### All SAT Math Resources

## Example Questions

### Example Question #21 : How To Find Rate

If an object takes 10 minutes to go 3 miles, how fast is the object going?

**Possible Answers:**

10/3 mph

3/10 mph

1/2 mph

18 mph

36 mph

**Correct answer:**

18 mph

First convert minutes to hours, so 10 minutes is 1/6 hours; then remember distance = rate * time, so distance/time = rate then 3/(1/6) = 18 mph

### Example Question #42 : Arithmetic

Mary travels at a constant speed to her friend Clara's house by walking directly east for 8 miles, and then walking directly north for 6 miles. The amount of time that it takes her to reach Clara's house is equal to t. If Mary had been able to travel directly to Clara's house in a straight line at the same speed, how much time would she have saved, in terms of t?

**Possible Answers:**

5*t*/7

6*t*/7

4*t*/7

2*t*/7

3*t*/7

**Correct answer:**

2*t*/7

### Example Question #41 : Proportion / Ratio / Rate

Sam earns *d* dollars per day. At this rate, how many days will it take Sam to earn *q* dollars?

**Possible Answers:**

*q*/*d*

*d*/*q*

10*q*

100*d*/*q*

*dq*

**Correct answer:**

*q*/*d*

*q* is the number of dollars to be earned, *d* is the amount earned each day, so you divide *q* by *d* to get the number of days.

### Example Question #1411 : Sat Mathematics

Bob can build a house in 3 days. Gary can build a house in 5 days. How long does it take them to build a house together?

**Possible Answers:**

3/2 days

5/4 days

15/8 days

2 days

4 days

**Correct answer:**

15/8 days

DO NOT pick 4 days, which would be the middle number between Bob and Gary's rates of 3 and 5 days respectively. The middle rate is the answer that students always want to pick, so the SAT will provide it as an answer to trick you!

Let's think about this intuitively before we actually solve it, so hopefully you won't be tempted to pick a trick answer ever again! Bob can build the house in 3 days if he works by himself, so with someone else helping him, it has to take *less* than 3 days to build the house! This will always be true. Never pick the middle rate on a combined rates problem like this!

Now let's look at the problem computationally. Bob can build a house in 3 days, so he builds 1/3 of a house in 1 day. Similarly, Gary can build a house in 5 days, so he builds 1/5 of a house in 1 day. Then together they build 1/3 + 1/5 = 5/15 + 3/15 = 8/15 of the house in 1 day.

Now, just as we did to see how much house Gary and Bob can build separately in one day, we can take the reciprocal of 8/15 to see how many days it takes them to build a house together. (When we took the reciprocal for Bob, 3 days/1 house = 1/3 house per day.) The reciprocal of 8/15 is 15/8, so they took 15/8 days to build the house together. 15/8 days is almost 2 days, which seems like a reasonable answer. Make sure your answer choices make sense when you are solving word problems!

### Example Question #521 : Arithmetic

Two brothers, Jake and Fred, have a pool in which 9 laps is 1 mile. Jake swims 2 laps in 1 minute, and Fred swims 4 laps in 1 minute. How far has Jake swum when Fred has finished swimming 2 miles?

**Possible Answers:**

3/4 miles

2 miles

9/2 miles

1 mile

3/2 miles

**Correct answer:**

1 mile

We can solve this with lots of calculations and conversions of laps to miles, etc., or we can look at what the question is really asking. We want to know how far Jake swims in the time it takes Fred to swim two miles. Instead of converting Fred's miles to laps and comparing to Jake's laps, let's just look at how fast the two brothers swim in relation to one another. Fred swims twice as fast as Jake, so in the same amount of time, he will swim twice as far as Jake. Therefore if Fred swims 2 miles, Jake swims 1 mile in the same amount of time.

### Example Question #46 : Arithmetic

Every 3 minutes, 4 liters of water are poured into a 2,000-liter tank. After 4 hours, what percent of the tank is full?

**Possible Answers:**

**Correct answer:**

60 minutes in an hour, 240 minutes in four hours. If 4 liters are poured every 3 minutes, then 4 liters are poured 80 times. That comes out to 320 liters. The tank holds 2,000 liters, so of the tank is full.

### Example Question #41 : Arithmetic

**Possible Answers:**

**Correct answer:**

### Example Question #42 : Arithmetic

Laura owns a large property. Her lawn is rectangular. It is 500 meters long, and 350 meters wide. If Laura mows the lawn at a rate of 20,000 meters squared per hour, how many hours will it take Laura to finish mowing the lawn?

**Possible Answers:**

**Correct answer:**

The area of a rectangle is the length , multiplied by the width . Here the area of the lawn in meters squared is:

We found that Laura is mowing 175,000 meters squared at a rate of 20,000 meters squared per hour.

Plugging in 20,000 for the rate, and 175,000 for the total area gives:

Multiply both sides by the total number of hours:

Now, divide both sides by 20,000:

### Example Question #21 : How To Find Rate

Jess is trying to fill her 10,000 gallon pool with water before the summer. She has three hoses, one that pump water at a rate of 175 gallons per hour, 25 gallons per hour and 200 gallons per hour. If she used all three hoses how many hours would it take to fill her pool?

**Possible Answers:**

**Correct answer:**

First add up all of the rates to get the total rate of water flowing into the pool at one time.

Then to determine the time it takes to fill the pool divide the total volume of the pool by this rate.

This answer of 25 hours.

### Example Question #51 : Proportion / Ratio / Rate

Joaquin can clean a pool in *j* minutes. River can clean the same size pool in *r* minutes. Which of the following expresses the time needed for three pools (all of the same size) to be cleaned when Joaquin and River work together?

**Possible Answers:**

**Correct answer:**

This is a rate question, so first we should rewrite the "times" given to us as rates.

Joaquin's rate :

River's rate:

Now we add their rates together, to find the rate when they work together:

Using the equiation for distance, d = rate * time we can rearrange it to see that to find time we need to do t = distance/rate

in this case, the distance is "3 pools" and the rate is "(j+r)/jr pools per minute". So we reach our answer:

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