Practice Test 12

No, because MVT requires $G(2)=G(6)$.

Yes, because $G$ crosses 0.

Yes, because $G$ is continuous, so the derivative must be constant.

Yes, because $G$ is continuous on $[2,6]$ and differentiable on $(2,6)$, so some $c$ has $G'(c)=\dfrac{7-(-1)}{6-2}=2$.

No, because $G(2)$ is negative.