### All Precalculus Resources

## Example Questions

### Example Question #21 : Polynomial Functions

Find the zeros of the following polynomial:

**Possible Answers:**

**Correct answer:**

To find the zeros of a polynomial, we have set it equal to 0, factor it, and solve for x.

### Example Question #22 : Polynomial Functions

Find the zeros of the following polynomials.

**Possible Answers:**

**Correct answer:**

To find the zeros, we must set the polynomial equal to 0, factor, and solve.

### Example Question #101 : Pre Calculus

Zeros of a quadratic.

Find the zeros of

.

**Possible Answers:**

.

.

.

.

**Correct answer:**

.

, and , so the polynomial factors into

.

When the function is set to equal 0, either of the products that it factors into are 0. That is

,

so

And

,

so .

### Example Question #102 : Pre Calculus

Find the zeros of the following polynomial:

**Possible Answers:**

**Correct answer:**

To find the zeros, we must set it equal to zero, factor, and solve.

### Example Question #1 : Evaluate A Polynomial Using Synthetic Substitution

Using synthetic division determine which of these is a factor of the polynomial .

**Possible Answers:**

**Correct answer:**

Synthetic division is a short cut for doing long division of polynomials and it can only be used when divifing by divisors of the form . The result or quoitient of such a division will either divide evenly or have a remainder. If there is no remainder, then the "" is said to be a factor of the polynomial. The polynomial must be in standard form (descending degree) and if a degree is skipped such as it must be accounted for by a "place holder".

___ __ __ __

__ __ ___

where is the remainder.** **

While doing the long division we add vertically and we multiply diagonally by k. The empty lines represent places we put the sums and products. Notice that after the first term in the top row there is a 0; this is the place holder. This is because the degrees in the polynomial skipped. When the new coefficients have been found always rewrite starting with one order lower than the highest degree of the original polynomial.

Use synthetic division to verify each factor of the form . Lets start with .

Two goes into 6 three times resulting in:

_____________________

From here we see will give you a remainder of zero and is therefore a factor of the polynomial .

### Example Question #2 : Evaluate A Polynomial Using Synthetic Substitution

Which of the following is the correct answer (quotient and remainder format) for the polynomial being divided by .

**Possible Answers:**

**Correct answer:**

Recall that dividing a polynomial by does not always result in a pefect division (remainder of 0). Sometimes there is a remainder just like in normal division. When there is a remainder, we write the answer in a certain way.

For example

where the divisor is , the quotient or answer is , the remainder is , and the dividend is .

Even though we have variables here, this is the same as noting that with a remainder of .

And how do we check to know if we have the right answer? We multiply and add 3 to get 15, our dividend. The same method is used for synthetic division.

Thus, for our problem:

,

we must first multiply the divisor by the quotient using the foil method (first multiplying everything in the divisor by x and then everything in the divisor by 3)

=

now we just add the remainder which is 1 to yield which matches the original dividend and is therefore our answer!

### Example Question #352 : Pre Calculus

Is a root of ?

**Possible Answers:**

Maybe

Yes

No

**Correct answer:**

No

To determine if is a root of the function given, you can use synthetic division to see if it goes in evenly. To set up the division problem, set up the coefficients of the function and then set 1 outside. Bring down the 1 (of the coefficients. Then multiply that by the being divided in. Combine the result of that with the next coefficient , which is . Then, multiply that by . Combine that result with the next coefficient , which gives you . Multiply that by , which gives you . Combine that with the last coefficient , whcih gives you . Since this is not , you have a remainder, which means that does not go in evenly to this function and is not a root.

### Example Question #1 : Divide Polynomials By Binomials Using Synthetic Division

Divide the polynomial by .

**Possible Answers:**

**Correct answer:**

Our first step is to list the coefficients of the polynomials in descending order and carry down the first coefficient.

We multiply what's below the line by and place the product on top of the line. We find the sum of this number with the next coefficient and place the sum below the line. We keep repeating these steps until we've reached the last coefficients.

To write the answer, we use the numbers below the line as our new coefficients. The last number is our remainder.

with remainder

This can be rewritten as

**Keep in mind:** the highest degree of our new polynomial will always be one less than the degree of the original polynomial.

### Example Question #1 : Divide Polynomials By Binomials Using Synthetic Division

Divide the polynomial by .

**Possible Answers:**

**Correct answer:**

Our first step is to list the coefficients of the polynomials in descending order and carry down the first coefficient.

We multiply what's below the line by and place the product on top of the line. We find the sum of this number with the next coefficient and place the sum below the line. We keep repeating these steps until we've reached the last coefficients.

To write the answer, we use the numbers below the line as our new coefficients. The last number is our remainder.

with remainder

This can be rewritten as:

**Keep in mind:** the highest degree of our new polynomial will always be one less than the degree of the original polynomial.

### Example Question #3 : Divide Polynomials By Binomials Using Synthetic Division

Divide the polynomial by .

**Possible Answers:**

**Correct answer:**

Our first step is to list the coefficients of the polynomials in descending order and carry down the first coefficient.

We mulitply what's below the line by 1 and place the product on top of the line. We find the sum of this number with the next coefficient and place the sum below the line. We keep repeating these steps until we've reached the last coefficients.

To write the answer, we use the numbers below the line as our new coefficients. The last number is our remainder.

with remainder

**Keep in mind:** *the highest degree of our new polynomial will always be one less than the degree of the original polynomial.*

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