Area of a Polar Region Practice Test

$\displaystyle \frac12\int_{-\pi}^{\pi}(1-2\cos\theta)^2,d\theta$

$\displaystyle \int_{0}^{\pi}(1-2\cos\theta)^2,d\theta$

$\displaystyle \frac12\int_{0}^{\pi}(1-2\cos\theta),d\theta$

$\displaystyle \frac12\int_{0}^{\pi}(1-2\cos\theta)^2,d\theta$

$\displaystyle \frac12\int_{0}^{2\pi}(1-2\cos\theta)^2,d\theta$