Developing Theoretical Probability Distributions, Expected Value - Statistics and Probability

  1. State the expected value formula for X∼Binomial(n,p)X\sim\text{Binomial}(n,p).
    E(X)=npE(X)=np. Mean of binomial distribution is number of trials times success probability.
  2. What is the expected value of a constant random variable X=cX=c?
    E(X)=cE(X)=c. A constant has no variability, so its expected value equals itself.
  3. What is P(X=1)P(X=1) for X∼Binomial(5,14)X\sim\text{Binomial}(5,\frac{1}{4})?
    (51)(14)(34)4\binom{5}{1}\left(\frac{1}{4}\right)\left(\frac{3}{4}\right)^4. Uses binomial formula with n=5n=5, k=1k=1, p=14p=\frac{1}{4}.
  4. What is the theoretical probability of a correct guess on a 44-choice multiple-choice question?
    14\frac{1}{4}. One correct choice out of four equally likely options.
  5. State the expected value for X∼Binomial(n,p)X\sim\text{Binomial}(n,p).
    E(X)=npE(X)=np. Average number of successes equals trials times success probability.
  6. What is P(X=0)P(X=0) when guessing on 55 questions with p=14p=\frac{1}{4}?
    (34)5\left(\frac{3}{4}\right)^5. All 5 wrong: (1−p)5(1-p)^5 where p=14p=\frac{1}{4}.
  7. What is P(X=5)P(X=5) when guessing on 55 questions with p=14p=\frac{1}{4}?
    (14)5\left(\frac{1}{4}\right)^5. All 5 correct: p5p^5 where p=14p=\frac{1}{4}.
  8. State the linearity rule for expected value: what is E(aX+b)E(aX+b)?
    E(aX+b)=aE(X)+bE(aX+b)=aE(X)+b. Constants factor out; adding bb shifts expected value by bb.
  9. Which expression gives P(X≥3)P(X\ge 3) for X∼Binomial(5,14)X\sim\text{Binomial}(5,\frac{1}{4})?
    1−[P(X=0)+P(X=1)+P(X=2)]1-[P(X=0)+P(X=1)+P(X=2)]. Complement rule: P(X≥3)=1−P(X≤2)P(X\ge 3)=1-P(X\le 2).
  10. What is the expected score if each correct answer is worth 22 points and XX is # correct?
    E(2X)=2E(X)E(2X)=2E(X). Linearity of expectation: constant multiplier scales the expected value.
  11. State the binomial probability formula for P(X=k)P(X=k) when X∼Binomial(n,p)X\sim\text{Binomial}(n,p).
    P(X=k)=(nk)pk(1−p)n−kP(X=k)=\binom{n}{k}p^k(1-p)^{n-k}. Counts ways to get kk successes times probability of each arrangement.
  12. Find E(X)E(X) if X∈{0,1,2}X\in\{0,1,2\} with P(0)=0.2P(0)=0.2, P(1)=0.5P(1)=0.5, P(2)=0.3P(2)=0.3.
    E(X)=0(0.2)+1(0.5)+2(0.3)=1.1E(X)=0(0.2)+1(0.5)+2(0.3)=1.1. Multiply each value by its probability and sum: 0.5+0.6=1.10.5+0.6=1.1.
  13. What two conditions must a probability distribution satisfy for values xix_i with probabilities pip_i?
    pi≥0p_i \ge 0 and ∑pi=1\sum p_i = 1. Probabilities must be non-negative and sum to 1 for a valid distribution.
  14. If score is S=2XS=2X, what is E(S)E(S) in terms of E(X)E(X)?
    E(S)=2E(X)E(S)=2E(X). Expected value scales linearly with constant multiplier.
  15. If each correct is +4+4 points and wrong is 00, what is expected score for 55 questions with p=14p=\frac{1}{4}?
    E(S)=4⋅54=5E(S)=4\cdot\frac{5}{4}=5. Score is 4X4X, so E(S)=4E(X)=4⋅54E(S)=4E(X)=4\cdot\frac{5}{4}.
  16. What is P(X=5)P(X=5) for guessing on 55 questions with p=14p=\frac{1}{4}?
    (14)5\left(\frac{1}{4}\right)^5. All 5 correct means p5p^5 where p=14p=\frac{1}{4}.
  17. What is the expected number correct when guessing on 55 questions with p=14p=\frac{1}{4}?
    E(X)=5⋅14=54E(X)=5\cdot\frac{1}{4}=\frac{5}{4}. For binomial, expected value equals npnp.
  18. What is P(X=4)P(X=4) for X∼Binomial(5,14)X\sim\text{Binomial}(5,\frac{1}{4})?
    (54)(14)4(34)\binom{5}{4}\left(\frac{1}{4}\right)^4\left(\frac{3}{4}\right). Uses binomial formula with n=5n=5, k=4k=4, p=14p=\frac{1}{4}.
  19. What two conditions must a probability distribution for discrete XX satisfy?
    0≤P(X=x)≤10 \le P(X=x) \le 1 and ∑P(X=x)=1\sum P(X=x)=1. Probabilities must be between 0 and 1, and sum to 1 for all outcomes.
  20. What is P(X=0)P(X=0) for guessing on 55 questions with p=14p=\frac{1}{4}?
    (34)5\left(\frac{3}{4}\right)^5. All 5 wrong means (1−p)5(1-p)^5 where p=14p=\frac{1}{4}.
  21. What is the expected score for scheme S=1X+0(5−X)S=1X+0(5-X) when guessing on 55 with p=14p=\frac{1}{4}?
    E(S)=E(X)=54E(S)=E(X)=\frac{5}{4}. Only correct answers score, so S=XS=X and E(S)=E(X)E(S)=E(X).
  22. What is the expected score for 55 questions, 22 points each correct, guessing with p=14p=\frac{1}{4}?
    2⋅54=522\cdot\frac{5}{4}=\frac{5}{2}. Apply E(2X)=2E(X)E(2X)=2E(X) with E(X)=54E(X)=\frac{5}{4}.
  23. Identify the distribution of XX = number correct when guessing on nn independent questions with success prob pp.
    X∼Binomial(n,p)X\sim\text{Binomial}(n,p). Counting successes in nn independent trials follows binomial distribution.
  24. If each correct is +1+1 and each wrong is −13-\frac{1}{3}, what is expected score for 55 questions with p=14p=\frac{1}{4}?
    5(14−13⋅34)=05\left(\frac{1}{4}-\frac{1}{3}\cdot\frac{3}{4}\right)=0. Expected gain per question is 1⋅p−13(1−p)=01\cdot p-\frac{1}{3}(1-p)=0 when p=14p=\frac{1}{4}.
  25. State the linearity rule for expected value of Y=aX+bY=aX+b.
    E(Y)=aE(X)+bE(Y)=aE(X)+b. Linear transformations scale and shift the expected value accordingly.
  26. If each correct is +1+1 point and no penalty, what is expected score for 55 questions with p=14p=\frac{1}{4}?
    E(S)=E(X)=54E(S)=E(X)=\frac{5}{4}. Score equals number correct, so E(S)=E(X)=npE(S)=E(X)=np.
  27. What is P(X=2)P(X=2) for X∼Binomial(5,14)X\sim\text{Binomial}(5,\frac{1}{4})?
    (52)(14)2(34)3\binom{5}{2}\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3. Uses binomial formula with n=5n=5, k=2k=2, p=14p=\frac{1}{4}.
  28. What is P(X=2)P(X=2) for guessing on 55 questions with p=14p=\frac{1}{4}?
    (52)(14)2(34)3\binom{5}{2}\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3. Choose 2 positions for successes, multiply by p2p^2 and (1−p)3(1-p)^3.
  29. What is P(X=3)P(X=3) for X∼Binomial(5,14)X\sim\text{Binomial}(5,\frac{1}{4})?
    (53)(14)3(34)2\binom{5}{3}\left(\frac{1}{4}\right)^3\left(\frac{3}{4}\right)^2. Uses binomial formula with n=5n=5, k=3k=3, p=14p=\frac{1}{4}.
  30. Identify the distribution of XX = number correct when guessing on nn 4-choice questions.
    X∼Binomial(n,14)X\sim\text{Binomial}(n,\frac{1}{4}). Counting successes in nn independent trials with success probability 14\frac{1}{4}.
  31. What is P(X=1)P(X=1) for guessing on 55 questions with p=14p=\frac{1}{4}?
    (51)(14)(34)4\binom{5}{1}\left(\frac{1}{4}\right)\left(\frac{3}{4}\right)^4. Choose 1 position for success, multiply by pp and (1−p)4(1-p)^4.
  32. State the formula for the expected value E(X)E(X) of a discrete random variable.
    E(X)=∑xipiE(X)=\sum x_i p_i. Sum each outcome times its probability to find the average value.
  33. What is the expected number correct when guessing on 55 questions with p=14p=\frac{1}{4}?
    E(X)=5⋅14=54E(X)=5\cdot\frac{1}{4}=\frac{5}{4}. For binomial, E(X)=np=5⋅14E(X)=np=5\cdot\frac{1}{4}.
  34. What is the expected percent score if percent =20X=20X for 55 questions and p=14p=\frac{1}{4}?
    E(20X)=20⋅54=25E(20X)=20\cdot\frac{5}{4}=25. Each correct is worth 20%, so multiply expected correct by 20.
  35. State the binomial probability formula for P(X=k)P(X=k) when X∼Binomial(n,p)X\sim\text{Binomial}(n,p).
    P(X=k)=(nk)pk(1−p)n−kP(X=k)=\binom{n}{k}p^k(1-p)^{n-k}. Gives probability of exactly kk successes in nn trials.
  36. State the formula for the expected value of a discrete random variable XX.
    E(X)=∑x P(X=x)E(X)=\sum x\,P(X=x). Sum each outcome value times its probability.
  37. What is P(correct)P(\text{correct}) when guessing on one 4-choice multiple-choice question?
    14\frac{1}{4}. One correct choice out of four equally likely options.

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