Electromagnetic Induction Practice Test

$80\ \text{V}$ from $40(0.040)/0.020$, misreading $4.0\ \text{mWb}$ as $40\ \text{mWb}$.

$8.0\ \text{A}$ computed as $I=N\Delta\Phi/\Delta t$, giving current units instead of volts.

$0.20\ \text{V}$ from $\varepsilon=\Delta\Phi/\Delta t$, incorrectly omitting the $N=40$ turns factor.

$8.0\ \text{V}$ from $\varepsilon=N\Delta\Phi/\Delta t=40(0.004)/0.020$ using Faraday’s law magnitude.