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7th Grade Math Quiz

7th Grade Math Quiz: Solve Two Step Linear Equations

Practice Solve Two Step Linear Equations in 7th Grade Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

The perimeter of a rectangle is 84 inches. The length is 6 inches more than twice the width. What are the dimensions of the rectangle?

Select an answer to continue

What this quiz covers

This quiz focuses on Solve Two Step Linear Equations, giving you a quick way to practice the rules, question types, and explanations that matter most for 7th Grade Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

The perimeter of a rectangle is 84 inches. The length is 6 inches more than twice the width. What are the dimensions of the rectangle?

  1. Width = 10 inches, Length = 32 inches
  2. Width = 12 inches, Length = 30 inches (correct answer)
  3. Width = 14 inches, Length = 28 inches
  4. Width = 16 inches, Length = 26 inches

Explanation: Let www be the width. Then length = 2w+62w + 62w+6. Perimeter formula: 2w+2(2w+6)=842w + 2(2w + 6) = 842w+2(2w+6)=84. Simplifying: 2w+4w+12=842w + 4w + 12 = 842w+4w+12=84, so 6w=726w = 726w=72 and w=12w = 12w=12. Therefore length = 2(12)+6=302(12) + 6 = 302(12)+6=30. Check: 2(12)+2(30)=24+60=842(12) + 2(30) = 24 + 60 = 842(12)+2(30)=24+60=84 ✓. Choice A results from solving 2w+2w+6=842w + 2w + 6 = 842w+2w+6=84 (forgetting to double the length). Choice C uses incorrect coefficient setup. Choice D comes from arithmetic errors in solving the equation.

Question 2

The equation 4(2x−3)=6x+144(2x - 3) = 6x + 144(2x−3)=6x+14 represents a real-world situation where costs must be equal. After solving algebraically to get x=13x = 13x=13, which arithmetic verification correctly confirms this solution?

  1. Left side: 4(2⋅13−3)=4(20)=804(2 \cdot 13 - 3) = 4(20) = 804(2⋅13−3)=4(20)=80; Right side: 6⋅13+14=926 \cdot 13 + 14 = 926⋅13+14=92
  2. Left side: 4(2⋅13−3)=4(23)=924(2 \cdot 13 - 3) = 4(23) = 924(2⋅13−3)=4(23)=92; Right side: 6⋅13+14=866 \cdot 13 + 14 = 866⋅13+14=86
  3. Left side: 4(2⋅13−3)=4(26)=1044(2 \cdot 13 - 3) = 4(26) = 1044(2⋅13−3)=4(26)=104; Right side: 6⋅13+14=926 \cdot 13 + 14 = 926⋅13+14=92
  4. Left side: 4(2⋅13−3)=4(23)=924(2 \cdot 13 - 3) = 4(23) = 924(2⋅13−3)=4(23)=92; Right side: 6⋅13+14=926 \cdot 13 + 14 = 926⋅13+14=92 (correct answer)

Explanation: When you have an algebraic equation and need to verify a solution, you substitute the proposed value back into the original equation and check that both sides are equal. This confirmation step is crucial because it catches any algebraic errors you might have made while solving. To verify x=13x = 13x=13 in the equation 4(2x−3)=6x+144(2x - 3) = 6x + 144(2x−3)=6x+14, you need to carefully substitute 13 for xxx and evaluate each side separately. For the left side: 4(2x−3)=4(2⋅13−3)=4(26−3)=4(23)=924(2x - 3) = 4(2 \cdot 13 - 3) = 4(26 - 3) = 4(23) = 924(2x−3)=4(2⋅13−3)=4(26−3)=4(23)=92 For the right side: 6x+14=6⋅13+14=78+14=926x + 14 = 6 \cdot 13 + 14 = 78 + 14 = 926x+14=6⋅13+14=78+14=92 Since both sides equal 92, the solution x=13x = 13x=13 is correct. This matches answer choice D. Looking at the wrong answers: Choice A makes an order of operations error on the left side, calculating 2⋅13−32 \cdot 13 - 32⋅13−3 as 20 instead of 23, leading to 80 instead of 92. Choice B correctly calculates the left side as 92 but makes an arithmetic error on the right side, getting 86 instead of 92. Choice C makes a different error on the left side, somehow getting 26 instead of 23 inside the parentheses. Remember: verification problems test your arithmetic precision more than your algebra skills. Work slowly through the order of operations, double-check your basic arithmetic, and make sure both sides of the equation give you the same final value.

Question 3

A science museum sells tickets for 999 each. There is also a one-time processing fee of 4.504.504.50 for the whole order. If the total cost was 58.5058.5058.50, how many tickets were bought?

  1. 666 tickets (correct answer)
  2. 555 tickets
  3. 777 tickets
  4. 545454 tickets

Explanation: This question tests solving two-step equations from word problems in the px+q=rpx + q = rpx+q=r form, where you multiply a variable by a coefficient and then add a constant, using inverse operations to isolate the variable. To solve px+q=rpx + q = rpx+q=r, first subtract qqq from both sides to isolate the variable term, for example, 9t+4.5=58.59t + 4.5 = 58.59t+4.5=58.5 becomes 9t=549t = 549t=54, then divide both sides by ppp to isolate the variable, so 9t/9=54/99t / 9 = 54 / 99t/9=54/9 gives t=6t = 6t=6; always verify by substituting back, like 9×6+4.5=54+4.5=58.59 \times 6 + 4.5 = 54 + 4.5 = 58.59×6+4.5=54+4.5=58.5, which checks out. For this specific problem, set up the equation from the context: 9t+4.5=58.59t + 4.5 = 58.59t+4.5=58.5, subtract 4.54.54.5 to get 9t=549t = 549t=54, divide by 999 to find t=6t = 6t=6, verify 9×6+4.5=58.59 \times 6 + 4.5 = 58.59×6+4.5=58.5, and interpret as 666 tickets bought. The correct two-step process yields t=6t = 6t=6, which is choice A. Common errors include dividing first (58.5/9=6.558.5 / 9 = 6.558.5/9=6.5, subtract 4.5=24.5 = 24.5=2 nonsense), arithmetic mistakes (54/9=554 / 9 = 554/9=5 wrongly), one-step only (58.5−4.5=5458.5 - 4.5 = 5458.5−4.5=54, forget divide), sign error (adding 4.54.54.5 instead), or setup wrong (4.5t+9=58.54.5t + 9 = 58.54.5t+9=58.5). Strategy: identify the equation form px+q=rpx + q = rpx+q=r from the context, apply inverse operations in reverse order (subtract then divide to undo add then multiply), maintain equality by doing the same to both sides, verify by substituting back to ensure it satisfies the equation and makes sense (666 tickets at 999 is 545454 plus 4.504.504.50 fee totals 58.5058.5058.50), and check reasonableness (total near 6×9+6 \times 9 +6×9+ small fee). Comparing to arithmetic, work backwards: 58.5−4.5=5458.5 - 4.5 = 5458.5−4.5=54, 54/9=654 / 9 = 654/9=6, same answer; algebra generalizes for any total; avoid mistakes like wrong order or stopping after one step.

Question 4

A taxi company charges 3.50forthefirstmileand3.50 for the first mile and 3.50forthefirstmileand2.25 for each additional mile. If the total fare for a trip was $25.75, which equation correctly represents this situation, and how many miles was the trip?

  1. 3.50+2.25x=25.753.50 + 2.25x = 25.753.50+2.25x=25.75; the trip was 9.9 miles total
  2. 3.50+2.25(x−1)=25.753.50 + 2.25(x - 1) = 25.753.50+2.25(x−1)=25.75; the trip was 10.9 miles total
  3. 3.50+2.25(x−1)=25.753.50 + 2.25(x - 1) = 25.753.50+2.25(x−1)=25.75; the trip was 11 miles total (correct answer)
  4. 3.50x+2.25(x−1)=25.753.50x + 2.25(x - 1) = 25.753.50x+2.25(x−1)=25.75; the trip was 6.2 miles total

Explanation: Since the first mile costs 3.50andadditionalmilescost3.50 and additional miles cost 3.50andadditionalmilescost2.25 each, if the total trip is xxx miles, there are (x−1)(x-1)(x−1) additional miles. The correct equation is 3.50+2.25(x−1)=25.753.50 + 2.25(x-1) = 25.753.50+2.25(x−1)=25.75. Solving: 2.25(x−1)=22.252.25(x-1) = 22.252.25(x−1)=22.25, so x−1=22.25÷2.25=9.89x-1 = 22.25 ÷ 2.25 = 9.89x−1=22.25÷2.25=9.89. Since distance must be a whole number of miles, x−1=10x-1 = 10x−1=10, giving x=11x = 11x=11 miles. Choice A uses the wrong equation structure. Choice B has the right equation but wrong calculation. Choice D incorrectly charges $3.50 per mile for all miles.

Question 5

A movie theater has two pricing options for groups. Option A charges 12perperson.OptionBchargesa12 per person. Option B charges a 12perperson.OptionBchargesa36 group fee plus $8 per person. For what group size do both options cost exactly the same amount?

  1. 8 people, with both options costing $96 total
  2. 9 people, with both options costing $108 total (correct answer)
  3. 10 people, with both options costing $120 total
  4. 11 people, with both options costing $132 total

Explanation: Let nnn be the number of people. Option A costs 12n12n12n and Option B costs 36+8n36 + 8n36+8n. Setting them equal: 12n=36+8n12n = 36 + 8n12n=36+8n, so 4n=364n = 364n=36 and n=9n = 9n=9. Check: Option A = 12(9)=10812(9) = 10812(9)=108 and Option B = 36+8(9)=36+72=10836 + 8(9) = 36 + 72 = 10836+8(9)=36+72=108. Both options cost exactly $108 for 9 people. The other choices show incorrect group sizes that don't result in equal costs.

Question 6

A bike rental costs 12perhourplusaone−time12 per hour plus a one-time 12perhourplusaone−time6 helmet fee. If the total cost was $78, how many hours did the bike rental last?

  1. 8 hours
  2. 5 hours
  3. 6 hours (correct answer)
  4. 7 hours

Explanation: This problem tests solving two-step equations from word problems in the form px+q=rpx + q = rpx+q=r, where we multiply the variable then add a constant, using inverse operations. The bike rental costs 12perhour(variablecost)plusa12 per hour (variable cost) plus a 12perhour(variablecost)plusa6 helmet fee (fixed cost), totaling 78,sowewrite78, so we write 78,sowewrite12h + 6 = 78wherehisthenumberofhours.Tosolve:(1)subtract6frombothsidestoisolatethevariableterm( where h is the number of hours. To solve: (1) subtract 6 from both sides to isolate the variable term (wherehisthenumberofhours.Tosolve:(1)subtract6frombothsidestoisolatethevariableterm(12h = 72),then(2)divideby12toisolateh(), then (2) divide by 12 to isolate h (),then(2)divideby12toisolateh(h = 72 ÷ 12 = 6).Therentallasted6hours.Commonerrorsinclude:stoppingafteronestep(getting72astheanswer),reversingoperations(dividingfirst:). The rental lasted 6 hours. Common errors include: stopping after one step (getting 72 as the answer), reversing operations (dividing first: ).Therentallasted6hours.Commonerrorsinclude:stoppingafteronestep(getting72astheanswer),reversingoperations(dividingfirst:78 ÷ 12 = 6.5,thensubtracting6=, then subtracting 6 = ,thensubtracting6=0.5),orarithmeticmistakes(), or arithmetic mistakes (),orarithmeticmistakes(72 ÷ 12 = 7).Strategy:identifytheequationformfromcontext(hourlyrate×hours+helmetfee=total),applyinverseoperationsinreverseorder(subtractthendivide),andverifybysubstitutingback(). Strategy: identify the equation form from context (hourly rate × hours + helmet fee = total), apply inverse operations in reverse order (subtract then divide), and verify by substituting back ().Strategy:identifytheequationformfromcontext(hourlyrate×hours+helmetfee=total),applyinverseoperationsinreverseorder(subtractthendivide),andverifybysubstitutingback(12 × 6 + 6 = 72 + 6 = 78 ✓$).

Question 7

A music app charges \3tostartanaccountandthento start an account and thentostartanaccountandthen$8eachmonth.Yourtotalcostwaseach month. Your total cost waseachmonth.Yourtotalcostwas$59$. How many months did you pay for?

  1. 888 months
  2. 777 months (correct answer)
  3. 565656 months
  4. 666 months

Explanation: This question tests solving two-step equations from word problems in the px + q = r form, where you multiply a variable by a coefficient and then add a constant, using inverse operations to isolate the variable. To solve px + q = r, first subtract q from both sides to isolate the variable term, for example, 8m + 3 = 59 becomes 8m = 56, then divide both sides by p to isolate the variable, so 8m / 8 = 56 / 8 gives m = 7; always verify by substituting back, like 8 × 7 + 3 = 56 + 3 = 59, which checks out. For this specific problem, set up the equation from the context: 8m + 3 = 59, subtract 3 to get 8m = 56, divide by 8 to find m = 7, verify 8 × 7 + 3 = 59, and interpret as 7 months of subscription. The correct two-step process yields m = 7, which is choice A. Common errors include one-step only (59 - 3 = 56, forgetting to divide so m = 56), operation order reversed (59 / 8 = 7.375, then subtract 3 ≈ 4.375 nonsense), sign error (adding 3 instead: 8m = 62), arithmetic mistake (56 / 8 = 8 wrongly), or setup wrong (3m + 8 = 59 reversing). Strategy: identify the equation form px + q = r from the context, apply inverse operations in reverse order (subtract then divide to undo add then multiply), maintain equality by doing the same to both sides, verify by substituting back to ensure it satisfies the equation and makes sense (7 months at 8is8 is 8is56 plus 3feetotals3 fee totals 3feetotals59), and check reasonableness (total around 7 × 8 + small fee). Comparing to arithmetic, work backwards: 59 - 3 = 56, 56 / 8 = 7, same answer; algebra generalizes for any total; avoid mistakes like stopping after one step or wrong order.

Question 8

A school fundraiser sells tubs of cookie dough for \8.75each.Theclubalsopaysaone−timeboothrentalfeeofeach. The club also pays a one-time booth rental fee ofeach.Theclubalsopaysaone−timeboothrentalfeeof$10.00.Ifthetotalcostwas. If the total cost was .Ifthetotalcostwas$80.00,howmanytubsdidtheybuy?Solve, how many tubs did they buy? Solve ,howmanytubsdidtheybuy?Solve8.75x+10=80$.

  1. x=70x=70x=70
  2. x=8x=8x=8 (correct answer)
  3. x=9x=9x=9
  4. x=6x=6x=6

Explanation: This question tests solving two-step equations from word problems in the px + q = r form, where you multiply a variable by a coefficient and then add a constant, using inverse operations to isolate the variable. To solve px + q = r, first subtract q from both sides to isolate the variable term, for example, 8.75x + 10 = 80 becomes 8.75x = 70, then divide both sides by p to isolate the variable, so 8.75x ÷ 8.75 = 70 ÷ 8.75 gives x = 8; for the other form p(x + q) = r, divide by p first then subtract q, and always verify by substituting back, like 8.75 × 8 + 10 = 70 + 10 = 80, which checks out in the context of cookie dough tubs at 8.75eachplus8.75 each plus 8.75eachplus10 fee totaling 80forxtubs.Forthisspecificproblem,theequationisgivenas8.75x+10=80,subtract10toget8.75x=70,divideby8.75tofindx=8,verify8.75×8+10=80,andinterpretas8tubsbought.Thecorrecttwo−stepprocessyieldsx=8,whichischoiceA.Commonerrorsincludesubtractingonlyandforgettingtodivide(x=70,choiceC),reversingorderbydividingfirst(80÷8.75≈9.14thensubtract10,nonsensical),signerrorslikeaddinginstead(8.75x=90),arithmeticmistakes(70÷8.75=9or6),orwrongsetupthoughit′sprovided.Strategytipsincludeidentifyingthepx+q=rformfromper−tubcostplusfixedfee,applyinginverseoperationsinreverse(subtractthendivide),maintainingequalitybydoingthesametobothsides,verifyingbysubstitutionandcontextsense(8tubsat80 for x tubs. For this specific problem, the equation is given as 8.75x + 10 = 80, subtract 10 to get 8.75x = 70, divide by 8.75 to find x = 8, verify 8.75 × 8 + 10 = 80, and interpret as 8 tubs bought. The correct two-step process yields x = 8, which is choice A. Common errors include subtracting only and forgetting to divide (x = 70, choice C), reversing order by dividing first (80 ÷ 8.75 ≈ 9.14 then subtract 10, nonsensical), sign errors like adding instead (8.75x = 90), arithmetic mistakes (70 ÷ 8.75 = 9 or 6), or wrong setup though it's provided. Strategy tips include identifying the px + q = r form from per-tub cost plus fixed fee, applying inverse operations in reverse (subtract then divide), maintaining equality by doing the same to both sides, verifying by substitution and context sense (8 tubs at 80forxtubs.Forthisspecificproblem,theequationisgivenas8.75x+10=80,subtract10toget8.75x=70,divideby8.75tofindx=8,verify8.75×8+10=80,andinterpretas8tubsbought.Thecorrecttwo−stepprocessyieldsx=8,whichischoiceA.Commonerrorsincludesubtractingonlyandforgettingtodivide(x=70,choiceC),reversingorderbydividingfirst(80÷8.75≈9.14thensubtract10,nonsensical),signerrorslikeaddinginstead(8.75x=90),arithmeticmistakes(70÷8.75=9or6),orwrongsetupthoughit′sprovided.Strategytipsincludeidentifyingthepx+q=rformfromper−tubcostplusfixedfee,applyinginverseoperationsinreverse(subtractthendivide),maintainingequalitybydoingthesametobothsides,verifyingbysubstitutionandcontextsense(8tubsat8.75 is 70plus70 plus 70plus10 totals $80, reasonable), and checking reasonableness. Compared to arithmetic working backwards (80 - 10 = 70, 70 ÷ 8.75 = 8), algebra generalizes for any total; avoid mistakes like stopping after one step, wrong order, sign errors, or mismatched setup.

Question 9

Verify a solution: A tutoring session costs 18perhourplusa18 per hour plus a 18perhourplusa6 materials fee. The total bill was $78. Which value of h correctly solves 18h+6=78 and fits the situation?

  1. h=4 (correct answer)
  2. h=7/2
  3. h=3
  4. h=13/3

Explanation: Subtracting 6 from both sides of 18h + 6 = 78 gives 18h = 72, and dividing by 18 gives h = 4, matching choice A. Checking: 18 x 4 + 6 = 72 + 6 = 78, which fits the situation of 4 hours tutored. Choices B, C, and D don't satisfy the equation: substituting each back in gives totals of 69,69, 69,60, and 84insteadoftherequired84 instead of the required 84insteadoftherequired78.

Question 10

Compare methods: A streaming service charges 9.75permonthplusaone−time9.75 per month plus a one-time 9.75permonthplusaone−time4.50 fee. The total paid was $53.25. How many months were paid for? (You could solve algebraically or by working backward.)

  1. 7 months
  2. 6 months
  3. 4 months
  4. 5 months (correct answer)

Explanation: This problem tests solving two-step equations from word problems in the form px+q=rpx + q = rpx+q=r, where we multiply the variable then add a constant, using inverse operations. The streaming service costs 9.75permonth(variablecost)plusa9.75 per month (variable cost) plus a 9.75permonth(variablecost)plusa4.50 fee (fixed cost), totaling 53.25,sowewrite53.25, so we write 53.25,sowewrite9.75m + 4.50 = 53.25wheremisthenumberofmonths.Tosolvealgebraically:(1)subtract4.50frombothsides( where m is the number of months. To solve algebraically: (1) subtract 4.50 from both sides (wheremisthenumberofmonths.Tosolvealgebraically:(1)subtract4.50frombothsides(9.75m = 48.75),then(2)divideby9.75(), then (2) divide by 9.75 (),then(2)divideby9.75(m = 48.75 ÷ 9.75 = 5).Workingbackwardgivesthesameresult:). Working backward gives the same result: ).Workingbackwardgivesthesameresult:$53.25 - $4.50 = $48.75,then, then ,then$48.75 ÷ $9.75 = 5$ months. Common errors include: stopping after one step, reversing operations, or arithmetic mistakes with decimals. Both methods—algebraic equation solving and working backward—yield 5 months, demonstrating that algebra generalizes the arithmetic approach of undoing operations in reverse order.

Question 11

A class is making gift bags. Each bag needs 333 stickers, and the teacher adds 555 extra stickers for mistakes. If there are 474747 stickers total, how many gift bags can be made? (Model with 3x+5=473x+5=473x+5=47.)

  1. x=16x=16x=16
  2. x=42x=42x=42
  3. x=12x=12x=12
  4. x=14x=14x=14 (correct answer)

Explanation: This question tests solving two-step equations from word problems in the px + q = r form, where you multiply a variable by a coefficient and then add a constant, using inverse operations to isolate the variable. To solve px + q = r, first subtract q from both sides to isolate the variable term, for example, 3x + 5 = 47 becomes 3x = 42, then divide both sides by p to isolate the variable, so 3x / 3 = 42 / 3 gives x = 14; always verify by substituting back, like 3 × 14 + 5 = 42 + 5 = 47, which checks out. For this specific problem, use the given model 3x + 5 = 47, subtract 5 to get 3x = 42, divide by 3 to find x = 14, verify 3 × 14 + 5 = 47, and interpret as 14 gift bags can be made. The correct two-step process yields x = 14, which is choice A. Common errors include dividing first (47 / 3 ≈ 15.667, subtract 5 ≈ 10.667 nonsense), arithmetic mistakes (42 / 3 = 12 or 16 wrongly), one-step only (47 - 5 = 42, forget divide), sign error (3x = 52 by adding), or setup wrong (5x + 3 = 47). Strategy: identify the equation form px + q = r from the context, apply inverse operations in reverse order (subtract then divide to undo add then multiply), maintain equality by doing the same to both sides, verify by substituting back to ensure it satisfies the equation and makes sense (14 bags need 42 stickers plus 5 extra totals 47), and check reasonableness (total minus extra divisible by 3). Comparing to arithmetic, work backwards: 47 - 5 = 42, 42 / 3 = 14, same answer; algebra generalizes for any total; avoid mistakes like wrong order or miscalculation.

Question 12

Solve the equation 3(x+4)=273(x+4)=273(x+4)=27.

  1. x=5x=5x=5 (correct answer)
  2. x=13x=13x=13
  3. x=7x=7x=7
  4. x=3x=3x=3

Explanation: This question tests solving two-step equations in the p(x + q) = r form, where you multiply a grouped expression by a coefficient, using inverse operations to isolate the variable. To solve p(x + q) = r, first divide both sides by p to isolate the grouped term, for example, 3(x + 4) = 27 becomes x + 4 = 9, then subtract q from both sides to isolate the variable, so x = 9 - 4 = 5; always verify by substituting back, like 3(5 + 4) = 3 × 9 = 27, which checks out. For this specific problem, start with 3(x + 4) = 27, divide by 3 to get x + 4 = 9, subtract 4 to find x = 5, and verify 3(5 + 4) = 27. The correct two-step process yields x = 5, which is choice A. Common errors include distributing wrongly (3x + 4 = 27, then mistakes), order reversed (subtract 4 from 27 = 23, divide by 3 ≈ 7.67 nonsense), arithmetic error (27 / 3 = 8, 8 - 4 = 4), or expanding incorrectly (3x + 12 = 27). Strategy: identify the equation form p(x + q) = r, apply inverse operations in reverse order (divide then subtract to undo multiply after add), maintain equality by doing the same to both sides, verify by substituting back to ensure it satisfies the equation, and check reasonableness (5 + 4 = 9, times 3 is 27). Comparing to arithmetic, work backwards: 27 / 3 = 9, 9 - 4 = 5, same answer; algebra generalizes for any right side; avoid mistakes like wrong order or distribution errors.

Question 13

A water bottle costs \3.25andthereisafixedtaxofand there is a fixed tax ofandthereisafixedtaxof$1.50addedtothetotalpurchase.Ifthetotalcostwasadded to the total purchase. If the total cost wasaddedtothetotalpurchase.Ifthetotalcostwas$27.50,howmanywaterbottleswerebought?Setupandsolve, how many water bottles were bought? Set up and solve ,howmanywaterbottleswerebought?Setupandsolve3.25b+1.50=27.50$.

  1. b=8b=8b=8 (correct answer)
  2. b=26b=26b=26
  3. b=7b=7b=7
  4. b=9b=9b=9

Explanation: This question tests solving two-step equations from word problems in the px+q=rpx + q = rpx+q=r form, where you multiply a variable by a coefficient and then add a constant, using inverse operations to isolate the variable. To solve px+q=rpx + q = rpx+q=r, first subtract qqq from both sides to isolate the variable term, for example, 3.25b+1.5=27.53.25b + 1.5 = 27.53.25b+1.5=27.5 becomes 3.25b=263.25b = 263.25b=26, then divide both sides by ppp to isolate the variable, so 3.25b÷3.25=26÷3.253.25b \div 3.25 = 26 \div 3.253.25b÷3.25=26÷3.25 gives b=8b = 8b=8; for the other form p(x+q)=rp(x + q) = rp(x+q)=r, divide by ppp first then subtract qqq, and always verify by substituting back, like 3.25×8+1.5=26+1.5=27.53.25 \times 8 + 1.5 = 26 + 1.5 = 27.53.25×8+1.5=26+1.5=27.5, which checks out in the context of water bottles at 3.253.253.25 each plus 1.501.501.50 tax totaling 27.5027.5027.50 for bbb bottles. For this specific problem, the equation is given as 3.25b+1.5=27.53.25b + 1.5 = 27.53.25b+1.5=27.5, subtract 1.51.51.5 to get 3.25b=263.25b = 263.25b=26, divide by 3.253.253.25 to find b=8b = 8b=8, verify 3.25×8+1.5=27.53.25 \times 8 + 1.5 = 27.53.25×8+1.5=27.5, and interpret as 888 water bottles bought. The correct two-step process yields b=8b = 8b=8, which is choice A. Common errors include subtracting only and forgetting to divide (b=26b = 26b=26, choice D), reversing order by dividing first (27.5÷3.25≈8.4627.5 \div 3.25 \approx 8.4627.5÷3.25≈8.46 then subtract 1.51.51.5, nonsensical), sign errors like adding instead (3.25b=293.25b = 293.25b=29), arithmetic mistakes (26÷3.25=926 \div 3.25 = 926÷3.25=9 or 777), or wrong setup though it's provided. Strategy tips include identifying the px+q=rpx + q = rpx+q=r form from per-bottle cost plus fixed tax, applying inverse operations in reverse (subtract then divide), maintaining equality by doing the same to both sides, verifying by substitution and context sense (888 bottles at 3.253.253.25 is 262626 plus 1.501.501.50 totals 27.5027.5027.50, reasonable), and checking reasonableness. Compared to arithmetic working backwards (27.5−1.5=2627.5 - 1.5 = 2627.5−1.5=26, 26÷3.25=826 \div 3.25 = 826÷3.25=8), algebra generalizes for any total; avoid mistakes like stopping after one step, wrong order, sign errors, or mismatched setup.

Question 14

A streaming app charges 7.50permonthplusaone−timesign−upfeeof7.50 per month plus a one-time sign-up fee of 7.50permonthplusaone−timesign−upfeeof4.50. If Maya paid a total of $49.50, how many months did she pay for? Write and solve an equation of the form px+q=r.

  1. m=6.6
  2. m=5
  3. m=6 (correct answer)
  4. m=7

Explanation: The equation is 7.5m + 4.5 = 49.5. Subtracting 4.5 from both sides gives 7.5m = 45, and dividing by 7.5 gives m = 6, matching choice C. Checking: 7.5 x 6 + 4.5 = 45 + 4.5 = 49.5, which fits the context of 6 months of subscription. Choice A (6.6) comes from dividing 49.5 by 7.5 first instead of subtracting the fee, and choices B and D don't satisfy the equation when substituted back in.

Question 15

A hobby store sells refill packs for 5each.Asciencekitcomeswithsomenumberofpaidrefillpacks,plus2bonuspacksaddedforfree.Thekit′stotaladvertisedvalue,treatingallpacks(paidandbonus)at5 each. A science kit comes with some number of paid refill packs, plus 2 bonus packs added for free. The kit's total advertised value, treating all packs (paid and bonus) at 5each.Asciencekitcomeswithsomenumberofpaidrefillpacks,plus2bonuspacksaddedforfree.Thekit′stotaladvertisedvalue,treatingallpacks(paidandbonus)at5 each, is 45.If45. If 45.Ifprepresentsthenumberofpaidrefillpacks,thiscanbemodeledbyrepresents the number of paid refill packs, this can be modeled byrepresentsthenumberofpaidrefillpacks,thiscanbemodeledby5(p+2)=45.Solvefor. Solve for .Solveforp$.

  1. p=9p=9p=9
  2. p=7p=7p=7 (correct answer)
  3. p=11p=11p=11
  4. p=5p=5p=5

Explanation: To solve 5(p+2)=45, first divide both sides by 5: p+2=9. Then subtract 2 from both sides: p=7, matching choice B. Verify: 5(7+2)=5x9=45, which checks out. Choice A stops after dividing but forgets to subtract 2, leaving p+2's value (9) as the final answer. Choice C divides 45 by 5 to get 9, then adds 2 instead of subtracting, giving 11. Choice D makes an arithmetic error, subtracting incorrectly to arrive at 5.

Question 16

A class is making snack bags. Each bag has the same number of pretzels. After making 6 bags, there are 3 pretzels left over, and the class started with 51 pretzels. Let xxx be the number of pretzels in each bag. Which equation matches the situation, and what is xxx?

(Equation form: px+q=rpx+q=rpx+q=r)

  1. 6x−3=516x-3=516x−3=51, so x=9x=9x=9
  2. 3x+6=513x+6=513x+6=51, so x=15x=15x=15
  3. 51x+3=651x+3=651x+3=6, so x=117x=\tfrac{1}{17}x=171​
  4. 6x+3=516x+3=516x+3=51, so x=8x=8x=8 (correct answer)

Explanation: This problem tests solving two-step equations from word problems in the form px+q=r, where we multiply the variable then add a constant, using inverse operations. The class makes 6 bags with x pretzels each (6x total) plus 3 leftover pretzels equals 51 total pretzels, giving equation 6x + 3 = 51. To solve: (1) subtract 3 from both sides to isolate the variable term (6x = 48), then (2) divide by 6 to isolate x (x = 48 ÷ 6 = 8). Each bag has 8 pretzels, matching answer choice A. Common errors include: reversing the equation setup (51x + 3 = 6 as in choice C), swapping coefficients (3x + 6 = 51 as in choice D), or using subtraction instead of addition for leftovers (6x - 3 = 51 as in choice B). Strategy: identify what's multiplied (bags × pretzels per bag) and what's added (leftovers), set up equation matching the context, apply inverse operations, and verify (6×8+3=48+3=51✓).

Question 17

A movie theater sells a snack combo for 6.25each,plusaone−timeonlineorderfeeof6.25 each, plus a one-time online order fee of 6.25each,plusaone−timeonlineorderfeeof2.50. If the total was 40,howmanycomboswereordered?Writeandsolveanequationoftheform40, how many combos were ordered? Write and solve an equation of the form 40,howmanycomboswereordered?Writeandsolveanequationoftheformpx+q=r$.

  1. 6.25 combos
  2. 6 combos (correct answer)
  3. 5 combos
  4. 8 combos

Explanation: The equation for this situation is 6.25x + 2.5 = 40, where x is the number of combos. Subtracting 2.5 from both sides gives 6.25x = 37.5, and dividing both sides by 6.25 gives x = 6. Checking: 6.25(6) + 2.5 = 37.5 + 2.5 = 40, which matches. Choice A mistakes the price per combo for the number of combos. Choice C comes from an arithmetic slip when dividing 37.5 by 6.25. Choice D comes from dividing the total by the price per combo first, 40/6.25 = 6.4, without properly subtracting the fee first.

Question 18

At a sports store, each item costs \4.Youarebuyingoneidenticalitemforeachofyourfriends,plus2extraitemsforyourselfandabackup.Ifthetotalcostwas. You are buying one identical item for each of your friends, plus 2 extra items for yourself and a backup. If the total cost was .Youarebuyingoneidenticalitemforeachofyourfriends,plus2extraitemsforyourselfandabackup.Ifthetotalcostwas$36$, how many friends were you shopping for?

  1. 777 friends (correct answer)
  2. 999 friends
  3. 111111 friends
  4. 555 friends

Explanation: Since you're buying one item for each friend plus 2 extra items for yourself and a backup, the total number of items is x + 2, where x is the number of friends. The equation for the total cost is 4(x + 2) = 36. Dividing both sides by 4 gives x + 2 = 9, and subtracting 2 gives x = 7. Checking: 4(7 + 2) = 4(9) = 36, which matches. Choice B comes from stopping after finding the total number of items, 9, without subtracting the 2 extra. Choice C and choice D come from errors in the order of the division and subtraction steps.

Question 19

A craft store sells beads in packs. Each pack costs 3.25,andthereisa3.25, and there is a 3.25,andthereisa5.50 shipping fee for the entire order. If the total was $31.50, how many packs did Lee buy? Write an equation and solve.

  1. 12 packs
  2. 10 packs
  3. 9 packs
  4. 8 packs (correct answer)

Explanation: The situation can be written as the equation 3.25p + 5.50 = 31.50, where p is the number of packs. Subtracting 5.50 from both sides gives 3.25p = 26.00, and dividing both sides by 3.25, the cost per pack, gives p = 8, matching Choice D. Choice A, 12 packs, and Choice B, 10 packs, do not satisfy the equation when checked. Choice C, 9 packs, is close but does not check out either, since 3.25 x 9 + 5.50 = 34.75, not 31.50. Checking the answer, 3.25 x 8 + 5.50 = 26.00 + 5.50 = 31.50, which confirms 8 packs is correct.

Question 20

Compare methods: A student says the equation for this situation is 7x+2=447x+2=447x+2=44: “Each notebook costs \7,andthereisa, and there is a ,andthereisa$2feeforthewholepurchase.Thetotalwasfee for the whole purchase. The total wasfeeforthewholepurchase.Thetotalwas$44$.” What is the correct number of notebooks?

  1. x=7x=7x=7
  2. x=42x=42x=42
  3. x=5x=5x=5
  4. x=6x=6x=6 (correct answer)

Explanation: Starting with the equation 7x plus 2 equals 44, subtracting 2 from both sides gives 7x equals 42, and dividing both sides by 7 gives x equals 6, matching choice D. Choice A, x equals 7, does not satisfy the equation, since 7 times 7 plus 2 equals 51, not 44. Choice B, x equals 42, comes from stopping after subtracting 2 and forgetting to divide by 7. Choice C, x equals 5, comes from an arithmetic slip when dividing 42 by 7. Checking the answer by substitution, 7 times 6 plus 2 equals 42 plus 2, which equals 44, confirms that x equals 6 is correct.