Using Two-Way Tables for Probability - Statistics and Probability

  1. What is the definition of a two-way frequency table?
    A table of counts for data classified by two categorical variables. Shows frequencies for combinations of two categorical variables.
  2. Find P(A∩B)P(A\cap B) if the cell count for (A,B)(A,B) is 1818 out of a grand total of 120120.
    18120=0.15\frac{18}{120}=0.15. Apply joint probability formula: cell count over grand total.
  3. Decide if AA and BB are independent when P(A)=0.4P(A)=0.4, P(B)=0.5P(B)=0.5, P(A∩B)=0.2P(A\cap B)=0.2.
    Independent, since 0.4×0.5=0.20.4\times 0.5=0.2. Check if P(A)P(B)=P(A∩B)P(A)P(B) = P(A \cap B).
  4. What equation must hold for events AA and BB to be independent using probabilities?
    P(A∩B)=P(A)P(B)P(A\cap B)=P(A)P(B). Independence means joint probability equals product of marginals.
  5. Find P(B∣A)P(B\mid A) if the count in (A,B)(A,B) is 99 and the total for AA is 3636.
    936=0.25\frac{9}{36}=0.25. Apply conditional formula with AA as the condition.
  6. Find P(B∣A)P(B\mid A) if count(A∩B)=9\text{count}(A\cap B)=9, count(A)=30\text{count}(A)=30.
    930=0.30\frac{9}{30}=0.30. Divide joint count by condition's marginal.
  7. What conditional-probability equality indicates AA and BB are independent (when defined)?
    P(A∣B)=P(A)P(A\mid B)=P(A). Independence means conditioning doesn't change the probability.
  8. What is the complement rule for a conditional probability P(A∣B)P(A\mid B)?
    P(Ac∣B)=1−P(A∣B)P(A^c\mid B)=1-P(A\mid B). Complement probabilities sum to 1 within the conditional space.
  9. Find P(A∣B)P(A\mid B) if count(A∩B)=12\text{count}(A\cap B)=12 and count(B)=40\text{count}(B)=40.
    1240=0.30\frac{12}{40}=0.30. Apply conditional probability formula.
  10. Find P(A)P(A) if the marginal total for AA is 4545 out of a grand total of 150150.
    45150=0.30\frac{45}{150}=0.30. Apply marginal probability formula.
  11. What is the formula for the probability of an event using a marginal total?
    P(A)=marginal total for Agrand totalP(A)=\frac{\text{marginal total for }A}{\text{grand total}}. Divide row/column sum by total count.
  12. Identify the sample space when using a two-way table to model outcomes.
    All table cells (each category pair) plus the grand total as the denominator. Each cell represents an outcome; grand total normalizes probabilities.
  13. What is a row total in a two-way frequency table?
    The sum of counts across a single row. Adds all values in that row to find the row's marginal total.
  14. Compute P(Ac∣B)P(A^c\mid B) if P(A∣B)=0.72P(A\mid B)=0.72.
    1−0.72=0.281-0.72=0.28. Use complement rule: probabilities sum to 1.
  15. What is the difference between joint and conditional probability in a two-way table?
    Joint uses grand total; conditional uses the given category total. Joint divides by all outcomes; conditional divides by given category.
  16. What formula gives the conditional probability P(A∣B)P(A\mid B) from a two-way table?
    P(A∣B)=count in A and Btotal count in BP(A\mid B)=\frac{\text{count in }A\text{ and }B}{\text{total count in }B}. Restricts to condition BB by dividing by BB's total.
  17. Find P(A∣B)P(A\mid B) if the count in (A,B)(A,B) is 77 and the total for BB is 2020.
    720=0.35\frac{7}{20}=0.35. Apply conditional formula: cell count over condition's total.
  18. Find P(A∣B)P(A\mid B) if P(A∩B)=0.18P(A\cap B)=0.18 and P(B)=0.6P(B)=0.6.
    0.180.6=0.30\frac{0.18}{0.6}=0.30. Apply P(A∣B)=P(A∩B)P(B)P(A|B) = \frac{P(A \cap B)}{P(B)}.
  19. What formula gives the joint probability P(A∩B)P(A \cap B) from a two-way table?
    P(A∩B)=count in A and Bgrand totalP(A \cap B)=\frac{\text{count in }A\text{ and }B}{\text{grand total}}. Divides the cell count by grand total for joint probability.
  20. What is a joint frequency in a two-way table?
    A count in an interior cell for a specific pair of categories. Frequency where two specific categories intersect.
  21. Decide if AA and BB are independent if P(A)=0.4P(A)=0.4, P(B)=0.5P(B)=0.5, and P(A∩B)=0.2P(A\cap B)=0.2.
    Independent, since 0.2=0.4×0.50.2=0.4\times 0.5. Check if P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B): 0.2=0.4×0.50.2 = 0.4 \times 0.5 ✓
  22. What formula gives the marginal probability P(A)P(A) from a two-way table?
    P(A)=row or column total for Agrand totalP(A)=\frac{\text{row or column total for }A}{\text{grand total}}. Divides marginal total by grand total for single-event probability.
  23. What condition using probabilities shows events AA and BB are independent?
    P(A∩B)=P(A)P(B)P(A\cap B)=P(A)P(B). Independent events satisfy the multiplication rule.
  24. Decide if AA and BB are independent when P(A)=0.3P(A)=0.3, P(B)=0.6P(B)=0.6, P(A∩B)=0.25P(A\cap B)=0.25.
    Not independent, since 0.3×0.6=0.18≠0.250.3\times 0.6=0.18\ne 0.25. Product 0.180.18 doesn't equal joint probability 0.250.25.
  25. Which equality using conditional probability shows AA and BB are independent?
    P(A∣B)=P(A)P(A\mid B)=P(A). Conditioning doesn't change probability when independent.
  26. What is a two-way frequency table used for when each object has two categorical variables?
    A table of counts for all combinations of two categorical variables. Organizes counts when objects have two categorical attributes.
  27. What is the grand total in a two-way frequency table?
    The sum of all cell counts in the table. Add all interior cells or all marginal totals.
  28. Identify the correct comparison to check independence in a table: compare P(A∣B)P(A\mid B) to what value?
    Compare P(A∣B)P(A\mid B) to P(A)P(A). Equal values indicate independence.
  29. Find P(A)P(A) if the row total for AA is 5454 out of a grand total of 9090.
    5490=0.6\frac{54}{90}=0.6. Marginal probability uses row total over grand total.
  30. What is a marginal total in a two-way table?
    A row or column total showing counts for one variable alone. Sum of all values in that row or column.
  31. What is the formula for conditional probability from a two-way table?
    P(A∣B)=count(A∩B)count(B)P(A\mid B)=\frac{\text{count}(A\cap B)}{\text{count}(B)}. Divide joint count by condition's total count.
  32. Choose the correct interpretation of P(Science∣Grade 10)P(\text{Science}\mid \text{Grade }10) from a two-way table.
    Probability a student prefers Science among only Grade 1010 students. Conditional restricts to Grade 10 subset only.
  33. What is the formula for joint probability using a two-way table cell count?
    P(A∩B)=cell countgrand totalP(A \cap B)=\frac{\text{cell count}}{\text{grand total}}. Divide the cell count by total count for joint probability.
  34. What is a column total in a two-way frequency table?
    The sum of counts down a single column. Adds all values in that column to find the column's marginal total.
  35. Decide if AA and BB are independent if P(A)=0.3P(A)=0.3, P(B)=0.6P(B)=0.6, and P(A∩B)=0.25P(A\cap B)=0.25.
    Not independent, since 0.25≠0.3×0.60.25\ne 0.3\times 0.6. Check if P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B): 0.25≠0.180.25 \ne 0.18 ✗
  36. Find P(A∩B)P(A\cap B) if the cell count for (A,B)(A,B) is 1818 and the grand total is 120120.
    18120=0.15\frac{18}{120}=0.15. Apply joint probability formula: cell/total.
  37. Identify the sample space when a two-way frequency table is used for probability.
    All individuals in the table; total outcomes equal the grand total. Each person counted is one possible outcome.
  38. Find P(A∣B)P(A\mid B) if the count in (A,B)(A,B) is 1212 and the total for BB is 4848.
    1248=0.25\frac{12}{48}=0.25. Apply conditional formula: cell count over condition's total.
  39. Compute the missing cell: grand total 200200, other three cells in a 2×22\times 2 table sum to 155155.
    200−155=45200-155=45. All cells must sum to grand total.

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