 500, growing by a ratio of 1.10 each term (10% growth). Choice A is correct because it accurately applies the geometric sequence formula: a₆ = a₁ × r⁵ = 500 × (1.10)⁵ = 500 × 1.61051 = 805.26. Choice B (732.05) is incorrect due to using the wrong power of r, a common mistake when students miscalculate compound growth. To help students: Remember that for the nth term, use r^(n-1). Practice with a calculator to ensure accuracy with decimal powers.

Question 11

A city’s population declines geometrically with a1=80,000a_1=80{,}000a1​=80,000 and r=0.90r=0.90r=0.90: 80,000; 72,000; 64,800. Using the given terms, determine the sum of the first 4 terms.

  1. 275,120275{,}120275,120 (correct answer)
  2. 295,200295{,}200295,200
  3. 268,920268{,}920268,920
  4. 27,51227{,}51227,512

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 80,000, declining by a ratio of 0.90 each term. Choice A is correct because it accurately calculates the sum: a₁ = 80,000, a₂ = 72,000, a₃ = 64,800, a₄ = 58,320, giving a sum of 275,120. Choice C (268,920) is incorrect due to calculation errors in finding individual terms, a common mistake when students rush through geometric calculations. To help students: Calculate each term carefully before summing. For geometric series, you can also use the formula S_n = a₁(1-rⁿ)/(1-r) as a check.

Question 12

A savings account grows geometrically with a1=1,000a_1=1{,}000a1​=1,000 and r=1.05r=1.05r=1.05: 1,000; 1,050; 1,102.50. Using the given terms, what is a5a_5a5​?

  1. 1,215.511{,}215.511,215.51 (correct answer)
  2. 1,250.001{,}250.001,250.00
  3. 12,155.0612{,}155.0612,155.06
  4. 1,205.001{,}205.001,205.00

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 1,000, changing by a ratio of 1.05 each term. Choice A is correct because it accurately applies the geometric sequence formula a_n = a_1 × r^(n-1), giving a_5 = 1,000 × 1.05^4 = 1,000 × 1.21550625 = 1,215.51. Choice C is incorrect due to multiplying by 10, likely from misreading the decimal point, a common mistake when students rush calculations. To help students: Practice careful calculation with geometric sequences, especially with decimal ratios. Emphasize checking that answers are reasonable given the growth rate.

Question 13

A city’s population declines geometrically with a1=100,000a_1=100{,}000a1​=100,000 and r=0.98r=0.98r=0.98: 100,000; 98,000; 96,040. Based on the sequence, how does the sequence change from term 1 to term 4?

  1. Decreases by 5,880.805{,}880.805,880.80 (correct answer)
  2. Decreases by 6,000.006{,}000.006,000.00
  3. Increases by 5,880.805{,}880.805,880.80
  4. Decreases by 5,880.085{,}880.085,880.08

Explanation: This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 100,000, declining by a ratio of 0.98 each term. Choice A is correct because it accurately calculates the change from term 1 to term 4: a_4 = 100,000 × 0.98^3 = 94,119.20, giving a decrease of 100,000 - 94,119.20 = 5,880.80. Choice B is incorrect due to assuming a linear decrease of 2,000 per term, a common mistake when students confuse geometric and arithmetic sequences. To help students: Practice distinguishing between multiplicative and additive changes. Emphasize that geometric sequences with r < 1 show decreasing changes between consecutive terms.