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AP Calculus BC Quiz

AP Calculus BC Quiz: Selecting Procedures For Calculating Derivatives

Practice Selecting Procedures For Calculating Derivatives in AP Calculus BC with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

For the cost model C(x)=(3x2−5x+1)7C(x)=(3x^2-5x+1)^7C(x)=(3x2−5x+1)7, which differentiation technique is most appropriate to find C′(x)C'(x)C′(x)?

Select an answer to continue

What this quiz covers

This quiz focuses on Selecting Procedures For Calculating Derivatives, giving you a quick way to practice the rules, question types, and explanations that matter most for AP Calculus BC.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

For the cost model C(x)=(3x2−5x+1)7C(x)=(3x^2-5x+1)^7C(x)=(3x2−5x+1)7, which differentiation technique is most appropriate to find C′(x)C'(x)C′(x)?

  1. Differentiate using implicit differentiation
  2. Differentiate using the chain rule with the power rule (correct answer)
  3. Differentiate using logarithmic differentiation
  4. Differentiate by expanding the polynomial completely first
  5. Differentiate using the quotient rule

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For C(x) = (3x² - 5x + 1)^7, the chain rule combined with the power rule is most efficient because the function is a composition where the outer function is a power and the inner is a polynomial. This method allows us to differentiate the outer function while multiplying by the derivative of the inner function, avoiding complex expansions. It directly yields C'(x) = 7(3x² - 5x + 1)^6 (6x - 5), which is straightforward and minimizes errors. While expanding the polynomial completely first might seem viable, it would result in a high-degree polynomial that's tedious to differentiate term by term. When choosing a technique, assess the function's structure to prioritize rules like the chain rule for compositions over methods that increase complexity.

Question 2

For f(x)=(x2+1)3/2(x−4)2f(x)=(x^2+1)^{3/2}(x-4)^2f(x)=(x2+1)3/2(x−4)2, which differentiation technique is most appropriate to compute f′(x)f'(x)f′(x)?

  1. Differentiate using the product rule with the chain rule (correct answer)
  2. Differentiate using the quotient rule
  3. Differentiate using implicit differentiation
  4. Differentiate by expanding completely before differentiating
  5. Differentiate using related rates

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For f(x) = (x² + 1)^{3/2} (x - 4)^2, using the product rule with the chain rule is most appropriate because it's a product of two terms, each requiring the chain rule for their powers. This involves differentiating each factor: the first uses chain on the 3/2 power, and the second on the square, then applying the product rule. It efficiently combines these to find f'(x) without full expansion. Differentiating by expanding completely before would create a messy polynomial with high degrees, increasing error risk. When functions are products of composites, integrate the product rule with chain applications for a balanced and effective approach.

Question 3

For the model y2+xy=cos⁡xy^2+xy=\cos xy2+xy=cosx, which differentiation technique is most appropriate to find dydx\dfrac{dy}{dx}dxdy​?

  1. Differentiate using the product rule only
  2. Differentiate using implicit differentiation (correct answer)
  3. Differentiate using the quotient rule
  4. Differentiate by solving explicitly for yyy first
  5. Differentiate using logarithmic differentiation

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For y² + x y = cos x, implicit differentiation is most appropriate because the equation isn't solved explicitly for y, requiring differentiation of both sides with respect to x while treating y as a function of x. This method involves applying the chain rule to terms like y² and the product rule to x y, leading to 2y y' + (y + x y') = -sin x. It allows solving for y' without isolating y, which might be difficult or impossible. Differentiating by solving explicitly for y first could be impractical if the equation doesn't yield a simple explicit form. Use implicit differentiation for equations where variables are intertwined, providing a general strategy for related rates and beyond.

Question 4

A growth curve is G(x)=(x2+1)sin⁡xG(x)=(x^2+1)\sin xG(x)=(x2+1)sinx. Which differentiation technique is most appropriate to compute G′(x)G'(x)G′(x)?

  1. Differentiate using the product rule (correct answer)
  2. Differentiate using the quotient rule
  3. Differentiate using implicit differentiation
  4. Differentiate using related rates
  5. Differentiate using separation of variables

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For G(x) = (x² + 1) sin x, the product rule is most appropriate because it's a product of a polynomial and a trigonometric function, enabling G'(x) = 2x sin x + (x² + 1) cos x. This direct application handles each part's derivative separately and combines them efficiently. It's simpler than alternatives, avoiding unnecessary manipulations. Using the quotient rule would be incorrect since the function isn't a quotient. Identify products early and apply the product rule to maintain simplicity, especially when combining algebraic and transcendental functions.

Question 5

A population model is P(t)=e(5t−1)2P(t)=e^{(5t-1)^2}P(t)=e(5t−1)2. Which differentiation technique is most appropriate to compute P′(t)P'(t)P′(t)?

  1. Differentiate using the product rule
  2. Differentiate using the chain rule (correct answer)
  3. Differentiate using the quotient rule
  4. Differentiate using logarithmic differentiation
  5. Differentiate using related rates

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For P(t) = e^{(5t - 1)^2}, the chain rule is most appropriate because it's an exponential function with a composed exponent, requiring differentiation of the outer exponential and then the inner quadratic. This method efficiently chains the derivatives: the derivative of e^u is e^u times u', where u = (5t - 1)^2, and u' requires another chain application. It produces P'(t) = e^{(5t - 1)^2} * 2(5t - 1) * 5, which is precise without extra steps. Logarithmic differentiation would add unnecessary complexity by taking the natural log first, which isn't needed for exponentials. For nested functions, apply the chain rule iteratively to handle each layer systematically.

Question 6

A revenue function is R(x)=xln⁡(4x+1)R(x)=x\ln(4x+1)R(x)=xln(4x+1). Which differentiation technique is most appropriate to find R′(x)R'(x)R′(x)?

  1. Differentiate using the chain rule only
  2. Differentiate using the product rule with a chain rule on ln⁡(4x+1)\ln(4x+1)ln(4x+1) (correct answer)
  3. Differentiate using implicit differentiation with y=R(x)y=R(x)y=R(x)
  4. Differentiate using the quotient rule by rewriting as ln⁡(4x+1)1/x\frac{\ln(4x+1)}{1/x}1/xln(4x+1)​
  5. Differentiate by expanding ln⁡(4x+1)\ln(4x+1)ln(4x+1) into a power series first

Explanation: This problem requires selecting the appropriate technique for differentiating a product of functions. The function R(x)=xln(4x+1)R(x)=xln(4x+1)R(x)=xln(4x+1) is a product of xxx and ln(4x+1)ln(4x+1)ln(4x+1), so the product rule is necessary. Additionally, ln(4x+1)ln(4x+1)ln(4x+1) is a composite function requiring the chain rule. Using the product rule: R'(x) = 1 cdot ln(4x+1) + x cdot rac{1}{4x+1} cdot 4 = ln(4x+1) + rac{4x}{4x+1}. Option A's suggestion to use only the chain rule ignores the product structure entirely. When you have a product where at least one factor is composite, combine the product rule with the chain rule as needed.

Question 7

Let v(x)=ln⁡(x2+1)⋅arctan⁡xv(x)=\ln(x^2+1)\cdot\arctan xv(x)=ln(x2+1)⋅arctanx. Which differentiation technique is most appropriate to determine v′(x)v'(x)v′(x)?​

  1. Use the product rule (correct answer)
  2. Use the chain rule only
  3. Use the quotient rule
  4. Use logarithmic differentiation
  5. Expand arctan⁡x\arctan xarctanx as a series, then differentiate

Explanation: This problem involves selecting the technique for a product of two different transcendental functions. The function v(x)=ln⁡(x2+1)⋅arctan⁡xv(x)=\ln(x^2+1)\cdot\arctan xv(x)=ln(x2+1)⋅arctanx is a product where each factor is a different type of function: a logarithm of a polynomial and an inverse trigonometric function. The product rule is necessary, giving ln⁡(x2+1)⋅ddx[arctan⁡x]+arctan⁡x⋅ddx[ln⁡(x2+1)]\ln(x^2+1)\cdot\frac{d}{dx}[\arctan x] + \arctan x\cdot\frac{d}{dx}[\ln(x^2+1)]ln(x2+1)⋅dxd​[arctanx]+arctanx⋅dxd​[ln(x2+1)]. Note that differentiating ln⁡(x2+1)\ln(x^2+1)ln(x2+1) requires the chain rule. Using the chain rule only (option B) would be incorrect because this is a product of two separate functions, not a composition. For products of transcendental functions, apply the product rule and use the chain rule within each factor as needed.

Question 8

For m(x)=ln⁡ ⁣(1+x2)m(x)=\ln\!\left(\sqrt{1+x^2}\right)m(x)=ln(1+x2​), which differentiation technique is most appropriate to compute m′(x)m'(x)m′(x)?

  1. Differentiate using the quotient rule after rewriting as ln⁡(1+x2)ln⁡(1+x2)\dfrac{\ln(1+x^2)}{\ln(\sqrt{1+x^2})}ln(1+x2​)ln(1+x2)​.
  2. Differentiate using log properties to rewrite as 12ln⁡(1+x2)\tfrac12\ln(1+x^2)21​ln(1+x2), then apply the chain rule. (correct answer)
  3. Differentiate using implicit differentiation by exponentiating to remove the logarithm.
  4. Differentiate by expanding 1+x2\sqrt{1+x^2}1+x2​ into a binomial series, then differentiating.
  5. Differentiate using the product rule after rewriting as ln⁡(1+x2)⋅1\ln(\sqrt{1+x^2})\cdot 1ln(1+x2​)⋅1.

Explanation: Selecting the appropriate differentiation technique is vital for simplifying logarithmic expressions involving roots in calculus. Using log properties to rewrite as (1/2) ln(1 + x²) allows for easy differentiation with the chain rule, yielding (1/2) * (2x) / (1 + x²) = x / (1 + x²). This simplification reduces the function to a scalar multiple of a basic log, making the derivative immediate. It avoids dealing with the square root directly in the differentiation process. A tempting distractor is using the product rule after rewriting as ln(√(1 + x²)) * 1, but this doesn't simplify and still requires a chain rule on the log without the benefit of property reduction. Always apply logarithm properties to simplify arguments, especially with powers or roots, before selecting differentiation techniques.

Question 9

For h(x)=ex3−5x (x2+1)h(x)=e^{x^3-5x}\,(x^2+1)h(x)=ex3−5x(x2+1), which differentiation technique is most appropriate to find h′(x)h'(x)h′(x)?

  1. Differentiate using the product rule with a chain rule on ex3−5xe^{x^3-5x}ex3−5x (correct answer)
  2. Differentiate using only the power rule after expanding ex3−5xe^{x^3-5x}ex3−5x
  3. Differentiate using the quotient rule by rewriting as ex3−5x1/(x2+1)\frac{e^{x^3-5x}}{1/(x^2+1)}1/(x2+1)ex3−5x​
  4. Differentiate using implicit differentiation with y=h(x)y=h(x)y=h(x)
  5. Differentiate using logarithmic differentiation as the primary method

Explanation: This problem asks for the technique to differentiate a product involving an exponential function. The function h(x)=ex3−5x(x2+1)h(x)=e^{x^3-5x}(x^2+1)h(x)=ex3−5x(x2+1) is a product of ex3−5xe^{x^3-5x}ex3−5x and (x2+1)(x^2+1)(x2+1), requiring the product rule. Additionally, ex3−5xe^{x^3-5x}ex3−5x is composite, needing the chain rule. Using both: h′(x)=ex3−5x(3x2−5)(x2+1)+ex3−5x(2x)=ex3−5x[(3x2−5)(x2+1)+2x]h'(x) = e^{x^3-5x}(3x^2-5)(x^2+1) + e^{x^3-5x}(2x) = e^{x^3-5x}[(3x^2-5)(x^2+1) + 2x]h′(x)=ex3−5x(3x2−5)(x2+1)+ex3−5x(2x)=ex3−5x[(3x2−5)(x2+1)+2x]. Option B's suggestion to expand ex3−5xe^{x^3-5x}ex3−5x is impossible since exponential functions don't expand into polynomials. When differentiating products involving composite exponential functions, combine the product rule with the chain rule.

Question 10

A position function is s(t)=sin⁡(t2+4t)s(t)=\sin(t^2+4t)s(t)=sin(t2+4t). Which differentiation technique is most appropriate to find s′(t)s'(t)s′(t)?

  1. Differentiate using the product rule on sin⁡(t2)sin⁡(4t)\sin(t^2)\sin(4t)sin(t2)sin(4t)
  2. Differentiate using the chain rule with outer sine and inner quadratic (correct answer)
  3. Differentiate using implicit differentiation with y=s(t)y=s(t)y=s(t)
  4. Differentiate using the quotient rule by rewriting as sin⁡(t2+4t)1\frac{\sin(t^2+4t)}{1}1sin(t2+4t)​
  5. Differentiate by converting sin⁡(t2+4t)\sin(t^2+4t)sin(t2+4t) to an exponential form and then using logarithmic differentiation

Explanation: This problem requires selecting the technique for a composite trigonometric function. The function s(t)=sin(t2+4t)s(t)=sin(t^2+4t)s(t)=sin(t2+4t) has sine as the outer function and t2+4tt^2+4tt2+4t as the inner function, making it a perfect candidate for the chain rule. Using the chain rule: s′(t)=cos(t2+4t)cdot(2t+4)=(2t+4)cos(t2+4t)s'(t) = cos(t^2+4t) cdot (2t+4) = (2t+4)cos(t^2+4t)s′(t)=cos(t2+4t)cdot(2t+4)=(2t+4)cos(t2+4t). Option A incorrectly suggests treating this as a product of sin(t2)sin(t^2)sin(t2) and sin(4t)sin(4t)sin(4t), which is not what the original function represents. When you have a trigonometric function of a polynomial expression, the chain rule is the standard and most efficient approach.

Question 11

For p(x)=tan⁡(2x)x2p(x)=\dfrac{\tan(2x)}{x^2}p(x)=x2tan(2x)​, which differentiation technique is most appropriate to find p′(x)p'(x)p′(x) efficiently?

  1. Differentiate using the quotient rule with a chain rule on tan⁡(2x)\tan(2x)tan(2x) (correct answer)
  2. Differentiate using the power rule after rewriting as tan⁡(2x)x2\tan(2x)x^2tan(2x)x2
  3. Differentiate using implicit differentiation with y=p(x)y=p(x)y=p(x)
  4. Differentiate using only the chain rule
  5. Differentiate by converting tan⁡(2x)\tan(2x)tan(2x) to sin⁡(2x)/cos⁡(2x)\sin(2x)/\cos(2x)sin(2x)/cos(2x) and then using only the product rule

Explanation: This problem asks for the technique to differentiate a quotient involving a composite trigonometric function. The function p(x)= rac{ an(2x)}{x^2} is a quotient, so the quotient rule is needed. Additionally, an(2x) an(2x)an(2x) requires the chain rule. Using both: p'(x) = rac{x^2 cdot 2sec^2(2x) - an(2x) cdot 2x}{x^4} = rac{2xsec^2(2x) - 2 an(2x)}{x^3}. Option D's suggestion to use only the chain rule ignores the quotient structure entirely. When differentiating quotients where one part is composite, combine the quotient rule with the chain rule as needed for each component.

Question 12

A population model is P(t)=(3t2−1)5P(t)=(3t^2-1)^5P(t)=(3t2−1)5. Which differentiation technique is most appropriate to find P′(t)P'(t)P′(t)?

  1. Differentiate by expanding (3t2−1)5(3t^2-1)^5(3t2−1)5 and then using the power rule term-by-term
  2. Differentiate using the product rule on (3t2−1)(3t2−1)4(3t^2-1)(3t^2-1)^4(3t2−1)(3t2−1)4
  3. Differentiate using implicit differentiation with y=P(t)y=P(t)y=P(t)
  4. Differentiate using the chain rule on an outer power function and inner polynomial (correct answer)
  5. Differentiate using logarithmic differentiation by taking rac{d}{dt}ig(\ln P(t)\big)

Explanation: This problem requires selecting the most efficient technique to differentiate a composite function. The function P(t)=(3t2−1)5P(t)=(3t^2-1)^5P(t)=(3t2−1)5 has an outer power function (raising to the 5th power) and an inner polynomial function (3t2−1)(3t^2-1)(3t2−1), making the chain rule the ideal choice. Using the chain rule, we get P′(t)=5(3t2−1)4cdot6t=30t(3t2−1)4P'(t) = 5(3t^2-1)^4 cdot 6t = 30t(3t^2-1)^4P′(t)=5(3t2−1)4cdot6t=30t(3t2−1)4. While expanding (3t2−1)5(3t^2-1)^5(3t2−1)5 (option A) would eventually work, it would require expanding a fifth-degree binomial and then differentiating many terms, which is unnecessarily tedious. When you see a function raised to a power, especially a high power, the chain rule is almost always the most efficient approach.

Question 13

A cost model is C(x)=ln⁡ ⁣(x2+1x)C(x)=\ln\!\left(\dfrac{x^2+1}{x}\right)C(x)=ln(xx2+1​). Which differentiation technique is most appropriate to find C′(x)C'(x)C′(x)?

  1. Differentiate using the chain rule with a quotient rule inside the logarithm
  2. Differentiate using the product rule after rewriting as ln⁡(x2+1)ln⁡(x−1)\ln(x^2+1)\ln(x^{-1})ln(x2+1)ln(x−1)
  3. Differentiate using implicit differentiation with y=C(x)y=C(x)y=C(x)
  4. Differentiate using logarithm properties to rewrite, then apply basic derivative rules (correct answer)
  5. Differentiate by expanding ln⁡(x2+1x)\ln\left(\frac{x^2+1}{x}\right)ln(xx2+1​) into a power series first

Explanation: This problem requires selecting the most efficient technique for a logarithm of a quotient. The function C(x)=lnleft( rac{x^2+1}{x} ight) can be simplified using logarithm properties: lnleft( rac{x^2+1}{x} ight) = ln(x^2+1) - ln(x). After this simplification, basic derivative rules give: C'(x) = rac{2x}{x^2+1} - rac{1}{x} = rac{2x^2 - (x^2+1)}{x(x^2+1)} = rac{x^2-1}{x(x^2+1)}. Option A would work but requires unnecessary complexity with nested rules. When differentiating logarithms of quotients or products, first use logarithm properties to simplify, then apply basic derivative rules for the most efficient solution.

Question 14

For f(x)=5x3−2x+7f(x)=\sqrt{5x^3-2x+7}f(x)=5x3−2x+7​, which differentiation technique is most appropriate to find f′(x)f'(x)f′(x) efficiently?

  1. Differentiate using the chain rule by rewriting as (5x3−2x+7)1/2(5x^3-2x+7)^{1/2}(5x3−2x+7)1/2 (correct answer)
  2. Differentiate using the quotient rule after rewriting as 5x3−2x+75x3−2x+7\frac{5x^3-2x+7}{\sqrt{5x^3-2x+7}}5x3−2x+7​5x3−2x+7​
  3. Differentiate by expanding the square root into a polynomial
  4. Differentiate using implicit differentiation with y2=5x3−2x+7y^2=5x^3-2x+7y2=5x3−2x+7
  5. Differentiate using the product rule by writing 5x3−2x+7=5x3 −2x+7\sqrt{5x^3-2x+7}=\sqrt{5x^3}\,\sqrt{-2x+7}5x3−2x+7​=5x3​−2x+7​

Explanation: This problem asks for the most efficient technique to differentiate a square root of a polynomial. The function f(x)=sqrt5x3−2x+7f(x)=sqrt{5x^3-2x+7}f(x)=sqrt5x3−2x+7 can be rewritten as (5x3−2x+7)1/2(5x^3-2x+7)^{1/2}(5x3−2x+7)1/2, revealing it as a composite function perfect for the chain rule. Applying the chain rule gives f'(x) = rac{1}{2}(5x^3-2x+7)^{-1/2} cdot (15x^2-2) = rac{15x^2-2}{2sqrt{5x^3-2x+7}}. Option E's suggestion to split the square root as a product is mathematically incorrect since sqrta+beqsqrtacdotsqrtbsqrt{a+b} eq sqrt{a}cdotsqrt{b}sqrta+beqsqrtacdotsqrtb. When differentiating roots or fractional powers of expressions, rewriting with rational exponents and using the chain rule is the standard efficient approach.

Question 15

A revenue function is R(x)=sin⁡xx2+1\displaystyle R(x)=\frac{\sin x}{x^2+1}R(x)=x2+1sinx​. Which technique is most appropriate to find R′(x)R'(x)R′(x)?

  1. Differentiate using the quotient rule (correct answer)
  2. Differentiate using implicit differentiation
  3. Differentiate using the power rule only
  4. Differentiate using the limit definition only
  5. Differentiate using integration by substitution

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For R(x)=sin⁡xx2+1R(x) = \frac{\sin x}{x^2 + 1}R(x)=x2+1sinx​, the quotient rule is most appropriate because the function is a quotient of sin x and a polynomial, allowing direct application of (num′⋅den−num⋅den′den2)(\frac{\text{num}' \cdot \text{den} - \text{num} \cdot \text{den}'}{\text{den}^2})(den2num′⋅den−num⋅den′​). This efficiently incorporates the derivative of sin x as cos x and the polynomial's derivative. It yields R′(x)=cos⁡x(x2+1)−sin⁡x(2x)(x2+1)2R'(x) = \frac{\cos x (x^2 + 1) - \sin x (2x)}{(x^2 + 1)^2}R′(x)=(x2+1)2cosx(x2+1)−sinx(2x)​, which is straightforward. Using the power rule only would fail completely since the function involves a trigonometric numerator, not just powers. Match the differentiation technique to the function's primary structure, such as quotient for divisions, to ensure minimal rework.

Question 16

For p(x)=(x2−1)sin⁡(4x)p(x)=(x^2-1)\sin(4x)p(x)=(x2−1)sin(4x), which technique is most appropriate to compute p′(x)p'(x)p′(x)?

  1. Differentiate using the product rule, with a chain rule on sin⁡(4x)\sin(4x)sin(4x). (correct answer)
  2. Differentiate using the quotient rule after rewriting as x2−1csc⁡(4x)\dfrac{x^2-1}{\csc(4x)}csc(4x)x2−1​.
  3. Differentiate by expanding sin⁡(4x)\sin(4x)sin(4x) into its Taylor series, then differentiate term-by-term.
  4. Differentiate using implicit differentiation by setting y=(x2−1)sin⁡(4x)y=(x^2-1)\sin(4x)y=(x2−1)sin(4x) and solving for xxx.
  5. Differentiate using only the chain rule by treating (x2−1)sin⁡(4x)(x^2-1)\sin(4x)(x2−1)sin(4x) as one composite function.

Explanation: Selecting the appropriate differentiation technique is important for products involving polynomials and trigonometric functions in calculus. The product rule is most efficient here, applying it to (x² - 1) and sin(4x), with a chain rule on the sine term to account for the inner 4x. This yields 2x sin(4x) + (x² - 1) * 4 cos(4x), which is direct and requires minimal rewriting. It leverages the product structure naturally without complicating the expression. A tempting distractor is rewriting as a quotient using csc(4x), but this unnecessarily introduces the quotient rule and trigonometric reciprocals, making the differentiation more cumbersome. When faced with products, opt for the product rule combined with chain rules as needed to maintain simplicity and efficiency.

Question 17

A population model is P(t)=et2−3t (t4+1)P(t)=e^{t^2-3t}\,(t^4+1)P(t)=et2−3t(t4+1). Which technique is most appropriate to find P′(t)P'(t)P′(t)?

  1. Differentiate by expanding et2−3te^{t^2-3t}et2−3t into a series, then multiplying and differentiating.
  2. Differentiate using the quotient rule after rewriting as t4+1e−(t2−3t)\dfrac{t^4+1}{e^{-(t^2-3t)}}e−(t2−3t)t4+1​.
  3. Differentiate using the product rule, applying the chain rule to et2−3te^{t^2-3t}et2−3t. (correct answer)
  4. Differentiate using implicit differentiation by taking 0˘07fln0˘07f\u007fln\u007f0˘07fln0˘07f of both sides.
  5. Differentiate using the power rule by treating et2−3te^{t^2-3t}et2−3t as t2−3tt^{2-3t}t2−3t.

Explanation: Selecting the appropriate differentiation technique is crucial for products of exponential and polynomial functions in calculus. The product rule is most efficient, applying it to e^{t² - 3t} and (t^4 + 1), with a chain rule on the exponential to get (2t - 3) e^{t² - 3t}. This combines to P'(t) = (2t - 3) e^{t² - 3t} (t^4 + 1) + e^{t² - 3t} * 4t³, which is straightforward. It respects the product structure and handles the composition in the exponent naturally. A tempting distractor is using logarithmic differentiation by taking ln of both sides, but this is unnecessary for a product and complicates things since the function isn't in exponential form with variable exponents. When differentiating products, choose the product rule with embedded chain rules to efficiently compute without overcomplicating.

Question 18

In a mixing model, R(x)=x2+13x−2R(x)=\dfrac{x^2+1}{\sqrt{3x-2}}R(x)=3x−2​x2+1​. Which differentiation technique is most appropriate for R′(x)R'(x)R′(x)?

  1. Differentiate using the chain rule only
  2. Differentiate using the quotient rule (correct answer)
  3. Differentiate using implicit differentiation
  4. Differentiate by expanding into a polynomial first
  5. Differentiate using related rates

Explanation: Selecting the appropriate differentiation technique is a key skill in calculus, ensuring efficiency and accuracy in finding derivatives. For R(x) = (x² + 1)/√(3x - 2), the quotient rule is most appropriate because the function is a ratio of two functions, with the denominator involving a composition that requires the chain rule internally. This method efficiently handles the structure by differentiating the numerator and denominator separately while applying the chain rule to the square root. It yields a precise derivative without needing to rewrite the function drastically. Differentiating by expanding into a polynomial first is not feasible since the square root prevents polynomial expansion. Evaluate the overall form of the function to choose between quotient, product, or chain rules for optimal efficiency.

Question 19

If u(x)=1(x2−6x+10)3u(x)=\dfrac{1}{(x^2-6x+10)^3}u(x)=(x2−6x+10)31​, which differentiation technique is most appropriate for u′(x)u'(x)u′(x)?​

  1. Use the quotient rule
  2. Expand the denominator fully, then differentiate
  3. Use the chain rule after rewriting as a power (correct answer)
  4. Use implicit differentiation
  5. Use the limit definition of the derivative

Explanation: This problem requires selecting the most efficient method for a reciprocal of a power. The function u(x)=1(x2−6x+10)3u(x)=\frac{1}{(x^2-6x+10)^3}u(x)=(x2−6x+10)31​ can be rewritten as (x2−6x+10)−3(x^2-6x+10)^{-3}(x2−6x+10)−3, transforming it into a power function with a composite base. The chain rule is ideal here: differentiate the outer function (getting −3(x2−6x+10)−4-3(x^2-6x+10)^{-4}−3(x2−6x+10)−4) and multiply by the derivative of the inner function (getting 2x−62x-62x−6). Using the quotient rule (option A) would work but involves more algebraic manipulation with the cube in the denominator. When dealing with reciprocals of powers, rewriting with negative exponents and using the chain rule is typically more efficient than the quotient rule.

Question 20

For p(x)=(sin⁡x)5(cos⁡x)3p(x)=\big(\sin x\big)^5\big(\cos x\big)^3p(x)=(sinx)5(cosx)3, which differentiation technique is most appropriate to find p′(x)p'(x)p′(x)?​

  1. Use the product rule combined with the chain rule (correct answer)
  2. Use the quotient rule
  3. Use implicit differentiation only
  4. Use the power rule only
  5. Use the limit definition of the derivative

Explanation: This problem involves selecting the appropriate technique for a product of powers of trigonometric functions. The function p(x)=(sin⁡x)5(cos⁡x)3p(x)=(\sin x)^5(\cos x)^3p(x)=(sinx)5(cosx)3 is a product of two factors, each involving a composition (power of a trig function). The product rule is necessary to handle the multiplication, and within each term of the product rule, the chain rule is needed for the powers of sine and cosine. Applying the product rule gives (sin⁡x)5⋅ddx[(cos⁡x)3]+(cos⁡x)3⋅ddx[(sin⁡x)5](\sin x)^5 \cdot \frac{d}{dx}[(\cos x)^3] + (\cos x)^3 \cdot \frac{d}{dx}[(\sin x)^5](sinx)5⋅dxd​[(cosx)3]+(cosx)3⋅dxd​[(sinx)5], where each derivative requires the chain rule. Using implicit differentiation only (option C) would be unnecessarily complex for this explicit function. When differentiating products where each factor is itself a composite function, combine the product rule with the chain rule for efficient computation.