### All PSAT Math Resources

## Example Questions

### Example Question #51 : How To Find The Solution To An Equation

What number decreased by 7 is equal to 10 increased by 7?

**Possible Answers:**

10

15

27

17

24

**Correct answer:**

24

The best way to solve this problem is to translate it into an equation, "decreased" meaning subtract and "increased" meaning add:

x – 7 = 10 + 7

x = 24

### Example Question #11 : Linear / Rational / Variable Equations

If a%b = (2b + 3a)/(6ab), what would have a greater value, 2%3 or 3%2?

**Possible Answers:**

They are the same

3%2

2%3

Cannot be determined

**Correct answer:**

3%2

First find 2%3 = (2 * 3 + 3 * 2)/(6 * 2 * 3) = 12/36 = 1/3, then 3%2 = (2 * 2 + 3 * 3)/(6 * 3 * 2) = 13/36 which is greater.

### Example Question #13 : Linear / Rational / Variable Equations

**Possible Answers:**

–1

0

1/2

1

–1/2

**Correct answer:**

–1/2

### Example Question #191 : Algebra

If 5 + *x *is 5 more than 5,what is the value of 2*x*?

**Possible Answers:**

10

5

20

15

**Correct answer:**

10

5 more than 5 = 10

5 + *x* = 10

Subtract 5 from each side of the equation: *x* = 5 → 2*x* = 10

### Example Question #121 : Algebra

Let *f*(*x*) = 2*x*^{3} + 7*x*^{2} - 4*x* and *g*(*x*) = 4*x* - *x*^{3}. If *k* is a positive number such that *f*(*k*) = 0, then what is *g*(*k*)?

**Possible Answers:**

7/8

17/8

1

2

15/8

**Correct answer:**

15/8

First, we need to find the possible values of *k* such that *f*(*k*) = 0.

We can use the definition of *f*(*x*) to write an expression for *k*.

*f*(*x*) = 2*x*^{3} + 7*x*^{2} – 4*x*

*f*(*k*) = 2*k*^{3} + 7*k*^{2} – 4*k* = 0

In order to solve this equation, we will want to factor as much as we can. We can immediately see that we could take out a *k* from all three terms.

2*k*^{3} + 7*k*^{2} – 4*k* = 0

*k*(2*k*^{2 }+ 7*k –* 4) = 0

Now, we need to factor 2*k*^{2 }+ 7*k –* 4 by grouping. When we multiply the outer two coefficients we get (2)(–4) = –8. The middle coefficient is 7. This means we need to think of two numbers that multiply to give us –8, but add to give us 7. These two numbers are 8 and –1. We can now rewrite 2*k*^{2 }+ 7*k –* 4 as follows:

2*k*^{2 }+ 7*k –* 4 = 2*k*^{2} + 8*k* – *k* – 4

Group the first two terms and the second two terms.

2*k*^{2} + 8*k* – *k* – 4 = (2*k*^{2} + 8*k* ) + (–*k* – 4)

Next, factor out a 2*k* from the first two terms and a –1 from the last two terms.

(2*k*^{2} + 8*k* ) + (–*k* – 4) = 2*k*(*k *+ 4) + –1(*k *+ 4)

Then, factor out *k *+ 4 from the 2*k* and the –1.

2*k*(*k *+ 4) + –1(*k *+ 4) = (*k *+ 4)(2*k –* 1)

Thus, 2*k*^{2 }+ 7*k –* 4, when fully factored, equals (*k *+ 4)(2*k –* 1).

Now, let's go back to the equation *k*(2*k*^{2 }+ 7*k –* 4) = 0 and substitute (*k *+ 4)(2*k –* 1) for 2*k*^{2 }+ 7*k –* 4.

*k*(2*k*^{2 }+ 7*k –* 4) = *k*(*k *+ 4)(2*k –* 1) = 0

We now have three factors, and we can set each equal to zero to find the possible values of *k*.

The first factor is *k*. This means *k* = 0 is one value for *k*.

The next factor is *k* + 4.

*k* + 4 = 0

*k* = –4

The last factor is 2*k* – 1.

2*k* – 1 = 0

2*k* = 1

*k* = 1/2

The values of *k* for which *f*(*k*) = 0 are 0, –4, and 1/2. However, we are told that *k* is positive, so this means that *k* can only be 1/2.

Ultimately, the problem asks us to find *g*(*k*). This means we must use the equation for *g*(*x*) to find *g*(1/2).

*g*(*x*) = 4*x* – *x*^{3}

*g*(1/2) = 4(1/2) – (1/2)^{3}

= 2 – (1/8)

= 15/8

The answer is 15/8.

### Example Question #21 : Linear / Rational / Variable Equations

The sum of two consecutive positive even integers is two greater than one-tenth of the product of the two integers. What is the sum of the positive factors of the smaller integer?

**Possible Answers:**

31

39

28

60

42

**Correct answer:**

39

We need to translate the information given into an algebraic equation that will help us solve for the integers.

Let *x* represent the smaller of the two integers. Because they are consecutive even integers, the other integer is equal to *x* + 2.

We are told that the sum of the two integers is two greater than one-tenth of their product. We can represent the sum of the two integers as *x* + (*x *+ 2).

To represent one-tenth of the product, we can write (1/10)(*x*)(*x *+ 2). Two greater than this quantity would be equal to 2 + (1/10)(*x*)(*x *+ 2). Remember that "two greater" requires us to add 2, while "two times greater" would have required us to multiply by 2.

Now, we can set the sum equal to two greater than one-tenth the product.

*x* + (*x *+ 2) = 2 + (1/10)(*x*)(*x *+ 2)

Multiply both sides by 10 to eliminate the fraction.

10(*x* + *x* + 2) = 10(2 + (1/10)*x*(*x *+ 2))

Distribute the 10 on both sides.

10*x* + 10*x* + 20 = 20 + 10(1/10)*x*(*x *+ 2)

Simplify both sides.

20*x* + 20 = 20 + *x*(*x *+ 2)

Distribute the *x* on the right side.

20*x* + 20 = 20 + *x*^{2 }+ 2*x*

Subtract 20 from both sides.

20*x* = *x*^{2} + 2*x*

Subtract 20*x* from both sides.

*x*^{2 }– 18*x* = 0

Factor out an *x*.

*x*(*x –* 18) = 0

Set each factor equal to zero.

*x* = 0, or *x* – 18 = 0, which means *x* = 0 or 18. However, because we are told that the integers are positive, the value of *x* must be 18.

The smaller integer is 18. We are asked to find the sum of its factors. To find the factors of 18, we must think of all the pairs of numbers that will multiply to give us 18. The pairs are as follows:

1 and 18, 2 and 9, 3 and 6

This means the factors of 18 are 1, 2, 3, 6, 9, and 18. The sum of these numbers is 1 + 2 + 3 + 6 + 9 + 18 = 39.

The answer is 39.

### Example Question #21 : Algebra

In a group of 24 children, there are twice as many girls as there are boys. How many boys are there?

**Possible Answers:**

14

16

10

12

8

**Correct answer:**

8

Since there are twice as many girls as boys, we know that 2*b* = *g*.

Since there are 24 total, we know that *b* + *g* = 24.

Substituting the first equation into the second equation yields

*b* + 2*b* = 24

3*b* = 24

*b* = 8

### Example Question #121 : Algebra

For each megawatt of power that it produces, a power plant spends $30,000 on coal, $50,000 on salaries, and $20,000 on general expenses. If the plant produces 250 megawatts, how much does it spend on salaries and general expenses combined?

**Possible Answers:**

$20,000,000

$12,500,000

$17,500,000

None of the other answers

$15,000,000

**Correct answer:**

$17,500,000

The problem is simple if you do not mix up your values and their meanings. What we know is that for 250 megawatts, we should have 250 times the expenses in each of our categories. Therefore, for our data, we know the following.

For salaries, we have $50,000 * 250 or $12,500,000.

For general expenses, we have $20,000 * 250 or $5,000,000

Therefore, our total is: $12,500,000 + $5,000,000 = $17,500,000

We also could have calculated this by adding $50,000 and $20,000 together to get $70,000 per megawatt. This would be $70,000 * 250 = $17,500,000 as well.

### Example Question #22 : How To Find The Solution To An Equation

**Possible Answers:**

20

6

24

12

2

**Correct answer:**

24

### Example Question #861 : Psat Mathematics

For what value of *x* does 4(3*x* – 2) = 12?

**Possible Answers:**

5/6

2

1

2/3

5/3

**Correct answer:**

5/3

We have to solve the equation 4(3*x* – 2) = 12. First, we can distribute the left side.

4(3*x*) – 4(2) = 12

12*x* – 8 = 12

Then we add 8 to both sides.

12*x* = 20

Divide both sides by 12.

*x* = 20/12

Simplify 20/12 by dividing the numerator and denominator by 4.

*x* = 20/12 = 5/3

The answer is 5/3.

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