Find Expected Value of a Game - Statistics and Probability

  1. Find expected payoff: prizes $0 with 0.90.9, $10 with 0.090.09, $100 with 0.010.01; cost $2.
    −110-\frac{1}{10}. E(X)=0.9(0)+0.09(10)+0.01(100)=1.9E(X)=0.9(0)+0.09(10)+0.01(100)=1.9, minus 22.
  2. A game pays $4 with probability 0.30.3 and $1 with probability 0.70.7. Find expected payoff.
    $1.90. E=4(0.3)+1(0.7)=1.2+0.7=1.9E = 4(0.3) + 1(0.7) = 1.2 + 0.7 = 1.9
  3. A fast-food promo gives $0 with probability 0.80.8 and $5 with probability 0.20.2. Find E(W)E(W).
    $1. E=0(0.8)+5(0.2)=0+1=1E = 0(0.8) + 5(0.2) = 0 + 1 = 1
  4. State the formula for expected value E(X)E(X) for outcomes xix_i with probabilities pip_i.
    E(X)=∑xipiE(X)=\sum x_i p_i. Sum each outcome times its probability.
  5. What is the expected payoff for outcomes $3, $0, −$1\$3,\ \$0,\ -\$1 with probabilities 0.2, 0.5, 0.30.2,\ 0.5,\ 0.3?
    $0.3. E=3(0.2)+0(0.5)+(−1)(0.3)=0.6+0−0.3E = 3(0.2) + 0(0.5) + (-1)(0.3) = 0.6 + 0 - 0.3
  6. What is the expected payoff if you win $5 with probability 14\frac{1}{4}, otherwise $0?
    $1.25. E=5⋅14+0⋅34=1.25E = 5 \cdot \frac{1}{4} + 0 \cdot \frac{3}{4} = 1.25
  7. Find the expected payoff: win $10 with p=15p=\frac{1}{5}, otherwise 00; ticket costs $1.
    11. E(payoff)=15(10)−1=1E(\text{payoff})=\frac{1}{5}(10)-1=1.
  8. Find the expected payoff: win $5 with p=14p=\frac{1}{4}, otherwise 00; ticket costs $2.
    −34-\frac{3}{4}. E(payoff)=14(5)−2=−34E(\text{payoff})=\frac{1}{4}(5)-2=-\frac{3}{4}.
  9. Identify the expected payoff: win $4 with p=13p=\frac{1}{3}, win $1 with p=23p=\frac{2}{3} (no cost).
    22. E(payoff)=13(4)+23(1)=2E(\text{payoff})=\frac{1}{3}(4)+\frac{2}{3}(1)=2.
  10. Identify the fair ticket price cc in terms of expected winnings E(W)E(W).
    Fair price: c=E(W)c=E(W). Fair when expected winnings equal cost.
  11. Find the expected payoff: win $50 with p=0.02p=0.02, otherwise 00; ticket costs $1.
    00. E(payoff)=0.02(50)−1=0E(\text{payoff})=0.02(50)-1=0.
  12. Find the expected net gain if a ticket costs $2 and pays $10 with probability 0.10.1, else $0.
    −$1-\$1. E=10(0.1)+0(0.9)−2=1−2=−1E = 10(0.1) + 0(0.9) - 2 = 1 - 2 = -1
  13. What is the expected net gain if expected winnings are E(W)E(W) and the ticket costs cc?
    E(net)=E(W)−cE(\text{net})=E(W)-c. Subtract the cost from expected winnings.
  14. Choose the correct method to compute expected payoff from a payoff table of (xi,pi)(x_i,p_i) values.
    Compute ∑xipi\sum x_i p_i. Multiply outcomes by probabilities and sum.
  15. State the linearity rule for expected value: E(aX+b)E(aX+b) in terms of E(X)E(X).
    E(aX+b)=aE(X)+bE(aX+b)=aE(X)+b. Scale by aa and shift by bb.
  16. What is the probability of winning if 11 prize ticket is in a box of NN tickets?
    1N\frac{1}{N}. One winning ticket out of NN total tickets.
  17. Find the expected payoff: win $3 with p=12p=\frac{1}{2}, lose $1 with p=12p=\frac{1}{2}.
    11. E(payoff)=12(3)+12(−1)=1E(\text{payoff})=\frac{1}{2}(3)+\frac{1}{2}(-1)=1.
  18. Find the fair ticket cost cc: win $5 with p=0.3p=0.3, otherwise 00.
    1.51.5. Set 0.3(5)−c=00.3(5)-c=0, solve for cc.
  19. State the formula for expected value E(X)E(X) for outcomes xix_i with probabilities pip_i.
    E(X)=∑xipiE(X)=\sum x_i p_i. Sum each outcome times its probability.
  20. What is the expected payoff if you win amount ww with probability pp and otherwise win 00, with cost cc?
    pw−cpw-c. Expected value of winning minus cost.
  21. Choose the expected net gain if cost is $1 and payout is $3 with probability 12\frac{1}{2}, else $0.
    $0.50. E=3⋅12−1=1.5−1=0.50E = 3 \cdot \frac{1}{2} - 1 = 1.5 - 1 = 0.50
  22. A game pays $6 with probability 13\frac{1}{3}, $0 with probability 23\frac{2}{3}. Find fair price.
    $2. Fair price equals expected value: 6⋅13=26 \cdot \frac{1}{3} = 2
  23. Find the ticket cost cc for a fair game: win $12 with p=16p=\frac{1}{6}, otherwise 00.
    22. Set 16(12)−c=0\frac{1}{6}(12)-c=0, solve for cc.
  24. Find E(X)E(X): outcomes $-2 with p=34p=\frac{3}{4} and $6 with p=14p=\frac{1}{4}.
    00. E(X)=34(−2)+14(6)=0E(X)=\frac{3}{4}(-2)+\frac{1}{4}(6)=0.
  25. What is the expected payoff if payoff =X−c=X-c where cc is the ticket cost?
    E(payoff)=E(X)−cE(\text{payoff})=E(X)-c. Subtract cost from expected winnings.
  26. What is the expected value of a constant random variable X=kX=k?
    E(X)=kE(X)=k. Expected value of a constant is the constant itself.
  27. A raffle has 200200 tickets at $2 each and one prize of $250. Find expected net gain per ticket.
    −$0.75-\$0.75. E=250200−2=1.25−2=−0.75E = \frac{250}{200} - 2 = 1.25 - 2 = -0.75
  28. Find the missing probability pp if outcomes are $5 with probability pp and $0 with probability 0.60.6.
    p=0.4p=0.4. Probabilities sum to 11: p+0.6=1p + 0.6 = 1
  29. Identify whether the game is favorable: cost $2, payout $9 with probability 0.20.2, else $0.
    Unfavorable since E(net)=−$0.20E(\text{net})=-\$0.20. E=9(0.2)−2=1.8−2=−0.20<0E = 9(0.2) - 2 = 1.8 - 2 = -0.20 < 0
  30. What is the expected payoff if a game pays aa with probability pp and bb with probability 1−p1-p?
    E=ap+b(1−p)E=ap+b(1-p). Multiply each payout by its probability and sum.
  31. Identify whether the game is favorable to the player if E(payoff)>0E(\text{payoff})>0.
    Favorable to the player. Positive expected payoff benefits the player.
  32. A ticket costs $2. Prizes: $0 with 0.80.8, $5 with 0.150.15, $20 with 0.050.05. Find expected payoff.
    −14-\frac{1}{4}. E(X)=0.8(0)+0.15(5)+0.05(20)=1.75E(X)=0.8(0)+0.15(5)+0.05(20)=1.75, minus cost 22.
  33. A game pays $8 with probability 15\frac{1}{5} and costs $1 to play. Find expected net gain.
    $0.60. E=8⋅15−1=1.6−1=0.60E = 8 \cdot \frac{1}{5} - 1 = 1.6 - 1 = 0.60
  34. Find E(X)E(X) if XX is $20 with probability 150\frac{1}{50} and $0 otherwise.
    $0.40. E=20⋅150+0⋅4950=0.40E = 20 \cdot \frac{1}{50} + 0 \cdot \frac{49}{50} = 0.40
  35. A prize box has 33 cards worth $2 and 77 cards worth $0. Find expected payoff per draw.
    $0.60. E=3⋅2+7⋅010=610=0.60E = \frac{3 \cdot 2 + 7 \cdot 0}{10} = \frac{6}{10} = 0.60
  36. Find E(X)E(X): outcomes $0 with p=0.7p=0.7 and $10 with p=0.3p=0.3.
    33. E(X)=0.7(0)+0.3(10)=3E(X)=0.7(0)+0.3(10)=3.
  37. Identify the fair-game condition in terms of expected payoff.
    Fair game means E(payoff)=0E(\text{payoff})=0. Expected gain equals expected loss.

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