Electric Potential Practice Test

An electron ($q=-e=-1.60\times10^{-19}\ \text{C}$) moves from point $X$ to point $Y$ where the electric potential increases by $\Delta V=+250\ \text{V}$. Use $\Delta U=q\Delta V$ (and $k=8.99\times10^{9}$). In the situation described, determine the change in electric potential energy $\Delta U$.

A uniform electric field $E=8.0\times10^{2}\ \text{V/m}$ points upward. Point $B$ is $0.15\ \text{m}$ above point $A$. Use $\Delta V=-Ed$ along the field direction (and $k=8.99\times10^{9}$, $e=1.60\times10^{-19}\ \text{C}$). In the situation described, calculate the potential difference $V_B-V_A$.