All questions
Question 1
A student investigated how the number of paper towel layers affects water absorption. She cut paper towels into identical 10 cm×10 cm squares and stacked them to make pads with 1, 2, 3, or 4 layers. She poured exactly 50 mL of water onto each pad placed in the same type of tray. After 60 seconds, she measured how much water remained in the tray (in mL) and calculated water absorbed by the pad. All trials used the same brand of paper towel and were performed at room temperature. Which of the following is the independent variable?
- Water absorbed by the paper towel pad
- Number of paper towel layers (correct answer)
- Volume of water poured (50 mL)
- Time before measuring (60 seconds)
Explanation: In this experiment, the independent variable is the number of paper towel layers, the dependent variable is the water absorbed by the paper towel pad, and controlled variables include the volume of water poured, time before measuring, paper towel size, brand, and room temperature. The independent variable is intentionally varied to examine its impact, the dependent variable is calculated from measurements like remaining water, and controlled variables are kept consistent to ensure the results reflect only the independent variable's effect. Choice B correctly identifies the number of paper towel layers as the independent variable because it was manipulated (1, 2, 3, 4 layers) to test absorption. Choice A is the dependent variable, as water absorbed was the measured response, not what was changed.
Question 2
A student examined whether fertilizer amount changes the number of flowers produced by marigold plants. She grew identical seedlings in 12 identical pots with the same soil type. Pots were assigned to receive 0 g, 5 g, 10 g, or 15 g of fertilizer per week (3 pots per group). All plants received the same volume of water each day, were kept in the same greenhouse with the same light schedule, and were grown for 6 weeks. At the end, she counted the number of flowers on each plant.
Which factor was controlled in this experiment?
- Amount of fertilizer applied per week
- Number of flowers counted after 6 weeks
- Daily volume of water given to each plant (correct answer)
- Number of weeks the plants were grown
Explanation: The independent variable is fertilizer amount (0g, 5g, 10g, or 15g per week - what was changed), the dependent variable is number of flowers (what was measured), and controlled variables include water volume, soil type, pot size, light schedule, and growth duration (all kept constant). To isolate fertilizer's effect, the student kept water volume the same for all plants. Choice C correctly identifies daily water volume as a controlled variable because it was held constant across all treatment groups. Choice A (fertilizer amount) is the independent variable being tested, not a controlled factor.
Question 3
A botanist studied the effect of water frequency on plant health. Plants were watered daily, weekly, or not at all, and health was assessed. The primary purpose of this experiment was to:
- Test the impact of water quality on growth.
- Find drought-resistant plant species.
- Measure water absorption by plants.
- Determine optimal watering frequency for plant health. (correct answer)
Explanation: The experiment tests how watering frequency affects plant health by providing different watering schedules (daily, weekly, none) and assessing plant condition. The botanist varies watering frequency while measuring plant health responses to determine optimal watering practices. The primary purpose is to determine optimal watering frequency for plant health, as this involves comparing different watering schedules to identify the most beneficial approach. The experiment specifically tests multiple frequencies to establish best practices for plant care rather than testing drought resistance or water quality effects.
Question 4
The consistency of results in a viscosity measurement experiment would most likely be affected by:
- Measuring at a constant speed.
- Using a digital viscometer.
- Mixing liquids with different densities.
- Temperature fluctuations during measurement. (correct answer)
Explanation: Temperature fluctuations during viscosity measurement would most significantly affect result consistency because viscosity is highly temperature-dependent for most liquids. As temperature changes, the liquid's viscosity changes accordingly, causing measured values to vary even when using the same sample under otherwise identical conditions. These temperature variations introduce random error since room temperature typically fluctuates unpredictably, leading to scattered results rather than systematic bias. Maintaining constant temperature is crucial for reproducible viscosity measurements since even small temperature changes can produce significant viscosity variations.
Question 5
PASSAGE V
BIOLOGY: This passage is adapted from a study on the metabolic rates of vertebrates.
Introduction
Metabolism is the set of chemical reactions that occur in living organisms to maintain life. The metabolic rate is often measured by the amount of oxygen (O2) consumed per gram of body mass per hour.
Animals can be classified based on how they regulate body temperature:
•Endotherms (e.g., mammals, birds) generate their own body heat to maintain a constant internal temperature.
•Ectotherms (e.g., reptiles, amphibians) rely on external heat sources to regulate their body temperature.
Students conducted two studies to compare the metabolic rates of a Mouse (Endotherm) and a Lizard (Ectotherm) of similar body mass.
Study 1
The students placed the mouse and the lizard in separate metabolic chambers. They varied the environmental temperature from 5°C to 35°C in 10°C increments. The animals were kept at rest. The rate of oxygen consumption (mL O2/g⋅hr) was measured after the animals had acclimated to each temperature for 30 minutes. Findings were reported in Figure 1.
Study 2
The students investigated the effect of activity level on metabolic rate. They maintained the environmental temperature at 25°C for both animals. They measured the oxygen consumption while the animals were at rest and while they were running on a treadmill at 1.0 km/hr. Findings were reported in Table 1.
Study 3
To determine if body mass affects metabolic rate within the same group, students measured the resting metabolic rate of three different lizards at 25°C. Findings were reported in Table 2.
Based on Table 2, what is the relationship between body mass and metabolic rate per gram for lizards?
- As body mass increases, metabolic rate per gram increases.
- As body mass increases, metabolic rate per gram decreases. (correct answer)
- Metabolic rate per gram is independent of body mass.
- Metabolic rate per gram doubles for every 50 g increase in mass.
Explanation: This is a trend identification question. Table 2 shows three lizards: as mass increases from 20 g to 50 g to 100 g, the metabolic rate per gram decreases from 0.80 to 0.50 to 0.35 mL O₂/g·hr. This is a clear inverse relationship—larger lizards have lower mass-specific metabolic rates. Choice B correctly describes this inverse trend. Choice A (increases) is opposite. Choice C (independent) would show no pattern. Choice D (doubles) is factually wrong and describes an increase, not decrease. Pro tip: This inverse relationship reflects a biological principle (Kleiber's Law)—larger animals have lower per-gram metabolic rates due to surface area to volume ratios.
Question 6
A lab tested whether a disinfectant (Solution D) reduces bacterial growth on countertops. Identical countertop squares were inoculated with bacteria and then treated with either Solution D or water (Control). After 4 hours, technicians counted colony-forming units (CFU). The experiment was repeated at two room humidities.
Based on the data, which conclusion is most strongly supported?
- Solution D works only at low humidity, since CFU counts are higher at 70% RH than 30% RH.
- Solution D eliminates all bacteria regardless of humidity, proving complete sterilization within 4 hours.
- Humidity has no effect on CFU because Solution D lowers CFU under both humidity conditions.
- Solution D reduces CFU relative to water at both humidities tested, though humidity still affects overall CFU. (correct answer)
Explanation: Solution D reduces CFU relative to water control at both humidity levels tested, though humidity still affects overall bacterial survival. At 30% humidity, Solution D yields 150 CFU compared to 1,200 for Control (87.5% reduction), and at 70% humidity, it yields 260 CFU versus 2,100 for Control (87.6% reduction). The consistently large reductions demonstrate Solution D's effectiveness across humidity conditions. However, humidity clearly influences bacterial growth since both treatments show higher CFU at 70% than 30% humidity, indicating environmental factors interact with but don't eliminate the disinfectant's antimicrobial effect.
Question 7
A chemist investigated how temperature affects the rate of a reaction that produces gas. The same concentrations of reactants were used each time. The chemist measured the time required to produce 50 mL of gas at three temperatures.
Based on the data, which conclusion is most strongly supported?
- Increasing temperature increases the reaction rate over 10–30°C, as shown by decreasing time to produce 50 mL gas. (correct answer)
- Reaction rate is independent of temperature because gas volume produced is the same in all trials.
- The reaction stops at 30°C because the time is lowest, indicating no further gas can be produced.
- Temperature decreases reaction rate, since higher temperatures correspond to smaller numerical values in the table.
Explanation: Increasing temperature increases the reaction rate over the 10-30°C range, as demonstrated by the decreasing time required to produce 50 mL of gas. At 10°C, the reaction took 120 seconds, at 20°C it took 75 seconds, and at 30°C only 50 seconds. Since reaction rate is inversely related to time (faster reactions take less time), the data show that higher temperatures accelerate this gas-producing reaction. This follows the general principle that increased thermal energy enhances molecular motion and collision frequency, leading to faster chemical reactions.
Question 8
A study aimed to find the effect of exercise duration on weight loss. Participants engaged in different lengths of exercise routines while their diet and sleep were kept constant. The change in weight was recorded. Which is the dependent variable?
- Sleep
- Diet
- Change in weight (correct answer)
- Exercise duration
Explanation: The independent variable is exercise duration (what was varied with different lengths of routines), the dependent variable is change in weight (what was recorded), and controlled variables include diet and sleep (kept constant). The dependent variable is the measured response that depends on changes in the independent variable. Choice C correctly identifies change in weight as the dependent variable since this outcome was recorded in response to different exercise durations.
Question 9
An experiment is conducted to test the effect of air pressure on sound speed. The independent variable is air pressure, and the dependent variable is the speed of sound. Which change would make the experiment more reliable?
- Using different sound frequencies.
- Repeating the experiment multiple times. (correct answer)
- Measuring sound intensity instead.
- Varying the temperature during experiments.
Explanation: The independent variable is air pressure, the dependent variable is sound speed, and controlled variables should include temperature, humidity, and measurement distance. Choice B correctly identifies that repeating the experiment multiple times would make it more reliable by reducing random error and improving the precision of measurements. Multiple trials allow for statistical analysis and help identify outliers or measurement errors, leading to more confident conclusions about the relationship between air pressure and sound speed. Choice A would change the independent variable, while choices C and D would alter the experimental design rather than improve reliability of the current setup.
Question 10
A student tested the hypothesis that increasing salt concentration lowers the freezing point of water. She prepared 4 beakers, each with 100 mL of distilled water, and added NaCl to reach concentrations of 0%, 2%, 4%, or 6% (mass/volume). Each beaker was placed in the same freezer set to −10∘C for 45 minutes. The student stirred each beaker for 10 seconds every 5 minutes using the same stirring rod and then recorded the temperature at which the first ice crystals appeared (freezing point). All beakers were identical and started at 20∘C. Which of the following is the independent variable?
- Temperature when ice first appears
- Time in the freezer (45 minutes)
- Salt concentration in the water (correct answer)
- Freezer temperature (−10∘C)
Explanation: In this experiment, the independent variable is the salt concentration in the water, the dependent variable is the temperature when ice first appears, and controlled variables include the freezer temperature, time in the freezer, water volume, and initial temperature. The independent variable is what the experimenter deliberately changes to test its effect, the dependent variable is the outcome measured in response to that change, and controlled variables are factors kept constant to ensure a fair test. Choice C correctly identifies the salt concentration as the independent variable because it was manipulated across different levels (0%, 2%, 4%, 6%) to observe its impact on freezing point. Choice A represents the dependent variable, as it is the measured response, not what was changed.
Question 11
Two hypotheses explain the increase in jellyfish populations. Hypothesis 1 states warmer ocean temperatures increase jellyfish numbers. Hypothesis 2 suggests overfishing of predators is the cause. Data correlates higher jellyfish numbers with warmer temperatures. Which hypothesis is more supported?
- Neither hypothesis is supported.
- Hypothesis 2 is more supported.
- Both hypotheses are equally supported.
- Hypothesis 1 is more supported. (correct answer)
Explanation: Hypothesis 1 is more supported because it correctly predicts that warmer ocean temperatures increase jellyfish populations. The data correlates higher jellyfish numbers with warmer temperatures, which directly aligns with Hypothesis 1's temperature-driven population growth prediction. Hypothesis 2 suggests overfishing of predators as the cause, but this explanation doesn't account for the observed temperature-population correlation patterns. The evidence clearly demonstrates that thermal conditions, not predator removal alone, drive the observed jellyfish population increases.
Question 12
PASSAGE II
BIOLOGY: This passage is adapted from a study on the factors affecting the rate of photosynthesis in aquatic plants.
Introduction
Photosynthesis is the process by which green plants use sunlight to synthesize nutrients from carbon dioxide (CO2) and water (H2O). The process releases oxygen (O2) as a byproduct according to the following chemical equation:
6CO2+6H2O+light energy→C6H12O6+6O2
Students conducted three studies to investigate how different environmental factors affect the rate of photosynthesis in Elodea, an aquatic plant. The rate was measured by counting the number of oxygen bubbles produced by a cut stem of Elodea submerged in water over a 5-minute period.
Study 1
To test the effect of light intensity, students placed a 10 cm sprig of Elodea into a test tube filled with a 0.5% sodium bicarbonate (NaHCO3) solution (a source of CO2). A light source was placed at various distances from the test tube. The temperature was maintained at 25°C. The number of bubbles produced in 5 minutes was recorded.
Study 2
To test the effect of light color (wavelength), students used the same setup as in Study 1. The light source was kept at a constant distance of 10 cm. Colored filters were placed between the light and the plant to isolate specific wavelengths. Clear cellophane was used as a control.
Study 3
To test the effect of CO2 availability, students prepared five test tubes with different concentrations of sodium bicarbonate (NaHCO3). A 10 cm sprig of Elodea was placed in each. The light source was kept constant at 10 cm (white light).
Based on the chemical equation provided in the Introduction, the bubbles counted in these experiments consisted primarily of:
- Carbon dioxide (CO₂).
- Water vapor (H₂O).
- Glucose (C₆H₁₂O₆).
- Oxygen (O₂). (correct answer)
Explanation: This is a basic science understanding question about what's being measured. The introduction states photosynthesis "releases oxygen (O₂) as a byproduct" and the experimental procedure states "The rate was measured by counting the number of oxygen bubbles." The chemical equation shows 6O₂ as a product. Choice D (Oxygen) is correct and explicitly stated. Choice A (CO₂) is a reactant (input), not product. Choice B (H₂O) is also a reactant. Choice C (Glucose) is a product but it's dissolved in plant cells, not released as bubbles. Pro tip: For measurement questions, carefully note what the procedure states is being counted or measured.
Question 13
PASSAGE IV
PHYSICS: Research Summary
Introduction
A group of physics students investigated the motion of a projectile. They used a toy cannon that utilizes a compressed steel spring to launch a 50-gram (g) plastic ball.
The students investigated how the horizontal distance traveled by the ball (D) was affected by two variables:
1. The launch angle (θ), measured in degrees from the horizontal.
2. The spring compression distance (x), which is the distance the spring is pushed inward before being released.
Study 1
The students set up the cannon on a flat, level field. They kept the spring compression distance (x) constant at 4.0 cm for all trials. They launched the ball at five different angles (θ) and measured the horizontal distance (D) the ball traveled before hitting the ground. The results are shown in Table 1.
Study 2
Next, the students kept the launch angle (θ) constant at 45∘ (the angle that yielded the greatest distance in Study 1). They varied the spring compression distance (x) and measured the resulting horizontal distance (D). The results are shown in Table 2.
Based on the trend in Table 1, if the students had launched the ball at an angle of 90° (straight up), the horizontal distance traveled by the ball would most likely be:
- 0.0 m (correct answer)
- 10.0 m
- 20.0 m
- 25.0 m
Explanation: The correct answer is A (0.0 m). The data in Table 1 shows that as the angle moves away from 45° in either direction, horizontal distance decreases: at 75° the distance is 10.0 m, which is lower than at 45° (20.0 m). If the ball is launched straight up at 90°, all of the projectile's velocity is directed vertically — none is directed horizontally. The ball would travel straight up and land directly back at the launch point, traveling zero horizontal distance. The trend from 45° to 75° shows decreasing horizontal distance as the angle approaches vertical, and at exactly 90° this reaches its minimum of 0.0 m. G (10.0 m) is the value at 75°, which is a plausible wrong answer for students who don't extrapolate the trend fully. Pro tip: on extrapolation questions, follow the established trend to its logical physical endpoint.
Question 14
Which statement about measurement precision is supported by the data?
- The scale measures to the nearest 0.1 cm. (correct answer)
- The scale measures to the nearest 1 cm.
- The scale measures to the nearest 0.01 cm.
- The scale measures to the nearest 5 cm.
Explanation: The precision of a measuring scale is determined by examining its smallest marked divisions. When a scale has gradations marked at 1 cm intervals, proper measurement technique allows readings to be estimated to 0.1 cm by interpolating between the marked lines. This represents appropriate precision for such an instrument - not claiming false precision beyond its capability. A scale measuring to 0.01 cm would require much finer markings than typical ruler gradations.
Question 15
A meteorology club recorded wind speed and air pressure during five afternoon observations. Use Table 1 to answer the question.
Which observation had the highest air pressure?
- Obs. 1
- Obs. 5 (correct answer)
- Obs. 3
- Obs. 2
Explanation: Observation 5 had the highest air pressure. In Table 1, scan down the air pressure column and compare all values to identify the maximum pressure reading, which occurs in Obs. 5. To solve this systematically, examine each air pressure value and determine which observation corresponds to the highest pressure measurement.
Question 16
The digital thermometer reads 36.58 °C. The precision of the thermometer is:
- 1 °C
- 0.1 °C
- 0.001 °C
- 0.01 °C (correct answer)
Explanation: Digital thermometer precision is indicated by the number of decimal places in its display. A reading of 36.58°C shows measurement to two decimal places, indicating precision to 0.01°C. This precision level is typical for quality digital thermometers used in laboratory or medical applications. The displayed resolution reflects the instrument's ability to detect small temperature differences reliably.
Question 17
PASSAGE VI
Fruit Fly Genetics
Introduction
In the fruit fly Drosophila melanogaster, eye color is a sex-linked trait determined by a gene on the X chromosome. The allele for the wild-type red eye color (XR) is dominant, while the allele for the mutant white eye color (Xr) is recessive.
Females (XX): Inherit one X chromosome from each parent. A female will have white eyes only if she is homozygous recessive (XrXr).
Males (XY): Inherit an X chromosome from the mother and a Y chromosome from the father. Because the Y chromosome does not carry the eye color gene, a male expresses whichever allele is present on his single X chromosome (X^R Y \= Red; X^r Y \= White).
Students conducted two studies to observe these inheritance patterns.
Study 1
The students crossed a homozygous red-eyed female (XRXR) with a white-eyed male (XrY). To predict the genotypes of the offspring, they constructed a Punnett square (Figure 1).
They then collected 100 offspring (the F1 generation) and recorded the results in Table 1.
Study 2
The students performed the reciprocal cross. They crossed a white-eyed female (XrXr) with a red-eyed male (XRY). A second Punnett square was constructed to predict the outcome (Figure 2).
They collected 100 offspring and recorded the results in Table 2.
A student hypothesized that the gene for eye color is located on an autosome (a non-sex chromosome). Do the results of Study 1 and Study 2 support this hypothesis?
- Yes; the ratio of red-eyed to white-eyed offspring was 1:1 in both studies.
- Yes; both males and females inherited the red eye trait equally in Study 2.
- No; if the trait were autosomal, the reciprocal crosses in Study 1 and Study 2 would have yielded identical results. (correct answer)
- No; the F1 males in Study 2 had red eyes, while the females had white eyes.
Explanation: This is a hypothesis evaluation question that requires you to understand how reciprocal crosses can reveal sex-linkage. The key phrase "Do the results... support this hypothesis?" signals you need to compare the hypothesis claim against the actual data. The hypothesis claims the gene is on an autosome (non-sex chromosome). If true, swapping which parent has which trait (reciprocal crosses) shouldn't change the offspring ratios—the sex of the parent shouldn't matter. But comparing Table 1 (all red offspring) with Table 2 (mixed white males, red females) shows dramatically different results. This difference proves the trait IS linked to sex chromosomes, refuting the autosomal hypothesis. Choice A is factually wrong about the ratios. Choice B is wrong because inheritance was NOT equal between sexes in Study 2 (males were white, females were red). Choice D is backwards—it claims males had red while females had white (opposite of reality). Pro tip: Sex-linked traits produce different results when you swap which parent has the trait; autosomal traits do not. When reciprocal crosses differ, the trait must be sex-linked!
Question 18
A psychology experiment tested whether a brief mindfulness session reduces test anxiety. Sixty students were randomly assigned to either 10 minutes of guided mindfulness or quiet sitting. Anxiety was rated (0–100) immediately before and immediately after the session.
Based on the data, which conclusion is most strongly supported?
- Mindfulness is associated with a larger mean reduction in anxiety than quiet sitting under these study conditions. (correct answer)
- Quiet sitting increases anxiety because its post‑session mean remains above 50.
- Mindfulness eliminates anxiety entirely, since the post‑session mean is much lower than the pre-session mean.
- Mindfulness works only for students with initially low anxiety, as shown by similar pre-session means.
Explanation: Mindfulness is associated with a larger mean reduction in anxiety than quiet sitting under these study conditions. Both groups started with similar anxiety levels (68-69) and both decreased after the 10-minute sessions, but mindfulness produced a greater reduction. The mindfulness group decreased by 14 points (69→55) compared to 8 points for quiet sitting (68→60). While both interventions showed benefits relative to baseline, the mindfulness session resulted in a 6-point greater improvement than the control condition, suggesting it may be more effective for acute anxiety reduction in this population.
Question 19
PASSAGE III
EARTH SCIENCE / BIOLOGY: Conflicting Viewpoints
Introduction
Approximately 66 million years ago, a mass extinction event occurred at the boundary between the Cretaceous and Paleogene periods (the K-Pg boundary), wiping out roughly 75% of all plant and animal species on Earth, including all non-avian dinosaurs. Geologists have discovered a distinct layer of sedimentary rock worldwide at the K-Pg boundary that contains unusually high levels of iridium, a metal rare in Earth’s crust. Two scientists present different hypotheses for the cause of the extinction and the source of the iridium.
Scientist 1
The mass extinction was caused by the impact of a massive asteroid, approximately 10 kilometers in diameter. Asteroids are naturally rich in iridium. When the asteroid struck the Earth, the immense force of the collision vaporized the asteroid and a large portion of Earth's crust, ejecting a massive cloud of iridium-rich dust and debris into the atmosphere. This dust cloud enveloped the planet for months or even years, blocking out incoming sunlight. The lack of sunlight halted photosynthesis globally, causing the collapse of marine and terrestrial food webs.
Furthermore, the impact would have triggered global wildfires, acid rain, and massive tsunamis. The presence of shocked quartz (quartz crystals deformed by intense, sudden pressure) and tektites (glassy spheres formed by rapidly cooling, ejected rock) in the K-Pg boundary layer alongside the iridium firmly points to a high-velocity extraterrestrial impact as the sole trigger of the extinction.
Scientist 2
The mass extinction was not caused by a sudden impact, but rather by intense, prolonged volcanic activity. Around 66 million years ago, a massive volcanic region in what is now India, known as the Deccan Traps, experienced a series of colossal eruptions that lasted for tens of thousands of years. These eruptions released millions of cubic kilometers of lava.
While iridium is rare in Earth's surface crust, it is present in high concentrations in the deep mantle. The massive magma plumes from the Deccan Traps brought this deep-Earth iridium to the surface, where volcanic ash plumes spread it globally. The prolonged eruptions released massive quantities of sulfur dioxide (SO2) and carbon dioxide (CO2) into the atmosphere. The SO2 caused severe short-term global cooling and acid rain, while the CO2 led to long-term extreme global warming. This resulting climate instability severely stressed ecosystems over thousands of years, leading to a gradual, rather than instantaneous, mass extinction. Shocked quartz can also be formed by the explosive pressures of massive volcanic eruptions.
Suppose a geological study proved that tektites can only form when rock is subjected to temperatures and instantaneous impact pressures far exceeding those generated by even the most explosive volcanic eruptions. This finding would:
- support Scientist 1's hypothesis. (correct answer)
- support Scientist 2's hypothesis.
- weaken Scientist 1's hypothesis.
- have no effect on either hypothesis.
Explanation: The correct answer is A. Tektites appear in both scientists' frameworks. Scientist 1 uses tektites as evidence of a high-velocity extraterrestrial impact. Scientist 2 acknowledges tektites but claims 'Shocked quartz can also be formed by the explosive pressures of massive volcanic eruptions' — implying volcanic processes could account for these features. If it were proved that tektites cannot be produced by volcanic activity, this would eliminate Scientist 2's ability to explain the tektites' presence using volcanism. Simultaneously, it would confirm that only an impact of the type Scientist 1 describes could produce them — directly supporting Scientist 1. B is wrong — this finding removes one of Scientist 2's key explanatory tools. C is wrong — the finding does not weaken Scientist 1; it removes an alternative explanation for the physical evidence. D is wrong because both scientists reference tektites and the finding directly affects their explanatory power.
Question 20
A food scientist tested the hypothesis that higher oven temperature shortens cookie baking time. She baked identical cookie dough balls (20 g each) on the same metal tray lined with the same parchment paper. She used three oven settings: 160∘C, 180∘C, and 200∘C. For each temperature, she timed how long it took for the cookie edges to turn golden brown, using the same oven rack position and the same stopwatch. Which variable was held constant?
- Time until edges turn golden brown
- Oven temperature setting
- Mass of each dough ball (20 g) (correct answer)
- Baking time recorded for each trial
Explanation: In this experiment, the independent variable is the oven temperature setting, the dependent variable is the time until the cookie edges turn golden brown, and controlled variables include the mass of each dough ball, tray type, parchment paper, oven rack position, and stopwatch. The independent variable is adjusted by the experimenter to study its influence, the dependent variable is timed as the resulting effect, and controlled variables are kept the same to ensure the test is fair. Choice C correctly identifies the mass of each dough ball as held constant at 20 g, making it a controlled variable to isolate temperature's effect on baking time. Choice B is the independent variable, as oven temperatures were varied (160°C, 180°C, 200°C), not held constant.
Question 21
PASSAGE VI
PHYSICS: This passage is adapted from a study on the forces acting on an object on an inclined plane.
Introduction
A student conducted experiments to determine the factors that affect the force required to pull a block up an inclined plane at a constant velocity. The force (F) required depends on the mass of the block (m), the angle of the incline (θ), and the friction between the block and the surface.
The experimental setup consisted of a wooden board (the inclined plane) and a spring scale attached to a rectangular block. The student pulled the block up the incline at a steady speed and recorded the force in Newtons (N).
Study 1
To test how the angle of the incline affects the force, the student used a standard wooden block with a mass of 1.0 kg. The surface of the inclined plane was smooth wood. The student varied the angle of the incline from 10° to 60°. Results were recorded in Table 1.
Study 2
To test how the surface material (friction) affects the force, the student fixed the angle of the incline at 30° and used the same 1.0 kg block. The student covered the wooden board with different materials: Sandpaper, Rubber, and Plastic. The force was measured for each surface. Results were recorded in Table 2.
Study 3
To test how the mass of the block affects the force, the student used the smooth wood surface and fixed the angle at 30°. The student added weights to the block to increase its total mass. Results were recorded in Table 3.
In Study 1, the independent variable (the factor intentionally changed by the student) was:
- the mass of the block.
- the angle of the incline. (correct answer)
- the force measured by the spring scale.
- the surface material.
Explanation: This is an experimental design question about variables. The independent variable is what the experimenter deliberately manipulates to see its effect. Study 1's procedure states: "The student varied the angle of the incline from 10° to 60°." This shows the angle was intentionally changed across trials. Choice B is correct. Choice A (mass) was kept constant at 1.0 kg in Study 1. Choice C (force) is the dependent variable being measured, not manipulated. Choice D (surface material) was kept constant (smooth wood) in Study 1. Pro tip: Independent variables are described with words like "varied," "changed," or "tested." Dependent variables are "measured" or "recorded."
Question 22
A robotics team tested how battery voltage affects motor speed. They measured the motor’s rotational speed after 30 seconds of operation at each voltage setting.
Comparing Trial 2 and Trial 4, which variable increased?
- Voltage increased, but speed decreased.
- Speed increased, but voltage decreased.
- Both voltage and speed increased. (correct answer)
- Neither voltage nor speed increased.
Explanation: Both voltage and speed increased when comparing Trial 2 and Trial 4. In Table 1, compare the voltage and speed values between these two trials: voltage increased from one value to a higher value, and speed also increased correspondingly. This demonstrates the direct relationship between applied voltage and motor rotational speed.
Question 23
Student X claims that the internet is the primary driver of globalization. Student Y believes it's international trade. On which point would Student X and Student Y most likely disagree?
- Existence of globalization.
- Importance of global markets.
- Role of international communication.
- Primary driver of globalization. (correct answer)
Explanation: Student X and Student Y would most likely disagree on the primary driver of globalization. Student X 'claims that the internet is the primary driver of globalization,' emphasizing digital communication and connectivity. Student Y 'believes it's international trade,' focusing on economic exchange and commerce as the main globalizing force. This represents a fundamental disagreement about whether technological communication or economic activity is the dominant factor in creating global interconnectedness.
Question 24
A class compared the electrical resistance of wires of different lengths. Procedure: (1) Cut copper wire into lengths of 10 cm, 20 cm, 30 cm, and 40 cm. (2) Measure each length with a ruler. (3) Connect each wire to a digital multimeter set to ohms, using alligator clips. (4) Record resistance and plot resistance vs. length. The alligator clips sometimes gripped oxidized sections of wire; students did not sand the wire ends. The ruler had millimeter marks, and most students estimated to the nearest millimeter. Expected pattern: resistance increases linearly with length. Which procedural error would have the greatest effect on the results?
- Estimating wire length to the nearest millimeter, causing only small random length errors relative to 10–40 cm.
- Using copper wire, which prevents resistance from changing with length due to copper’s constant resistivity.
- Clipping onto oxidized wire, adding contact resistance that can vary and distort the resistance-length relationship. (correct answer)
- Plotting resistance versus length, which mathematically forces a linear relationship regardless of data.
Explanation: Clipping onto oxidized wire creates the most significant error source by adding variable contact resistance that distorts the resistance-length relationship. Wire oxidation creates an insulating layer that increases resistance at the connection points, and this contact resistance varies unpredictably between measurements depending on how much oxidation is present and how well the clips grip. This variable additional resistance can be substantial compared to the wire's inherent resistance, especially for shorter lengths, making it impossible to accurately determine the true relationship between wire length and resistance.
Question 25
Two scientists propose different mechanisms for the sudden extinction of dinosaurs. Scientist A suggests a massive asteroid impact, while Scientist B points to gradual volcanic activity. Fossil records show a sudden extinction event. Which hypothesis is more consistent with the fossil evidence?
- Neither hypothesis is consistent.
- Scientist B's hypothesis is more consistent.
- Both hypotheses are equally consistent.
- Scientist A's hypothesis is more consistent. (correct answer)
Explanation: Scientist A's hypothesis is more consistent with the fossil evidence because it correctly predicts sudden extinction events. The fossil records show a sudden extinction event, which aligns with Scientist A's asteroid impact hypothesis that would cause rapid, catastrophic changes. Scientist B's gradual volcanic activity hypothesis predicts gradual extinction patterns that contradict the observed sudden disappearance in the fossil record. The evidence specifically supports catastrophic rather than gradual extinction mechanisms.