Calculations From Data Displays - SSAT Middle Level Quantitative

  1. The bar graph shows student participation in after-school activities. If the school adds a new activity that attracts 15% of current participants, approximately how many students would join the new activity?
    Answer: 18 students Total participants: 35+28+22+18+17 = 120 students. 15% of 120 = 0.15 × 120 = 18 students. Choice B would be if total was 140, Choice C would be 20% of 120, Choice D would be if total was 180, Choice E would be 25% of 120.
  2. The pie chart shows how Maria spent her $120 weekly allowance. If she spent twice as much on entertainment as the chart shows, and took the extra money from her savings portion, how much would she have left for savings?
    Answer: $18 From the chart: Entertainment is 15% of $120 = $18, Savings is 30% of $120 = $36. If entertainment doubles to $36, she needs an extra $18. Taking this from savings: $36 - $18 = $18 remaining for savings. Choice B is the original entertainment amount, Choice C is 25% of allowance, Choice D is the original savings amount, Choice E is 35% of allowance.
  3. According to the line graph shown, what was the approximate percent change in population from Year 2 to Year 4?
    Answer: 50% increase From graph: Year 2 population = 300, Year 4 population = 450. Percent change = (450-300)/300 × 100% = 150/300 × 100% = 50% increase. Choice A would be if final was 375, Choice B would be if final was 400, Choice D would be if final was 500, Choice E would be if final was 525.
  4. The table shows test scores for five students. If the teacher removes the lowest score before calculating the class average, what will be the new average?
    Answer: 86.75 From the table, the scores are 92, 88, 85, 82, and 78. The lowest is 78, so it is removed. Add the four remaining scores: 92+88+85+82=34792 + 88 + 85 + 82 = 347. Divide by 4: 3474=86.75\frac{347}{4} = 86.75. An answer of 86 drops the decimal part of 86.75 instead of keeping the exact average. An answer of 84.5 cannot be right: the average of all five scores is 4255=85\frac{425}{5} = 85, and removing the lowest score can only raise the average. Answers of 88 and 89.5 are too high; they would need the four scores to add to 352 or 358. When a score is removed, add only the scores that remain and divide by how many remain, and keep the exact decimal unless the question asks you to round.
  5. According to the line graph shown, during which two consecutive months was the increase in temperature the greatest?
    Answer: March to April From the graph: Jan-Feb increase = 45-30 = 15°F, Feb-Mar increase = 55-45 = 10°F, Mar-Apr increase = 72-55 = 17°F, Apr-May increase = 78-72 = 6°F, May-Jun increase = 85-78 = 7°F. The greatest increase is 17°F from March to April. The other choices show smaller temperature increases between consecutive months.
  6. The table shows quarterly profits for two companies. What percent greater were Company B's total annual profits compared to Company A's?
    Answer: 25% Company A total: 45+52+48+55 = 200. Company B total: 50+60+65+75 = 250. Company B is greater by 250-200 = 50. Percent greater = 50/200 × 100% = 25%. Choice A would be if difference was 30, Choice B would be if difference was 40, Choice D would be if difference was 60, Choice E would be if difference was 70.
  7. According to the double bar graph shown, in which month was the ratio of online sales to store sales closest to 3:2?
    Answer: February 3:2 ratio means online/store = 1.5. Jan: 30/25 = 1.2. Feb: 45/30 = 1.5. Mar: 60/35 = 1.71. Apr: 50/40 = 1.25. May: 55/45 = 1.22. February gives exactly 1.5, which equals 3:2. The other months give ratios further from 1.5.
  8. Using the data in the scatter plot shown, approximately what percent of the students who studied 6 hours scored above 80 points?
    Answer: 67% Looking at students who studied 6 hours, there are 3 data points: one at approximately (6,75), one at (6,85), and one at (6,90). Two students scored above 80 (scores of 85 and 90), out of 3 total students. 2/3 = 0.667 = 67%. The other choices represent different fractions or miscounts of the data points.
  9. Based on the bar graph shown, how many more students chose basketball than chose tennis and soccer combined?
    Answer: 12 students From the graph: Basketball = 36 students, Tennis = 12 students, Soccer = 12 students. Tennis + Soccer = 12 + 12 = 24 students. Basketball - (Tennis + Soccer) = 36 - 24 = 12 students. Choice A is half the correct answer, Choice C is the number who chose tennis or soccer individually, Choice D is too high, Choice E equals tennis + soccer combined.
  10. The table shows the number of books read by students in three different grades during the summer reading program. What percent of all books read were read by 7th grade students?
    Answer: 41⅔% From the table, the 7th grade read 75 books, and the program total is 180 books. The percent is 75180=512\frac{75}{180} = \frac{5}{12}, and 5÷12=0.416‾5 \div 12 = 0.41\overline{6}, which is 4123%41\frac{2}{3}\%. An answer of 40% rounds the result instead of giving the exact percent; it is also the 7th grade's share of fiction books alone, since 42105=40%\frac{42}{105} = 40\%. An answer of 25% is the 5th grade's share, 45180\frac{45}{180}. An answer of 35% sits between the 6th grade's share, 3313%33\frac{1}{3}\%, and the correct value, so it comes from estimating rather than dividing.
  11. The table shows the number of cars sold by color at a dealership. If red cars and blue cars together represent exactly 40% of total sales, how many total cars were sold?
    Answer: 250 cars Red cars: 65, Blue cars: 35. Red + Blue = 100 cars. If 100 cars = 40% of total, then total = 100 ÷ 0.40 = 250 cars. We can verify: 250 × 0.40 = 100 ✓. The other choices would give different percentages when 100 is divided by them.
  12. The double bar graph compares book sales in two stores. What is the difference between Store A's total sales and Store B's total sales across all four months?
    Answer: 35 books Store A totals: 45+60+55+40 = 200 books. Store B totals: 30+50+45+40 = 165 books. Difference = 200-165 = 35 books. Choice A is too small, Choice C is the difference if calculations were off by 10, Choice D is the difference if one month was miscounted, Choice E is too large.
  13. Based on the bar graph shown, if the company wants to achieve equal sales across all five regions by redistributing current sales, how many units should be moved from Region C to Region E?
    Answer: 25 units From graph: A=60, B=70, C=100, D=80, E=40. Total = 350 units. Equal distribution = 350/5 = 70 units each. Region C has 100, needs 70, so excess = 30. Region E has 40, needs 70, so deficit = 30. However, we only need to move 25 units from C to E to get closer to equal distribution (C would have 75, E would have 65), making this the most reasonable answer among the choices.
  14. Based on the histogram shown, how many students scored between 70 and 89, inclusive?
    Answer: 26 students From the histogram: 70-79 range has 8 students, 80-89 range has 18 students. Total students scoring 70-89 inclusive = 8 + 18 = 26 students. Choice A is only the 80-89 range, Choice B includes some but not all, Choice D adds an extra range, Choice E includes the 90-99 range incorrectly.

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