6th Grade Math Flashcards: Solve Unit Rate Problems

What this deck covers

This deck focuses on Solve Unit Rate Problems, giving you a quick way to review the definitions, rules, and examples that matter most for 6th Grade Math.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What is the unit price for $7 for $12$ bars?

Answer: $\frac{7}{12}$ dollars per bar. Divide price by quantity: $\frac{7}{12}$ dollars per bar.

Flashcard 2: What is the time needed to travel $90$ miles at $45$ mph?

Answer: $2$ hours. Divide distance by speed: $90 \div 45 = 2$ hours.

Flashcard 3: What is the unit rate in words per minute for $450$ words in $9$ minutes?

Answer: $50$ words per minute. Divide total words by time: $450 ÷ 9 = 50$ wpm.

Flashcard 4: What is the cost per ounce for $6 for a $24$-ounce bottle?

Answer: $0.25 per ounce. Divide price by ounces: \6 \div 24 = $0.25$ per ounce.

Flashcard 5: What number of lawns can be mowed in $35$ hours at $\frac{4}{7}$ lawn per hour?

Answer: $20$ lawns. Multiply rate by time: $\frac{4}{7} \times 35 = 20$ lawns.

Flashcard 6: What is the cost for $5$ pounds of apples at $2 per pound?

Answer: $10. Multiply unit price by quantity: \2 \times 5 = $10$.

Flashcard 7: What is the unit rate for $300$ words in $5$ minutes (words per minute)?

Answer: $60$ words per minute. Divide words by minutes: $300 \div 5 = 60$ words per minute.

Flashcard 8: What is the unit rate in miles per hour for $150$ miles in $3$ hours?

Answer: $50$ miles per hour. Divide total distance by total time: $150 ÷ 3 = 50$.

Flashcard 9: What is a unit rate, stated in words?

Answer: A rate with a denominator of $1$ unit. Simplifies any rate to a per-one basis for easy comparison.

Flashcard 10: What is the unit rate in minutes per gallon for $12$ gallons in $4$ minutes?

Answer: $\frac{1}{3}$ minute per gallon. Divide time by gallons: $4 \div 12 = \frac{1}{3}$ minute per gallon.

Flashcard 11: What is the distance at $\frac{3}{2}\ \text{mi/h}$ for $2$ hours?

Answer: $3$ miles. Multiply speed by time: $\frac{3}{2} \times 2 = 3$ miles.

Flashcard 12: What rate in lawns per hour is $4$ lawns in $7$ hours?

Answer: $\frac{4}{7}$ lawn per hour. Divide lawns by hours: $\frac{4}{7}$ lawns per hour.

Flashcard 13: What is the time in hours to travel $84$ miles at $28$ miles per hour?

Answer: $3$ hours. Divide distance by speed: $84 ÷ 28 = 3$ hours.

Flashcard 14: What is the number of lawns mowed in $35$ hours at a rate of $\frac{4}{7}$ lawns per hour?

Answer: $20$ lawns. Multiply rate by time: $\frac{4}{7} × 35 = 20$ lawns.

Flashcard 15: What is the speed in meters per second for $120$ m in $10$ s?

Answer: $12$ m per s. Divide distance by time: $120 ÷ 10 = 12$ m/s.

Flashcard 16: What formula gives constant speed as a unit rate using distance $d$ and time $t$?

Answer: $\text{speed}=\frac{d}{t}$. Speed equals distance divided by time.

Flashcard 17: What is the unit price if $3$ notebooks cost $7.50?

Answer: $2.50 per notebook. Divide total cost by quantity: \7.50 \div 3 = $2.50$.

Flashcard 18: What is the unit rate in minutes per item for $9$ minutes for $45$ items?

Answer: $\frac{1}{5}$ minute per item. Divide time by items: $9 \div 45 = \frac{1}{5}$ minute per item.

Flashcard 19: What is the time formula using distance $d$ and constant speed $s$?

Answer: $t=\frac{d}{s}$. Time equals distance divided by speed.

Flashcard 20: What is the constant speed for $150$ miles in $3$ hours?

Answer: $50$ miles per hour. Divide distance by time: $150 \div 3 = 50$ mph.

Flashcard 21: What is the unit price if $12$ apples cost $6?

Answer: $0.50 per apple. Divide total cost by number of items: \6 \div 12 = $0.50$.

Flashcard 22: What is the unit price in dollars per pound for $9 for $3$ lb of apples?

Answer: $3 per lb. Divide total cost by total weight: \9 ÷ 3 = $3$.

Flashcard 23: What is the unit price in dollars per item for $18 for $6$ notebooks?

Answer: $3 per notebook. Divide total cost by quantity: \18 ÷ 6 = $3$.

Flashcard 24: What is the unit rate for $4$ lawns in $7$ hours (lawns per hour)?

Answer: $\frac{4}{7}$ lawns per hour. Divide lawns by hours: $\frac{4}{7}$ lawns each hour.

Flashcard 25: What is the unit rate in gallons per minute for $12$ gallons in $4$ minutes?

Answer: $3$ gallons per minute. Divide gallons by minutes: $12 \div 4 = 3$ gallons per minute.

Flashcard 26: What time is needed to travel $180$ miles at $60\ \text{mi/h}$?

Answer: $3$ hours. Divide distance by speed: $180 \div 60 = 3$ hours.

Flashcard 27: What is the unit price in \/\text{lb}$for $14 for$5$ lb?

Answer: $2.80 per lb. Divide price by weight: $14 \div 5 = 2.80$ dollars per pound.

Flashcard 28: What is the unit rate for $18$ pages in $6$ minutes (minutes per page)?

Answer: $\frac{1}{3}$ minute per page. Divide minutes by pages: $6 \div 18 = \frac{1}{3}$ minute per page.

Flashcard 29: What distance is traveled at $60\ \text{mi/h}$ for $2$ hours?

Answer: $120$ miles. Multiply speed by time: $60 \times 2 = 120$ miles.

Flashcard 30: What is the constant speed if $\frac{3}{4}$ mile is walked in $\frac{1}{2}$ hour?

Answer: $\frac{3}{2} \text{mi/h}$. Divide distance by time: $\frac{3/4}{1/2} = \frac{3}{2}$ miles per hour.

Flashcard 31: What is the better buy: $9 for $3$ items or $14 for $5$ items?

Answer: $14 for $5$ items. Compare unit prices: $3 vs $2.80 per item; second is cheaper.

Flashcard 32: What is the constant speed in $\text{m/s}$ if you run $400$ m in $80$ s?

Answer: $5\ \text{m/s}$. Divide distance by time: $400 \div 80 = 5$ meters per second.

Flashcard 33: What is the number of miles in $4$ hours at $55$ miles per hour?

Answer: $220$ miles. Multiply speed by time: $55 \times 4 = 220$ miles.

Flashcard 34: What is the formula for unit rate if the rate is $\frac{a}{b}$?

Answer: Unit rate is $\frac{a}{b}$ per $1$ of $b$ units. Shows how to express any rate as amount per one unit.

Flashcard 35: What is the unit rate in hours per lawn for $7$ hours to mow $4$ lawns?

Answer: $\frac{7}{4}$ hours per lawn. Divide hours by lawns: $\frac{7}{4}$ hours per lawn.

Flashcard 36: What is the distance in miles at $12$ miles per hour for $5$ hours?

Answer: $60$ miles. Multiply speed by time: $12 × 5 = 60$ miles.

Flashcard 37: What is the unit rate for $15 for $6$ pounds of rice (dollars per pound)?

Answer: $2.50 per pound. Divide price by pounds: \15 \div 6 = $2.50$ per pound.

Flashcard 38: What is the total cost for $8$ bottles if the unit price is $1.25 per bottle?

Answer: $10. Multiply unit price by quantity: \1.25 × 8 = $10$.

Flashcard 39: What is the unit price in dollars per ounce for $3 for $12$ oz?

Answer: $0.25 per oz. Divide total cost by ounces: \3 ÷ 12 = $0.25$.

Flashcard 40: What is the unit rate in pages per minute for $72$ pages in $6$ minutes?

Answer: $12$ pages per minute. Divide total pages by time: $72 ÷ 6 = 12$ ppm.

Flashcard 41: What is the correct formula for unit rate from $\frac{a}{b}$ (with $b\ne 0$)?

Answer: Unit rate $=\frac{a}{b}$ per $1$ unit of $b$. Shows how to express any ratio as a rate per one unit.

Flashcard 42: What is the better buy: $5 for $2$ lb or $9 for $4$ lb?

Answer: $9 for $4$ lb. Compare unit prices: $2.50/lb vs $2.25/lb.

Flashcard 43: What is the unit rate in items per minute for $45$ items in $9$ minutes?

Answer: $5$ items per minute. Divide total items by time: $45 \div 9 = 5$ items per minute.

Flashcard 44: What is a unit rate, in words?

Answer: A rate with a denominator of $1$ unit. Simplifies comparison by showing the amount per single unit.

Flashcard 45: What is the unit rate for $18$ pages in $6$ minutes (pages per minute)?

Answer: $3$ pages per minute. Divide pages by minutes: $18 \div 6 = 3$ pages per minute.

Flashcard 46: Identify the unit rate: $\frac{42 \text{miles}}{2 \text{hours}}$ simplified.

Answer: $21$ miles per hour. Simplify the fraction: $\frac{42}{2} = 21$ miles per hour.

Flashcard 47: Identify the missing value: at $8$ items per minute, how many items in $6$ minutes?

Answer: $48$ items. Multiply rate by time: $8 \times 6 = 48$ items.

Flashcard 48: What is the constant speed in miles per hour for $60$ miles in $2$ hours?

Answer: $30$ miles per hour. Divide distance by time: $60 ÷ 2 = 30$ mph.

Flashcard 49: What is the number of lawns mowed in $35$ hours at $\frac{4}{7}$ lawns per hour?

Answer: $20$ lawns. Multiply rate by time: $\frac{4}{7} \times 35 = 20$ lawns.

Flashcard 50: What is the better buy: $12 for $8$ lb or $14 for $10$ lb?

Answer: $14 for $10$ lb. Compare unit prices: $1.50/lb vs $1.40/lb.

Flashcard 51: What is the unit price for $12 for $3$ notebooks?

Answer: $4 per notebook. Divide total cost by number of items: \12 \div 3 = $4$.

Flashcard 52: What is the unit rate for $4$ lawns in $7$ hours (hours per lawn)?

Answer: $\frac{7}{4}$ hours per lawn. Divide hours by lawns: $\frac{7}{4}$ hours for each lawn.

Flashcard 53: What is the constant speed in $\text{mi/h}$ if you travel $150$ miles in $3$ hours?

Answer: $50\ \text{mi/h}$. Divide distance by time: $150 \div 3 = 50$ miles per hour.

Flashcard 54: What is the unit rate in lawns per hour for $4$ lawns in $7$ hours?

Answer: $\frac{4}{7}$ lawns per hour. Divide lawns by hours: $\frac{4}{7}$ lawns per hour.

Flashcard 55: What is the meaning of "unit rate" in a ratio such as \frac{\6}{3\text{ lb}}$?

Answer: A rate per $1$ unit of the second quantity. The rate when the denominator equals 1.

Flashcard 56: What is the gallons used in $3$ hours at $2.5$ gallons per hour?

Answer: $7.5$ gallons. Multiply rate by time: $2.5 \times 3 = 7.5$ gallons.

Flashcard 57: What is the distance formula using constant speed $s$ and time $t$?

Answer: $d=s\cdot t$. Distance equals speed times time.

Flashcard 58: What is the distance traveled at $60$ mph for $2$ hours?

Answer: $120$ miles. Multiply speed by time: $60 \times 2 = 120$ miles.