The Product Rule Practice Test

$g'(x)=\arctan(x)(3x^2)$

$g'(x)=\frac{1}{1+x^2}(x^3-2)$

$g'(x)=\frac{x^3-2}{1+x^2}+3x^2\arctan(x)$

$g'(x)=\frac{1}{1+x^2}(3x^2)$

$g'(x)=\arctan(x)\cdot\frac{x^3-2}{1+x^2}$