Behavior of Accumulation Functions Involving Area Practice Test

$H$ is increasing only where $e^{-x^2}$ increases

$H$ is increasing because $e^{-x^2}>0$

$H$ is decreasing for $x>0$ and increasing for $x<0$

$H$ is decreasing because $e^{-x^2}$ decreases

$H$ is constant because $e^{-x^2}$ approaches $0$