Solving Linear–Quadratic Systems Practice Test

Solve graphically and algebraically: the line $y=2x-4$ intersects the parabola $y=x^2-4$. What are the intersection point(s)?

$$\begin{cases} y = 2x - 4 \\ y = x^2 - 4 \end{cases}$$

Solve graphically and algebraically (substitution is fine). The solutions are the intersection point(s) of the line and the parabola:

$$\begin{cases}

y = 2x - 1 \

y = x^2 - 4

\end{cases}$$