All questions
Question 1
Learning center schedule:
Everyday Writing: Tuesday and Thursday, 6:30–7:30 p.m.
Job Forms: Tuesday, 7:00–9:00 p.m.
Reading at Work: Monday and Wednesday, 6:00–7:00 p.m.
Writing Practice: Saturday, 9:00 a.m.–12:00 noon
Students must attend every day listed for a class. Maria wants a writing class. She is available Tuesday and Thursday from 6:00 to 8:00 p.m. She cannot attend on weekends.
Which class fits Maria's goal and schedule?
- Everyday Writing, because both meetings fit her available evening hours (correct answer)
- Job Forms, because its Tuesday meeting begins during her available hours
- Reading at Work, because both meetings finish before 8:00 p.m.
- Writing Practice, because the class has only one weekly meeting
Explanation: When a schedule question lists multiple requirements, your job is to check every condition before choosing an answer. Here, you need to find a class that is (1) a writing class, (2) meets only on days Maria is available, and (3) fits entirely within her 6:00–8:00 p.m. window. Missing even one condition means the class doesn't work.
Everyday Writing meets Tuesday and Thursday, 6:30–7:30 p.m. Both days fall within Maria's available evenings, and 7:30 is before her 8:00 cutoff. The class is also a writing class. Every condition is satisfied, making A the correct answer.
Here's why the other options fail. B points to Job Forms, but that class runs until 9:00 p.m. on Tuesday — well past Maria's 8:00 p.m. limit. Just because a class starts during her available hours doesn't mean it ends in time. C suggests Reading at Work, which does finish before 8:00 p.m., but it meets Monday and Wednesday — not Tuesday and Thursday. More importantly, it's a reading class, not a writing class, so it doesn't even match Maria's goal. D highlights Writing Practice's single weekly meeting, which sounds convenient, but the class is on Saturday, and Maria cannot attend on weekends.
A useful strategy: on schedule-matching questions, make a quick mental checklist of every requirement before evaluating each option. One failed condition eliminates the choice entirely — don't let a partially correct answer trick you into selecting it.
Question 2
Available work shifts:
Shift 1: 6:30 a.m.–2:30 p.m.
Shift 2: 7:00 a.m.–3:00 p.m.
Shift 3: 7:30 a.m.–3:30 p.m.
Shift 4: 8:00 a.m.–4:00 p.m.
Workers must arrive 10 minutes before a shift. Buses reach the workplace at 6:45 a.m., 7:20 a.m., and 8:05 a.m. Devon must leave work by 3:10 p.m. to pick up his child.
Which shift can Devon work if he travels by bus?
- Shift 1, because the first bus arrives before the shift ends
- Shift 2, because the first bus arrives before the required arrival time (correct answer)
- Shift 3, because the second bus arrives just before the shift starts
- Shift 4, because the third bus arrives shortly after the start time
Explanation: When solving a scheduling problem like this, you need to juggle multiple conditions at once — arrival time requirements, bus schedules, and departure deadlines. Work through each constraint step by step before choosing an answer.
Devon needs to arrive 10 minutes early for his shift, and he must leave by 3:10 p.m. Check both conditions for every shift.
Shift 2 starts at 7:00 a.m., so Devon must arrive by 6:50 a.m. The first bus arrives at 6:45 a.m. — that's 5 minutes before the required arrival time, so he makes it. Shift 2 also ends at 3:00 p.m., which is before his 3:10 p.m. deadline. Both conditions are satisfied, making B the correct answer.
Here's why the other choices fail. A is tempting but wrong — the first bus arriving before Shift 1 ends doesn't help Devon get there on time. Shift 1 starts at 6:30 a.m., meaning he'd need to arrive by 6:20 a.m., but the earliest bus doesn't arrive until 6:45 a.m. He'd already be late. C says the second bus arrives "just before" Shift 3 starts at 7:30 a.m. — but that bus arrives at 7:20 a.m., and Devon needs to be there by 7:20 a.m. That's cutting it exactly to the minute with no margin, and more importantly, Shift 3 ends at 3:30 p.m., which is past his 3:10 p.m. pickup deadline. D fails immediately because the third bus arrives after Shift 4's start time — Devon would already be late before he even walked in.
When you see multi-condition scheduling questions, create a quick checklist: Does he arrive on time? Does he leave on time? Both boxes must be checked.
Question 3
Dental clinic information:
Cleaning appointments begin at 10:00 a.m., 10:30 a.m., or 11:00 a.m.
Patients must arrive 10 minutes before the appointment.
A cleaning takes 40 minutes. Checkout takes another 15 minutes.
Lee's bus reaches the clinic at 10:05 a.m. He must leave the clinic by 11:45 a.m.
Which appointment should Lee choose?
- The 10:00 a.m. appointment, because the cleaning ends at 10:40 a.m.
- The 11:00 a.m. appointment, because the cleaning ends at 11:40 a.m.
- The 10:30 a.m. appointment, because checkout ends at 11:25 a.m. (correct answer)
- No appointment, because every available time ends after 11:45 a.m.
Explanation: When a question gives you multiple time rules at once, slow down and check every rule against each option — arrival time, start time, and end time all matter.
Here's how to work through Lee's situation. He arrives at 10:05 a.m., so he cannot book any appointment that requires him to arrive earlier than 10:05. Since patients must arrive 10 minutes before their appointment, the 10:00 a.m. slot requires a 9:50 a.m. arrival — Lee misses that. The 10:30 a.m. slot requires a 10:20 a.m. arrival — Lee is there by 10:05, so he qualifies. Now check the finish time: cleaning (40 min) + checkout (15 min) = 55 minutes total. Starting at 10:30, Lee finishes at 10:30+55 min=11:25 a.m. — well before his 11:45 deadline. Choice C is correct.
Choice A is wrong for two reasons: Lee arrives too late for the 10:00 a.m. appointment (he'd need to be there by 9:50), and the answer ignores the 15-minute checkout, so the total time is miscalculated anyway. Choice B describes the 11:00 a.m. appointment correctly finishing the cleaning at 11:40, but it forgets the 15-minute checkout, which pushes the true end time to 11:55 a.m. — past Lee's 11:45 deadline. Choice D is wrong because, as shown, the 10:30 appointment works fine.
A useful habit: list every time constraint in the problem before evaluating any answer choice. Missing even one rule — like checkout time — leads you straight into the traps the question sets. Question 4
Downtown parking rates:
First hour or part of an hour: $3.00
Each additional hour or part of an hour: $2.00
Evening flat rate after 6:00 p.m.: $5.00, only for drivers who enter after 6:00 p.m.
Victor enters the parking lot at 4:50 p.m. and leaves at 7:10 p.m.
How much must Victor pay for parking?
- $7.00, because he uses one first hour and two additional started hours. (correct answer)
- $5.00, because he leaves the parking lot after 6:00 p.m.
- $9.00, because each of the three started hours costs $3.00.
- $10.00, because the daytime and evening rates must be added.
Explanation: When a parking lot has different rates, your first job is to figure out which rate applies — and read the conditions carefully, because the wording matters.
Victor enters at 4:50 p.m., which is before 6:00 p.m. That detail is critical. The evening flat rate of $5.00 only applies to drivers who enter after 6:00 p.m. Since Victor enters before 6:00 p.m., he pays the standard hourly rate for his entire stay, no matter when he leaves.
Now count his hours. He parks from 4:50 p.m. to 7:10 p.m. — that's 2 hours and 20 minutes. The rate charges for each started hour, so you round up any partial hour. That gives him 3 started hours total. The first hour costs $3.00, and each additional hour costs $2.00:
$\3.00 + $2.00 + $2.00 = $7.00
That makes A correct.
Choice B is wrong because the $5.00 evening rate requires entering after 6:00 p.m. — Victor entered at 4:50 p.m., so he doesn't qualify. Choice C incorrectly charges $3.00 for every hour, but only the first hour costs $3.00; additional hours are $2.00 each. Choice D invents a rule that doesn't exist — the rates aren't added together; only one rate structure applies based on your entry time.
Study tip: On questions with tiered or conditional pricing, underline the conditions (like "only for drivers who enter after...") before you calculate anything. Missing a condition is the most common trap. Question 5
Laundromat prices and limits:
Small washer: $3.00 for 1 basket
Large washer: $5.00 for up to 2 baskets
Extra-large washer: $7.00 for up to 3 baskets
Dryer: $2.00 for up to 3 baskets
Tara has 2 baskets of work clothes and 1 basket of towels. The towels must be washed separately from the work clothes. All 3 baskets may be dried together.
What is the lowest-cost way for Tara to wash and dry everything?
- Use one extra-large washer and one dryer for a total of $9.00.
- Use one large washer, one small washer, and one dryer for $10.00. (correct answer)
- Use three small washers and one dryer for a total of $11.00.
- Use two large washers and two dryers for a total of $14.00.
Explanation: When a question asks for the "lowest-cost way," you need to think like a comparison shopper — try different combinations, add up the totals, and pick the cheapest one. The key constraint here is that Tara must wash the towels separately from the work clothes, so you need at least two separate washer loads.
The smartest move is to match each load to the smallest (cheapest) washer that fits it. Tara has 2 baskets of work clothes — that fits exactly in a large washer at $5.00. The 1 basket of towels fits in a small washer at $3.00. For drying, all 3 baskets can go together in one dryer at $2.00. That gives you $5 + 3 + 2 = \10.00 — which is answer B, the correct choice.
A uses an extra-large washer ($7.00) for all three baskets, but that's not allowed — the towels must be washed separately. Even if it were allowed, one dryer costs $2.00, totaling $9.00, but this option violates the rules entirely, making it invalid regardless of price.
C uses three small washers ($3 × 3 = 9.00)plusonedryer(2.00) for $11.00. This is technically legal but wasteful — you're paying for three machines when two are enough.
D uses two large washers ($5 × 2 = 10.00)andtwodryers(2 × 2 = $4.00) for $14.00. Two dryers are completely unnecessary since all baskets dry together.
A good tip: always read the rules carefully before comparing prices — an option that looks cheap may break a stated condition and should be crossed off first. Question 6
Monthly phone plans:
Basic: $16 for 2 GB of data; each extra GB or part of a GB costs $6
Choice: $25 for 5 GB of data; each extra GB costs $5
Flex: $20 for 3 GB of data; each extra GB or part of a GB costs $4
Andre expects to use 4 GB of data and wants the lowest monthly price.
Which plan should Andre choose?
- The Basic plan, with a monthly cost of $28
- The Choice plan, with a monthly cost of $25
- The Flex plan, with a monthly cost of $24 (correct answer)
- The Basic plan, with a monthly cost of $22
Explanation: When a question asks you to compare phone plans, your job is to calculate the total cost for each plan given a specific usage — not just look at the base price. Here, Andre needs 4 GB, so you must figure out what each plan actually charges him for that amount.
Start with the Flex plan: it includes 3 GB for $20, and Andre needs 1 extra GB at $4 each. That gives $20 + 4 = \24. That's option C, and it's the lowest total you'll find.
Now check the others. For the Basic plan, Andre gets 2 GB for $16 but needs 2 extra GB at $6 each: $16+(2\times 6) = \28$$. That matches option A, which correctly calculates the Basic plan — but $28 is higher than the Flex plan, so it's not the best deal. Option D also claims the Basic plan but lists a cost of $22, which would require only one extra GB. Andre needs 2 extra GB beyond the Basic plan's 2 GB allowance, so $22 is a miscalculation — a classic arithmetic trap.
For the Choice plan (option B), Andre gets 5 GB for $25 — but he only needs 4 GB. He's paying for more data than he uses, and $25 is still more than $24, so this isn't the cheapest option.
The winning plan is C, the Flex plan at $24.
Study tip: Always calculate the full cost for each plan before comparing. A higher base price can sometimes beat a lower one once you add overage fees. Question 7
Library computer schedule:
Computer sessions begin at 6:00 p.m., 6:30 p.m., and 7:00 p.m.
Each session lasts 45 minutes.
The printing desk closes at 7:30 p.m.
Printing takes about 10 minutes.
Rosa arrives at 6:20 p.m. She needs a full computer session before she prints her papers.
Which computer session should Rosa choose so she can also finish printing?
- The 6:00 p.m. session, followed by printing at about 6:45 p.m.
- A 7:30 p.m. session, followed by printing at about 8:15 p.m.
- The 7:00 p.m. session, followed by printing at about 7:45 p.m.
- The 6:30 p.m. session, followed by printing at about 7:15 p.m. (correct answer)
Explanation: When a question gives you a schedule with time limits, your job is to work forward through the steps — session start → session end → printing done — and check whether each fits before a deadline.
Here's how the math works for answer D: Rosa arrives at 6:20 p.m., which means she has already missed the 6:00 p.m. session start. The next available session begins at 6:30 p.m. Each session lasts 45 minutes, so: 6:30+0:45=7:15 p.m. (session ends) Printing takes 10 more minutes: 7:15+0:10=7:25 p.m. (printing done) The printing desk closes at 7:30 p.m., so Rosa finishes with 5 minutes to spare. D is correct.
Now let's look at why the other choices fail. A is impossible because the 6:00 p.m. session already started before Rosa arrived at 6:20 — she cannot get a full session. B describes a 7:30 p.m. session, which doesn't exist on the schedule — sessions are only at 6:00, 6:30, and 7:00 — and even if it did, printing would end at 8:15 p.m., long after the desk closes. C is tempting but fails the deadline test: the 7:00 p.m. session ends at 7:45 p.m., and printing would finish at 7:55 p.m. — both after the 7:30 p.m. desk closing.
A useful strategy: always check every step in a chain of events against the final deadline. Missing even one step — like confirming the session already started — is the most common trap in schedule-reading questions. Question 8
Cafe lunch list:
Garden wrap: $7; vegetarian; served cold; contains cheese
Bean bowl: $8; vegetarian; served hot; dairy-free
Chicken plate: $9; served hot; dairy-free
Soup and salad: $6; vegetarian; served hot; soup contains milk
Drink: $2
Elena wants a hot, vegetarian, dairy-free lunch with a drink. She can spend no more than $10.
Which order meets all of Elena's needs?
- A garden wrap and a drink for a total of $9
- Soup and salad with a drink for a total of $8
- A chicken plate without a drink for a total of $9
- A bean bowl and a drink for a total of $10 (correct answer)
Explanation: When a question gives you a list of requirements, treat each one like a filter — every condition must be met, not just most of them. Elena needs four things: hot, vegetarian, dairy-free, and under $10 total (including a drink).
Start by pricing in the drink: at $2, her food can cost no more than $8. Now run each item through all four filters together.
Option D, the bean bowl and a drink, passes every test. The bean bowl costs $8, is vegetarian, served hot, and dairy-free. Add the $2 drink and you get exactly $10 — right at her limit. This is the correct answer.
Option A fails on two counts: the garden wrap is served cold, not hot, and it contains cheese, which means it's not dairy-free. Even though the math works at $9, two requirements are broken.
Option B looks promising — soup and salad is vegetarian and hot — but the soup contains milk, making it not dairy-free. That one detail disqualifies it entirely, even at the low price of $8.
Option C fails because the chicken plate is not vegetarian, and Elena specifically needs a vegetarian meal. It also doesn't include a drink, which Elena said she wants.
The key strategy here is to check every requirement before selecting an answer. A common trap on these questions is to find an answer that satisfies most conditions and stop there. Always go through the full checklist — one missed condition means the whole answer is wrong.
Question 9
Bus schedule to Central Station:
Route 4 departures: 7:50 a.m., 8:10 a.m., 8:25 a.m., and 8:40 a.m.
The ride takes 35 minutes. From Central Station, it is a 10-minute walk to the office.
Nina must reach the office by 9:00 a.m. What is the latest bus she can take?
- The 7:50 a.m. bus, arriving at the office at 8:35 a.m.
- The 8:10 a.m. bus, arriving at the office at 8:55 a.m. (correct answer)
- The 8:25 a.m. bus, arriving at the office at 9:10 a.m.
- The 8:40 a.m. bus, arriving at the office at 9:25 a.m.
Explanation: When a question asks about the "latest" option that still meets a deadline, you need to work backwards from the end goal. Here, Nina must arrive at the office by 9:00 a.m., and getting there involves two steps: a 35-minute bus ride plus a 10-minute walk. That's a total travel time of 45 minutes after boarding the bus. So ask yourself: which is the latest bus that gets her there by 9:00 a.m., not after?
The 8:10 a.m. bus is the correct choice. Adding 35 minutes puts her at Central Station at 8:45 a.m., and after a 10-minute walk, she arrives at 8:55 a.m. — five minutes before her deadline. That's choice B, and it's the latest bus that still works.
Choice A (the 7:50 a.m. bus) also gets her there on time — arriving at 8:35 a.m. — but it's not the latest option. The question asks how long she can wait, not just whether she'd make it.
Choice C (the 8:25 a.m. bus) arrives at the office at 9:10 a.m., which is 10 minutes too late. It misses the 9:00 a.m. deadline.
Choice D (the 8:40 a.m. bus) is even later, arriving at 9:25 a.m. — clearly past the deadline.
A good strategy: when a question says "latest," eliminate any option that misses the deadline, then pick the latest departure among the ones that work. Don't stop at the first bus that arrives on time.
Question 10
Market prices:
Small bag of rice: 2 pounds for $4.50
Large bag of rice: 5 pounds for $9.00
Bag of beans: 1 pound for $2.75
Omar needs at least 5 pounds of rice and 2 pounds of beans. He can spend no more than $15.00.
Which purchase gives Omar enough rice and beans without going over his budget?
- Two small rice bags and two bean bags for $14.50
- One large rice bag and two bean bags for $14.50 (correct answer)
- One large rice bag and three bean bags for $17.25
- Three small rice bags and one bean bag for $16.25
Explanation: When a question gives you a shopping scenario with two conditions — a minimum amount needed and a maximum budget — check both conditions for every answer choice. Skipping either one is how test-takers get tripped up.
Let's work through the math. Omar needs at least 5 pounds of rice and at least 2 pounds of beans, spending no more than $15.00.
Answer B — one large bag of rice plus two bags of beans — is the correct choice. The large rice bag gives exactly 5 pounds for $9.00. Two bean bags give 2 pounds for $2 \times \2.75 = $5.50. The total is $9.00 + $5.50 = $14.50, which meets both quantity requirements and stays under budget. ✓
Answer A — two small bags of rice plus two bean bags — also costs $14.50, so the price looks the same. But two small bags only provide $$2 \times 2 = 4$$ pounds of rice, which falls short of the 5-pound minimum. This is a trap designed to catch you if you skip checking the quantity.
Answer C — one large rice bag and three bean bags — meets the quantity requirements, but costs $9.00+(3×$2.75)=$17.25, which exceeds the $15.00 budget.
Answer D — three small bags and one bean bag — costs $\13.50 + $2.75 = $16.25$$ and only provides 1 pound of beans, failing both the budget and the bean requirement.
A good habit: make a quick two-column checklist (quantities | cost) for each option so nothing slips through.