Conservation of Electric Charge Practice Test

$\Phi_E=\dfrac{kQ}{r^2}$, because flux equals field magnitude

$\Phi_E$ increases with shell thickness because more material encloses charge

$\Phi_E=0$, because insulators block electric fields

$\Phi_E=\dfrac{Q}{\varepsilon_0}=1.13\times10^5,\text{N·m}^2/\text{C}$