Rotational Equilibrium and Newton's First Law Practice Test

A uniform meterstick is balanced horizontally on a pivot located at the $40,\text{cm}$ mark. A $1.0,\text{N}$ weight hangs from the $10,\text{cm}$ mark, and an unknown weight hangs from the $90,\text{cm}$ mark. The stick remains at rest, and the angular acceleration is $\alpha=0$. Which statement must be true about the net torque on the stick about the pivot?

A uniform rod lies horizontally on two supports, one near each end. A $50,\text{N}$ weight is hung somewhere along the rod, and the rod remains at rest without tipping. The angular acceleration is $\alpha=0$. Without calculating forces, what must be true about the net torque on the rod about its center of mass?