### All Precalculus Resources

## Example Questions

### Example Question #44 : Parabolas

Write the equation for a vertex of that passes through the point .

**Possible Answers:**

**Correct answer:**

The vertex form for a parabola is given below:

The vertex coordinates are or as given in the problem statement.

Now solve for a using the point it crosses , by plugging the point into the equation.

Plug a back to find the final answer:

### Example Question #45 : Parabolas

Find the focus and the directrix of the following parabola: .

**Possible Answers:**

Focus:

Directrix:

Focus:

Directrix:

Focus:

Directrix:

Focus:

Directrix:

**Correct answer:**

Focus:

Directrix:

To find the focus from the equation of a parabola, first set the equation to resemble the form where represents any numerical value.

For our problem, it is already in this form.

Therefore,

.

Solve for then .

The focus for this parabola is given by .

So, is the focus of the parabola.

The directrix is represented as .

Therefore, the directrix for this problem is .

### Example Question #46 : Parabolas

Find the directerix of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

For the parabola in question, the vertex is and . This parabola will open up. Because the parabola will open up, the directerix will be located units down from the vertex. The equation for the directerix is then .

### Example Question #47 : Parabolas

Find the directerix for the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

For the parabola in question, the vertex is and . This parabola will open up. Because the parabola will open up, the directerix will be located unit down from the vertex. The equation for the directerix is then .

### Example Question #48 : Parabolas

Find the directerix of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

Start by putting the equation in th estandard form of the equation of a vertical parabola.

Isolate the terms to one side.

Complete the square for the terms. Remember to add the same amount on both sides!

Factor out both sides of the equation to get the standard form of a vertical parabola.

For the parabola in question, the vertex is and . This parabola will open down. Because the parabola will open down, the directerix will be located units above the vertex. The equation for the directerix is then .

### Example Question #49 : Parabolas

Find the focus of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

Start by putting the equation into the standard form.

Isolate the terms on one side.

Complete the square. Remember to add teh same amount on both sides!

Factor both sides of the equation to get the standard equation for the parabola.

For the parabola in question, the vertex is and . This parabola will open up. Because the parabola will open up, the focus will be located unit up from the vertex. The focus is then located at .

### Example Question #50 : Parabolas

Find the focus of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

For the parabola in question, the vertex is and . This parabola will open down. Because the parabola will open down, the focus will be located units down from the vertex. The focus is then located at .

### Example Question #51 : Parabolas

Find the focus of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a vertical parabola:

, where is the vertex of the parabola and gives the focal length.

When , the parabola will open up.

When , the parabola will open down.

For the parabola in question, the vertex is and . This parabola will open down. Because the parabola will open down, the focus will be located units down from the vertex. The focus is then located at

### Example Question #52 : Parabolas

Find the directerix of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a horizontal parabola:

, where is the vertex of the parabola and is the focal length.

When , the parabola opens to the right.

When , the parabola opens to the left.

For the given parabola, the vertex is and . This means the parabola is opening to the left and that the directerix will be located unit to the right of the vertex. The directerix is then .

### Example Question #53 : Parabolas

Find the directerix of the parabola with the following equation:

**Possible Answers:**

**Correct answer:**

Recall the standard form of the equation of a horizontal parabola:

, where is the vertex of the parabola and is the focal length.

When , the parabola opens to the right.

When , the parabola opens to the left.

For the given parabola, the vertex is and . This means the parabola is opening to the left and that the directerix will be located units to the right of the vertex. The directerix is then .