### All SAT Math Resources

## Example Questions

### Example Question #81 : How To Find The Probability Of An Outcome

You have a box of 90 colored scrunchies. Half of the scrunchies are black, one third of the scrunchies are white, one ninth of the scrunchies are blue, and the rest are green. You pull the scrunchies from the box at random.

The first scrunchie you pick up is blue. The second scrunchie is green. What is the probability that the third scrunchie you pick up will be black?

**Possible Answers:**

None of the other answers

**Correct answer:**

Half of the scrunchies are black, so

One third of the scrunchies are white

One ninth of the scrunchies are blue

And the rest are green:

If we have already drawn two, our total amount of scrunchies is now 88, so the probability of pulling a black scrunchie will be:

### Example Question #82 : How To Find The Probability Of An Outcome

There is a classroom of 60 students. of the students are wearing red shirts, of the students are wearing pink shirts, and the rest of the students are wearing orange shirts. What is the probability of randomly selecting the name of a student wearing an orange shirt?

**Possible Answers:**

None of the available answers

**Correct answer:**

of the students are wearing red shirts, and

One third of the students are wearing pink shirts

The remaining students are wearing orange

The probability of randomly selecting a student wearing an orange shirt is

### Example Question #83 : How To Find The Probability Of An Outcome

A bag of colored candies has ten red candies, 14 purple candies, 12 orange candies, and 4 yellow candies. What is the ratio of yellow to orange candies in the bag?

**Possible Answers:**

**Correct answer:**

There are four yellow candies, and 12 orange candies, so the raio is:

The ratio of yellow to orange candies is 1:3

### Example Question #84 : How To Find The Probability Of An Outcome

of the population in Town A is NOT Asian. In addition, of the Asian population in Town A is male. A random person from Town A is selected. What is the probability that the person selected is both Asian and female.

**Possible Answers:**

**Correct answer:**

Recall:

Consequently, the probability that the person selected is Asian is:

Similarly, the probability that a randomly selected Asian person is also female is:

Finally, the probability of 2 unrelated events occuring is equal to the product of the individual probabilities of the 2 events. Therefore the probability of selecting an Asian female is

### Example Question #81 : Outcomes

Fred wants to put together outfits that he can wear for the day. He can wear any type of outfit for school, but he needs to wear formal attire for dinner later. He can either choose to wear something all day or choose to change clothes before going out to dinner.

If Fred has 2 formal shirts and 3 informal shirts, 1 pair of formal pants and 2 pairs of informal pants, and 1 pair of formal shoes and 1 pair of informal shoes, how many different ways could Fred appear for school and then dinner, allowing for changing in between?

**Possible Answers:**

**Correct answer:**

Fred can wear anything to school. This means he can wear either formal things or informal things. He has 3 informal shirts and 2 formal shirts. This means he has a total of 5 shirts to choose from when deciding what to wear. Similarly, he has 3 pairs of pants and 2 pairs of shoes to choose from. After choosing a shirt (5 options), he chooses pants (3 options) and shoes (2 options) resulting in choices for outfits to wear to school.

Fred must wear formal attire to the dinner. This means that Fred can only choose between his 2 formal shirts, his formal pair of pants, and his formal shoes. Since he only has a choice of shirts, he ends up only having 2 choices to make in outfits.

To figure out how many ways he can dress throughout the day, we simply choose an outfit for school and an outfit for dinner. We have 30 choices for what to wear to school and 2 choices to wear to dinner, giving us choices in total.

### Example Question #86 : How To Find The Probability Of An Outcome

A school takes a poll of their students and 85% respond. They find that, of those who responded, 45% are male and 55% are female. Of the males who responded to the poll, 80% said they would prefer more money invested in extracurriculars rather than the core educational classes. 100% of female respondents agreed that more money should be invested in extracurriculars.

If the school has 2000 students, which of the following could possibly be true?

**Possible Answers:**

The number of males who think that the school should have more extracurriculars is greater than 900.

More males than females believe there should be increased spending on extracurriculars.

A greater number of male students prefer core classes to extracurriculars.

Less than of the school believe that the school should increase spending for extracurriculars.

The majority of students believe the school should increase funding of core classes.

**Correct answer:**

The number of males who think that the school should have more extracurriculars is greater than 900.

Firstly, when taking a percentage, we can simply multiply by the proper decimal, where multiplying by 1 is 100%.

The school has 2,000 students. Since only 85% responded, we have students that were not accounted for.

Of the 1700 who responded, are male. Of these students, believe that there should be more invested in extracurriculars.

The key is recognizing that we can 'control' the 300 votes that are unaccounted for. These students were not counted, but might be male or female, and might vote for or against increased spending on extracurriculars.

Thus while we initially have 612 males believing in extracurriculars, it might be true that the remaining 300 uncounted votes were all males that believed in increasing spending on extracurriculars, resulting in up to 912 males voting for it.

All the other options are entirely impossible.

We know that are in favor of spending on extracurriculars. This means that the majority of students believe in increased spending on *extracurriculars* not on core classes, and that *more* than of the school believe that this spending should be increased.

We also know that, even should we have the maximum possible of 912 males in favor of increasing spending on extracurriculars, the 935 females who are in favor are still greater.

Finally, the number of male students who prefer extracurriculars is currently 612. Even should all 300 remaining voters be males in favor of core classes, we end up with in favor of core classes vs 612 in favor of extracurriculars.

### Example Question #87 : How To Find The Probability Of An Outcome

We toss a fair 6-sided die twice. What is the probability that the first toss is bigger than the second toss.

**Possible Answers:**

**Correct answer:**

If the first toss is a 1, it can not be bigger than any of the numbers on the second toss. If first toss is a 2, then it can be bigger than 1. If the first toss is 3, it can be bigger than 1 or 2. With this pattern, if the first toss is a 6, it can be bigger than any of the 5 numbers on the second toss.

Therefore, we get ways to have the first toss being bigger than the second toss. The total number of combinations is .

So we have a probablility of .

### Example Question #88 : How To Find The Probability Of An Outcome

We randomly pick two numbers from positive integers. What is the probability that their sum is odd given that their product is even?

**Possible Answers:**

**Correct answer:**

There are four combinations total, being: {(odd,odd), (odd, even), (even, odd), (even, even)}

Given that their product is even, we only have the set {(odd,even),(even,odd),(even, even)}

The probability that their sum is odd from the set {(odd,even),(even,odd),(even, even)} is because and .

### Example Question #89 : How To Find The Probability Of An Outcome

Bill rolls three 6-sided dice at once. The first die comes up as a 5. What is the probability that the total of all three dice will **not** be a prime number?

**Possible Answers:**

**Correct answer:**

The first die comes up as a 5. We are essentially asking about outcomes of two dice, plus 5. As a first step, we should be sure we know the primes we need to exempt. The smallest sum we can have is if both of the other dice roll 1, giving us a 7. 7 is a prime number, so will will exempt this number. The largest number we can roll is both rolling 6, giving us a total of 17 (also a prime). All the primes we will need to remove are then: 7,11,13 and 17.

We have two approaches now. We can find the odds of rolling a number besides those above directly, or we can take the odds of getting any of the above 4, and then subtracting this value from 1.

The latter method is faster, but both use the same method. Firstly, we'll subtract 5 from all the numbers: 2,6,8,12.

The odds of getting a 2 on two dice is , since the only roll that will work is two 1s and there are a total of 36 possible rolls (6 choices per die).

Similarly, the odds of getting a 12 is since it requires two 6's.

For 6, you can roll 1-5, 2-4, 3-3, 4-2, 5-1. This gives us odds of getting a 6. Similarly, an 8 can be achieved by rolling 6-2, 5-3, 4-4, 3-5, 2-6.

Our total odds of rolling any of these 4 is thus:

Our answer is then:

### Example Question #90 : How To Find The Probability Of An Outcome

The first three songs of The Silver Comet’s demo album are 2 minutes 30 seconds, 3 minutes 20 seconds, and 3 minutes 45 seconds in length. Jane has the three songs on a continuous loop all night long. What is the probability that her dad tells her to go to sleep during the first song?

**Possible Answers:**

**Correct answer:**

2:30 = 150 seconds

3:20 = 200 seconds

3:45 = 225 seconds

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