6th Grade Math Quiz: Write And Represent Simple Inequalities
20 questions · exam conditions
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Write And Represent Simple InequalitiesQuestion 1 of 20

A library lets you check out a maximum of 6 books at a time. Let bb be the number of books you check out. Which inequality represents this limit?

b>6b>6
b6b\ge 6
b6b\le 6
b<6b<6
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6th Grade Math Quiz

6th Grade Math Quiz: Write And Represent Simple Inequalities

Practice Write And Represent Simple Inequalities in 6th Grade Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Write And Represent Simple Inequalities, giving you a quick way to practice the rules, question types, and explanations that matter most for 6th Grade Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A library lets you check out a maximum of 6 books at a time. Let bb be the number of books you check out. Which inequality represents this limit?

  1. b>6b>6
  2. b6b\ge 6
  3. b6b\le 6 (correct answer)
  4. b<6b<6
Explanation: This question is about turning words into an inequality. The key word here is "maximum," which means the most you can have. Let's think about what numbers work. You can check out 6 books, since 6 is allowed. You can also check out fewer, like 5, 4, or even 0. But you can't go over 6. So bb can be 6 or anything less than 6. The symbol that means "less than or equal to" is \le. That gives us:
b6b \le 6
Here's a way to picture it: imagine a backpack that holds up to 6 water bottles. Six fits perfectly, and fewer fits too — but a 7th bottle won't squeeze in! Try this at home: Find a "maximum" rule around you, like "snack box holds at most 4 cookies." Write it as an inequality using \le. You've got this!

Question 2

An elevator has a weight limit. The sign reads "Maximum capacity: 2000 pounds." If the elevator currently has 1650 pounds of weight, how much additional weight ww can be added?

  1. w<350w < 350 because the additional weight must be strictly less than 350 pounds
  2. w350w \leq 350 because the total weight cannot exceed the maximum capacity (correct answer)
  3. w>350w > 350 because more than 350 pounds can safely be added
  4. w350w \geq 350 because at least 350 pounds of space remains available
Explanation: Current weight is 1650 pounds, maximum is 2000 pounds, so additional weight plus current weight cannot exceed 2000: 1650+w20001650 + w ≤ 2000, which gives w350w ≤ 350. Choice A uses strict inequality, but exactly 350 pounds additional would reach exactly the maximum (allowed). Choices C and D suggest more than 350 pounds can be added, which would exceed the limit.

Question 3

Jordan is buying snacks and wants to spend at most $50. Let $x$ be the total cost (in dollars). Which inequality represents this situation?

  1. x50x\ge 50
  2. x>50x>50
  3. x<50x<50
  4. x50x\le 50 (correct answer)
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding that they have infinitely many solutions, and representing them on number lines with proper boundary markers (● for included, ○ for excluded) and shading. Constraint words translate to symbols: 'at least' means ≥ (includes boundary, like x ≥ 10 allows 10 or more), 'at most' means ≤ (includes, like x ≤ 50 allows 50 or less), 'more than' means > (excludes), 'less than' means < (excludes); inequalities have infinite solutions unlike equations, and on a number line, use closed ● for ≥/≤, open ○ for >/<, shading right for greater and left for lesser. For example, 'score more than 75' gives x > 75 with solutions like 76, 77, ... infinitely many, graphed as ○ at 75 shaded right. The correct inequality is x ≤ 50, as 'at most 50' includes up to 50. A common error is using < instead of ≤, excluding 50, or reversing to ≥ thinking of minimum. To write it: (1) identify 'at most' as ≤, (2) translate to x ≤ 50. Infinite solutions: all reals ≤ 50; mistakes include confusing at most with more than or wrong symbol.

Question 4

A runner wants to finish a mile in less than 9 minutes. Let tt be the time (in minutes). Which graph shows the solution set for this rule?

  1. t<9t<9; open circle at 9 and shading to the left (correct answer)
  2. t9t\ge 9; closed circle at 9 and shading to the right
  3. t>9t>9; open circle at 9 and shading to the right
  4. t9t\le 9; closed circle at 9 and shading to the left
Explanation: This question tests graphing inequalities like t < c from real-world constraints, understanding infinite solutions, with open circles ○ for exclusive and shading left for lesser values. Constraint words: 'less than' → < (excludes: t < 9 below 9), 'at most' → ≤ (includes), 'more than' → >, 'at least' → ≥; infinite solutions as t < 9 has all numbers less than 9 forever downward. Example: 'finish in less than 9 minutes' → t < 9, solutions: 8.9, 8, ..., infinite, graph: open ○ at 9 shaded left (<======○). The correct graph is t < 9 with open circle at 9 and shading left, matching choice B. Common error: using closed ● for < instead of ○, or shading right, or thinking only one solution like t=8. Graphing: (1) draw line, (2) mark 9, (3) open ○ for <, (4) shade left; writing: (1) identify 'less than,' (2) to <, (3) t < 9. Infinite solutions: all reals <9; context: times below 9 work; mistakes: circle type wrong, shade backward, finite solutions claim.

Question 5

A movie theater has a rule: "Children's tickets cost $8, and you can buy at most $40 worth of children's tickets." Let $x$ be the total amount spent (in dollars) on children's tickets. Which option correctly gives the inequality and a correct interpretation of its solutions?

  1. x>40x>40; you may spend more than $40 only.
  2. x40x\ge 40; you must spend $40 or more.
  3. x40x\le 40; any amount up to and including $40 works (infinitely many possible dollar amounts). (correct answer)
  4. x<40x<40; you may spend any amount under $40 but not $40.
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding that they have infinitely many solutions, and representing them on number lines with proper boundary markers (● for included, ○ for excluded) and shading. Constraint words translate to symbols: 'at least' means ≥ (includes), 'at most' means ≤ (includes boundary, like x ≤ 40 allows 40 or less), 'more than' means > (excludes), 'less than' means < (excludes); inequalities have infinite solutions unlike equations, and on a number line, use closed ● for ≥/≤, open ○ for >/<, shading right for greater and left for lesser. For example, 'at most 40' gives x ≤ 40 with infinite solutions up to 40. The correct is x ≤ 40 with interpretation of any amount up to including 40, infinitely many. A common error is using <, excluding 40. Infinite solutions: uncountably many reals ≤40. Mistakes: wrong symbol, not recognizing infinity.

Question 6

A 5K fun run asks runners to finish in less than 60 minutes to earn a ribbon. Let xx be the finishing time in minutes. Which inequality represents this?

  1. x<60x<60 (correct answer)
  2. x>60x>60
  3. x60x\ge 60
  4. x60x\le 60
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding infinitely many solutions, and representing on number lines with proper boundary markers (●/○) and shading. Constraint words translate to symbols: 'at least' → ≥ (includes boundary: x ≥ 10 means 10 or more), 'at most' → ≤ (includes: x ≤ 50 means 50 or less), 'more than' → > (excludes boundary: x > 75 means above 75, not including 75), 'less than' → < (excludes: x < 60 below 60); inequalities have infinitely many solutions (x > 10 includes 11, 12, 13, ..., 1000, ...—continues forever, unlike equations with one solution); on a number line, mark boundary at c (for x > 10, mark 10), use closed ● if ≥ or ≤ (includes), open ○ if > or < (excludes), shade right for > / ≥ (greater values), left for < / ≤ (lesser values). For example, 'must have at least 10 tickets' → x ≥ 10 (x = tickets, 10 or more), solutions: 10, 11, 12, ... infinitely many (all non-negative integers ≥ 10), graph: ● at 10 shaded right (●======> ), includes 10 and all greater; or 'score more than 75' → x > 75 (above 75, excludes 75), graph: ○======> at 75 (open circle, shade right), solutions: 76, 77, 78, ... infinite. The correct inequality is x < 60, matching choice B, for finishing in less than 60 minutes, excluding 60. Errors include using ≤ (choice A, including 60), or reversing to ≥ or > (choices C and D, for more time). To write: (1) identify 'less than' as excluding boundary, (2) translate to <, (3) write x < 60. This has infinitely many solutions, all reals < 60; mistakes often confuse < with ≤ or reverse the inequality.

Question 7

A snack bar has a sign: "Buy more than 6 bottles of water to get a discount." Let xx be the number of bottles you buy. Which description correctly explains why the inequality has infinitely many solutions?

  1. Because x>6x>6 has no solutions since you cannot buy more than 6 bottles.
  2. Because x>6x>6 is true for exactly 6 values of xx.
  3. Because x>6x>6 is true for x=7,8,9,10,x=7,8,9,10,\dots, and there is no largest number of bottles you could buy. (correct answer)
  4. Because x>6x>6 is true only for x=7x=7, so there is one solution.
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding infinitely many solutions, and representing on number lines with proper boundary markers (●/○) and shading. Constraint words translate to symbols: 'at least' → ≥ (includes boundary: x ≥ 10 means 10 or more), 'at most' → ≤ (includes: x ≤ 50 means 50 or less), 'more than' → > (excludes boundary: x > 75 means above 75, not including 75), 'less than' → < (excludes: x < 60 below 60); inequalities have infinitely many solutions (x > 10 includes 11, 12, 13, ..., 1000, ...—continues forever, unlike equations with one solution); on a number line, mark boundary at c (for x > 10, mark 10), use closed ● if ≥ or ≤ (includes), open ○ if > or < (excludes), shade right for > / ≥ (greater values), left for < / ≤ (lesser values). For example, 'must have at least 10 tickets' → x ≥ 10 (x = tickets, 10 or more), solutions: 10, 11, 12, ... infinitely many (all non-negative integers ≥ 10), graph: ● at 10 shaded right (●======> ), includes 10 and all greater; or 'score more than 75' → x > 75 (above 75, excludes 75), graph: ○======> at 75 (open circle, shade right), solutions: 76, 77, 78, ... infinite. The correct description is B, explaining x > 6 has infinitely many solutions like 7,8,9,... with no upper limit. Errors claim one solution (choice A), finite solutions (choice C), or no solutions (choice D). To understand: (1) identify 'more than' as >, (2) write x > 6, (3) recognize infinite integers > 6. Infinite solutions are uncountable in reals > 6; mistakes treat as finite or like equations.

Question 8

A water bottle holds no more than 20 ounces of water. Let ww be the amount of water (in ounces) in the bottle. Which inequality and graph description match the situation?

  1. w20w\le 20; closed circle at 20 and shading left (correct answer)
  2. w20w\ge 20; closed circle at 20 and shading right
  3. w>20w>20; open circle at 20 and shading right
  4. w<20w<20; open circle at 20 and shading left
Explanation: This question tests writing and graphing inequalities like w ≤ 20 from 'no more than,' with inclusive closed circle and left shading, infinite solutions. 'No more than' → ≤ includes (w ≤ 20: up to 20 ounces); infinite: all ≤20. Example: 'no more than 20' → w ≤ 20, graph: ● at 20 shaded left. Correct is w ≤ 20 with closed circle at 20 and shading left, matching choice B. Error: using <20 excluding 20, or shading right. Writing: (1) 'no more than' to ≤, (2) w ≤ 20; graphing: (1) line, (2) 20, (3) ●, (4) left. Context: 20 ounces is allowed; mistakes: symbol, direction.

Question 9

A movie is rated for ages 13 and up. Let aa be a person's age. Which statement best describes the solutions to the inequality for this rule?

  1. The inequality is a13a\ge 13, and it has infinitely many solutions: any age 13 or older. (correct answer)
  2. The inequality is a13a\le 13, and it has infinitely many solutions: any age 13 or younger.
  3. The inequality is a13a\ge 13, and it has exactly 13 solutions.
  4. The inequality is a>13a>13, and it has only one solution: a=14a=14.
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding infinitely many solutions, and representing on number lines with proper boundary markers (●/○) and shading. Constraint words translate to symbols: 'at least' → ≥ (includes boundary: x ≥ 10 means 10 or more), 'at most' → ≤ (includes: x ≤ 50 means 50 or less), 'more than' → > (excludes boundary: x > 75 means above 75, not including 75), 'less than' → < (excludes: x < 60 below 60); inequalities have infinitely many solutions (x > 10 includes 11, 12, 13, ..., 1000, ...—continues forever, unlike equations with one solution); on a number line, mark boundary at c (for x > 10, mark 10), use closed ● if ≥ or ≤ (includes), open ○ if > or < (excludes), shade right for > / ≥ (greater values), left for < / ≤ (lesser values). For example, 'must have at least 10 tickets' → x ≥ 10 (x = tickets, 10 or more), solutions: 10, 11, 12, ... infinitely many (all non-negative integers ≥ 10), graph: ● at 10 shaded right (●======> ), includes 10 and all greater; or 'score more than 75' → x > 75 (above 75, excludes 75), graph: ○======> at 75 (open circle, shade right), solutions: 76, 77, 78, ... infinite. The correct statement is B: a ≥ 13 with infinitely many solutions (any age 13 or older). Errors claim only one solution (choice A), reverse to ≤ (choice C), or say finite solutions (choice D). Context: 'at least 13' means 13, 14, 15, ... all valid (infinite possible ages). Mistakes include treating it like an equation or not recognizing infinity of solutions.

Question 10

The graph shows the solution to an inequality on a number line. Which inequality matches this representation?

  1. x4x \leq 4 because the circle is closed and shading goes left
  2. x4x \geq 4 because the circle is closed and shading goes right (correct answer)
  3. x<4x < 4 because the shading does not include numbers greater than 4
  4. x>4x > 4 because the circle shows 4 is included in the solution
Explanation: The number line shows a closed circle at 4 with shading extending to the right, indicating that 4 is included and all numbers greater than 4 are solutions. This represents x4x ≥ 4. Choice A has the wrong direction. Choice C uses an open circle (strict inequality) but the diagram shows closed. Choice D contradicts itself about whether 4 is included.

Question 11

A temperature sensor triggers an alarm when the temperature exceeds 75°F. The sensor recorded temperatures of 73°F, 76°F, 75°F, and 78°F. Based on the number line diagram shown, which inequality correctly represents when the alarm will sound?

  1. t>75t > 75 where tt is temperature in degrees Fahrenheit (correct answer)
  2. t75t \geq 75 where tt is temperature in degrees Fahrenheit
  3. t<75t < 75 where tt is temperature in degrees Fahrenheit
  4. t75t \leq 75 where tt is temperature in degrees Fahrenheit
Explanation: The alarm triggers when temperature 'exceeds' 75°F, meaning it goes above 75°F but not including 75°F itself. This is represented by t>75t > 75. The number line shows an open circle at 75 and shading to the right, confirming values greater than 75. Choice B uses ≥, which would include 75°F. Choices C and D represent temperatures below or equal to 75°F, which is when the alarm would NOT sound.

Question 12

The inequality x<2x < -2 has infinitely many solutions. Examine the number line representation below. Which statement about the solutions is correct?

  1. All numbers to the left of -2, including -2 itself, are solutions to the inequality
  2. All numbers to the left of -2, not including -2, are solutions to the inequality (correct answer)
  3. Only negative integers less than -2 are solutions to the inequality
  4. All numbers between -2 and positive infinity are solutions to the inequality
Explanation: The inequality x<2x < -2 means xx is strictly less than -2, so -2 itself is not included in the solution set. The solutions include all real numbers to the left of -2 on the number line, such as -3, -2.5, -10, etc. Choice A incorrectly includes -2. Choice C incorrectly limits solutions to only integers. Choice D describes the wrong direction (numbers greater than -2).

Question 13

The inequality y>1y > -1 is represented on the coordinate plane shown. A student claims that the point (2,0)(-2, 0) is a solution because "0 is greater than -1." Is the student correct?

  1. Yes, because the y-coordinate 0 satisfies the inequality y>1y > -1 regardless of x-coordinate (correct answer)
  2. No, because the point (2,0)(-2, 0) is not in the shaded region above y=1y = -1
  3. No, because negative x-coordinates cannot be solutions to inequalities involving y
  4. Yes, because both coordinates must be positive for the point to be a solution
Explanation: The inequality y>1y > -1 only constrains the y-coordinate, not the x-coordinate. Since the y-coordinate is 0 and 0>10 > -1 is true, the point (2,0)(-2, 0) is indeed a solution. The x-coordinate of -2 is irrelevant to this inequality. Choice B is wrong about shaded regions. Choice C incorrectly relates x-coordinates to y-inequalities. Choice D incorrectly requires both coordinates to be positive.

Question 14

A school dance requires students to be at least 13 years old. Let aa be a student's age (in years). Which inequality correctly represents this rule, and which number line matches it?

  1. Inequality: a>13a>13; Number line: open circle at 13, shaded to the right
  2. Inequality: a<13a<13; Number line: open circle at 13, shaded to the left
  3. Inequality: a13a\le 13; Number line: closed circle at 13, shaded to the left
  4. Inequality: a13a\ge 13; Number line: closed circle at 13, shaded to the right (correct answer)
Explanation: This question tests writing inequalities like a > c or a < c from real-world constraints, understanding that they have infinitely many solutions, and representing them on number lines with proper boundary markers (● for included, ○ for excluded) and shading. Constraint words translate to symbols: 'at least' means ≥ (includes boundary, like a ≥ 13 allows 13 or more), 'at most' means ≤ (includes), 'more than' means > (excludes), 'less than' means < (excludes); inequalities have infinite solutions unlike equations, and on a number line, use closed ● for ≥/≤, open ○ for >/<, shading right for greater and left for lesser. For example, 'must have at least 10 tickets' gives x ≥ 10 with solutions like 10, 11, 12, ... infinitely many, graphed as ● at 10 shaded right. The correct inequality is a ≥ 13 with a closed circle at 13 shaded right, as 'at least 13' includes 13 and all greater ages. A common error is using > instead of ≥, excluding 13 with an open circle, or shading left which would mean less than. To write it: (1) identify 'at least' as ≥, (2) translate to a ≥ 13. For graphing: (1) mark 13, (2) use closed ● since it includes, (3) shade right for greater values; solutions are infinite (all reals ≥ 13), and mistakes include wrong symbol or circle type.

Question 15

You are saving money for a game and can spend at most $50. Let xx be the amount you spend (in dollars). Which graph matches the inequality for this situation?

  1. x50x\le 50; number line: open circle at 50 and shading to the left
  2. x50x\ge 50; number line: closed circle at 50 and shading to the left
  3. x50x\le 50; number line: closed circle at 50 and shading to the right
  4. x50x\le 50; number line: closed circle at 50 and shading to the left (correct answer)
Explanation: This question tests writing inequalities like x > c or x < c from real-world constraints, understanding infinitely many solutions, and representing on number lines with proper boundary markers (●/○) and shading. Constraint words translate to symbols: 'at least' → ≥ (includes boundary: x ≥ 10 means 10 or more), 'at most' → ≤ (includes: x ≤ 50 means 50 or less), 'more than' → > (excludes boundary: x > 75 means above 75, not including 75), 'less than' → < (excludes: x < 60 below 60); inequalities have infinitely many solutions (x > 10 includes 11, 12, 13, ..., 1000, ...—continues forever, unlike equations with one solution); on a number line, mark boundary at c (for x > 10, mark 10), use closed ● if ≥ or ≤ (includes), open ○ if > or < (excludes), shade right for > / ≥ (greater values), left for < / ≤ (lesser values). For example, 'must have at least 10 tickets' → x ≥ 10 (x = tickets, 10 or more), solutions: 10, 11, 12, ... infinitely many (all non-negative integers ≥ 10), graph: ● at 10 shaded right (●======> ), includes 10 and all greater; or 'score more than 75' → x > 75 (above 75, excludes 75), graph: ○======> at 75 (open circle, shade right), solutions: 76, 77, 78, ... infinite. The correct choice is A: x ≤ 50 with closed circle at 50 and shading left, representing spending at most 50, including exactly 50. Errors include using an open circle for ≤ (choice B, excluding 50), shading right instead of left (choice C, for greater values), or wrong inequality like ≥ with incorrect shading (choice D). To graph: (1) draw number line, (2) mark boundary 50, (3) use closed ● for ≤, (4) shade left for lesser values. This has infinitely many solutions, all real numbers ≤ 50, not just integers; mistakes often involve circle type confusion or shading backward.

Question 16

To earn a certificate, a student must score more than 75 points. Let ss be the score. Which number line matches the inequality for this rule?

  1. Open circle at 75, shaded to the right (correct answer)
  2. Open circle at 75, shaded to the left
  3. Closed circle at 75, shaded to the left
  4. Closed circle at 75, shaded to the right
Explanation: This question tests writing inequalities like s > c or s < c from real-world constraints, understanding that they have infinitely many solutions, and representing them on number lines with proper boundary markers (● for included, ○ for excluded) and shading. Constraint words translate to symbols: 'at least' means ≥ (includes boundary), 'at most' means ≤ (includes), 'more than' means > (excludes, like s > 75 allows above 75 but not 75), 'less than' means < (excludes); inequalities have infinite solutions unlike equations, and on a number line, use closed ● for ≥/≤, open ○ for >/<, shading right for greater and left for lesser. For example, 'at least 13' gives a ≥ 13 with ● at 13 shaded right, infinite solutions like 13, 14, .... The correct number line is open circle at 75 shaded right, matching s > 75. A common error is using closed circle for >, including 75 wrongly, or shading left for less than. For graphing: (1) mark 75, (2) use open ○ since it excludes, (3) shade right for greater. Infinite solutions: all reals > 75; context like scores can be any real > 75, mistakes include circle type confusion.

Question 17

A parking meter accepts coins only if the total value is greater than 0.75.Sarahhasquarters(0.75. Sarah has quarters (0.25 each) and wants to determine how many quarters qq she needs. Which inequality and solution representation is correct?

  1. 0.25q>0.750.25q > 0.75; Sarah needs more than 3 quarters, so at least 4 quarters (correct answer)
  2. 0.25q0.750.25q \geq 0.75; Sarah needs at least 3 quarters to operate the meter
  3. 0.25q<0.750.25q < 0.75; Sarah needs fewer than 3 quarters to operate the meter
  4. q>0.75q > 0.75; Sarah needs more than 0.75 quarters to operate the meter
Explanation: The meter requires a value greater than $0.75, so 0.25q>0.750.25q > 0.75. Solving: q>3q > 3. Since Sarah can't use a fraction of a quarter, she needs at least 4 quarters. Choice B uses ≥ and incorrectly concludes 3 quarters is enough. Choice C uses the wrong inequality direction. Choice D omits the 0.25 coefficient and gives a nonsensical interpretation.

Question 18

A school requires students to read at least 20 minutes per day. Jenny reads for rr minutes on Monday. If she also reads for 15 minutes on Tuesday, which inequality ensures she meets the minimum requirement for both days combined?

  1. r+15>40r + 15 > 40 because she must exceed the two-day minimum
  2. r+1540r + 15 \geq 40 because she must meet or exceed the minimum (correct answer)
  3. r20r \geq 20 because each day has an independent 20-minute requirement
  4. r+1535r + 15 \geq 35 because the total must be at least 40 minutes
Explanation: The requirement is at least 20 minutes per day, so for 2 days she needs at least 40 minutes total. Jenny reads rr minutes Monday plus 15 minutes Tuesday, so r+1540r + 15 ≥ 40. Choice A uses strict inequality when 'at least' means ≥. Choice C ignores that this is about the combined total. Choice D states the correct reasoning but shows ≥ 35 instead of ≥ 40.

Question 19

A school club requires members to be at least 13 years old. Let aa be a student's age (in years). Which inequality correctly represents this rule?

  1. a>13a>13
  2. a13a\ge 13 (correct answer)
  3. a<13a<13
  4. a13a\le 13
Explanation: This question tests writing inequalities like a > c or a ≥ c from real-world constraints, understanding that inequalities have infinitely many solutions, and representing them on number lines with proper boundary markers such as closed circles (●) for inclusive or open circles (○) for exclusive, along with shading in the correct direction. Constraint words translate to symbols: 'at least' means ≥ which includes the boundary (a ≥ 13 means 13 or more), 'at most' means ≤ which includes it, 'more than' means > which excludes the boundary, and 'less than' means < which excludes it; inequalities have infinite solutions since they are satisfied by infinitely many numbers, unlike equations with finite solutions. For example, 'must be at least 13 years old' translates to a ≥ 13 where a is age, with solutions like 13, 14, 15, and infinitely many more, graphed as a number line with a closed circle at 13 and shading to the right (●======>). The correct inequality here is a ≥ 13, which includes 13 and all greater ages, matching choice B. A common error is using > instead of ≥ for 'at least,' excluding 13 incorrectly, or reversing to < or ≤, or misunderstanding infinite solutions by thinking only whole numbers count when actually all real numbers ≥13 satisfy it. To write this: (1) identify 'at least' as inclusive greater, (2) translate to ≥, (3) write a ≥ 13. For graphing: (1) draw number line, (2) mark 13, (3) use closed ● for ≥, (4) shade right for greater values; remember infinite solutions include all reals ≥13, and in context, ages like 13.5 would theoretically satisfy though practically ages are whole; mistakes include wrong symbol or circle type.

Question 20

To earn a badge in a video game, you must score more than 75 points. Let ss be your score. Which inequality represents all possible scores that earn the badge?

  1. s75s\ge 75
  2. s<75s<75
  3. s>75s>75 (correct answer)
  4. s75s\le 75
Explanation: This question tests writing inequalities like s > c from real-world constraints, recognizing infinitely many solutions, and the difference in symbols for exclusive vs inclusive boundaries. Constraint words to symbols: 'more than' → > (excludes boundary: s > 75 means above 75, not 75), 'at least' → ≥ (includes), 'less than' → <, 'at most' → ≤; infinite solutions as s > 75 includes 75.1, 76, ..., forever. For example, 'score more than 75' → s > 75, solutions: 76, 77, ... infinite integers or reals, graph: open ○ at 75 shaded right (○======>). The correct inequality is s > 75, matching choice C. Errors include using ≥ instead of >, including 75 wrongly, or reversing to <75, or saying finite solutions like only up to 100. Writing: (1) identify 'more than' as exclusive greater, (2) translate to >, (3) write s > 75; graphing would be open ○ at 75, shade right. Infinite solutions: uncountably many reals >75; context: scores above 75 qualify; mistakes: symbol mix-up (> vs ≥), not recognizing infinity.