Confirming Continuity over an Interval Practice Test

Only on $(2,\infty)$, since the integrand is undefined for $t<0$.

On $(-\infty,2]\cup(2,\infty)$, since continuity can include $x=2$ by definition.

On $[1,\infty)$ only, since the integral starts at $1$.

On $(-\infty,\infty)$, since integrals always produce continuous functions.

On $(-\infty,2)\cup(2,\infty)$, since only $\frac{1}{x-2}$ is discontinuous at $2$.