Volumes with Cross Sections: Triangles/Semicircles Practice Test

$V=\displaystyle\int_{0}^{9}\frac{\pi}{8},(9-y^2)^2,dy$

$V=\displaystyle\int_{-3}^{3}\frac{\pi}{8},(9-x^2)^2,dx$

$V=\displaystyle\int_{-3}^{3}\frac{\pi}{8},(9-x^2),dx$

$V=\displaystyle\int_{-3}^{3}\pi,(9-x^2)^2,dx$

$V=\displaystyle\int_{-3}^{3}\frac{\pi}{4},(9-x^2)^2,dx$