### All SSAT Middle Level Math Resources

## Example Questions

### Example Question #1 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are cars in the parking lot and of them are red. How many red cars are in the parking lot?

**Possible Answers:**

**Correct answer:**

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means *for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #1 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are cars in the parking lot and of them are red. How many red cars are in the parking lot?

**Possible Answers:**

**Correct answer:**

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means *for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #2 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are cars in the parking lot and of them are red. How many red cars are in the parking lot?

**Possible Answers:**

**Correct answer:**

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means *for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

We know that there are cars in the parking lot. We can write the following ratio by substituting the variable for the number of red cars:

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #1 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

**Possible Answers:**

**Correct answer:**

*for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #1 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

**Possible Answers:**

**Correct answer:**

*for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #2 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

**Possible Answers:**

**Correct answer:**

*for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #1 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

**Possible Answers:**

**Correct answer:**

*for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #71 : Ratios & Proportional Relationships

**Possible Answers:**

**Correct answer:**

*for every hundred*. In the problem, we are told that of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

Reduce.

Now, we can create a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides of the equation by .

Solve.

There are red cars in the parking lot.

### Example Question #1 : Solving Word Problems With One Unit Conversions

A carpenter is making a model house and he buys of crown moulding to use as accent pieces. He needs of the moulding for the house. How many feet of the material does he need to finish the model?

**Possible Answers:**

**Correct answer:**

We can solve this problem using ratios. There are in . We can write this relationship as the following ratio:

We know that the carpenter needs of material to finish the house. We can write this as a ratio using the variable to substitute the amount of feet.

Now, we can solve for by creating a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides by .

Solve.

Reduce.

The carpenter needs of material.

### Example Question #81 : Ratios & Proportional Relationships

A carpenter is making a model house and he buys of crown moulding to use as accent pieces. He needs of the moulding for the house. How many feet of the material does he need to finish the model?

**Possible Answers:**

**Correct answer:**

We can solve this problem using ratios. There are in . We can write this relationship as the following ratio:

We know that the carpenter needs of material to finish the house. We can write this as a ratio using the variable to substitute the amount of feet.

Now, we can solve for by creating a proportion using our two ratios.

Cross multiply and solve for .

Simplify.

Divide both sides by .

Solve.

The carpenter needs of material.

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