All SAT Math Resources
Example Questions
Example Question #21 : Venn Diagrams
What is the intersection of the Venn Diagram shown below?
The intersection of the Venn Diagram is only the numbers in both circles.
The section in the middle contains the answer set.
Thus the intersection is, .
Example Question #11 : Intersection
Find
A =
B =
represents the intersection of the two sets A and B. The intersection of A and B is the set of elements that are contained in both A and B.
The elements that appear in A and B are 4, 5, and 154.
Therefore, the intersection of A and B is .
Example Question #11 : How To Find The Intersection Of A Venn Diagram
Farmer John has one hundred plots of land. Sixty plots grow corn. Forty plots grow carrots. These numbers take into account that some of the plots grow both corn and carrots.
How many plots grow both corn and carrots?
To find how many plots grow both carrots and corn, we subtract .
That means that fifty plots grow corn only, while thirty plots grow carrots only.
Example Question #22 : Venn Diagrams
What is the intersection of the sets A and B?
A =
B =
The intersection of 2 sets A and B is the set of the items that are included in both sets. The items that appear in both A and B are 4 and 35.
Therefore, the intersection of A and B is .
Example Question #21 : Venn Diagrams
In the above Venn diagram, let the universal set be
yields a remainder of 1 when divided by 4
yields a remainder of 1 when divided by 3
How many elements of would be placed in the shaded portion of the above diagram?
Five
Nine
Eight
Seven
Six
Six
The shaded portion of the Venn diagram is - the set of all elements in but not .
The following elements of yield a remainder of 1 when divided by 4, and therefore comprise set :
If 3 is subtracted from each, what results are the elements whose division by 4 yields a remainder of 1, and thus, elements of .
The following elements of yield a remainder of 1 when divided by 4, and therefore comprise set :
The elements in that are also elements in are 1, 13, 25, and 37 - four elements out of ten. Therefore, the set comprises six elements.