Applying the Addition Rule for Probability - Statistics and Probability

  1. What is the equivalent notation statement for P(A and B)P(A\text{ and }B) using the intersection symbol?
    P(A∩B)P(A\cap B). Intersection symbol represents outcomes in both events.
  2. What is P(A or B)P(A\text{ or }B) if events AA and BB are mutually exclusive?
    P(A or B)=P(A)+P(B)P(A\text{ or }B)=P(A)+P(B). Mutually exclusive means no overlap, so P(A and B)=0P(A\text{ and }B)=0.
  3. State the Addition Rule formula for P(A or B)P(A\text{ or }B) in terms of P(A)P(A), P(B)P(B), and P(A and B)P(A\text{ and }B).
    P(A or B)=P(A)+P(B)−P(A and B)P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B). Subtracts overlap to avoid counting shared outcomes twice.
  4. Identify the error: A student used P(A or B)=P(A)+P(B)P(A\text{ or }B)=P(A)+P(B) when P(A and B)≠0P(A\text{ and }B)\neq 0.
    Missing subtraction of P(A and B)P(A\text{ and }B). Must subtract overlap when events aren't disjoint.
  5. Find P(A or B)P(A\text{ or }B) if P(A)=14P(A)=\frac{1}{4}, P(B)=13P(B)=\frac{1}{3}, and P(A and B)=112P(A\text{ and }B)=\frac{1}{12}.
    12\frac{1}{2}. 14+13−112=3+4−112=12\frac{1}{4}+\frac{1}{3}-\frac{1}{12}=\frac{3+4-1}{12}=\frac{1}{2}.
  6. What value does the Addition Rule subtract to correct for double counting in P(A or B)P(A\text{ or }B)?
    P(A and B)P(A\text{ and }B). Removes the overlap where both events occur together.
  7. Find P(A and B)P(A\text{ and }B) if P(A)=0.55P(A)=0.55, P(B)=0.30P(B)=0.30, and P(A or B)=0.70P(A\text{ or }B)=0.70.
    0.150.15. 0.55+0.30−0.70=0.150.55+0.30-0.70=0.15 by rearranging.
  8. What is the equivalent notation statement for P(A or B)P(A\text{ or }B) using the union symbol?
    P(A∪B)P(A\cup B). Union symbol represents the set of outcomes in either event.
  9. Identify the condition that makes P(A and B)=0P(A \text{ and } B)=0 in the Addition Rule.
    AA and BB are mutually exclusive (disjoint). Events can't happen simultaneously.
  10. State the Addition Rule formula for P(A or B)P(A \text{ or } B) in terms of P(A)P(A), P(B)P(B), and P(A and B)P(A \text{ and } B).
    P(A or B)=P(A)+P(B)−P(A and B)P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B). Subtract overlap to avoid counting twice.
  11. Find P(A or B)P(A\text{ or }B) if AA and BB are mutually exclusive with P(A)=0.18P(A)=0.18 and P(B)=0.22P(B)=0.22.
    0.400.40. Mutually exclusive: just add 0.18+0.22=0.400.18+0.22=0.40.
  12. Which probability is subtracted in P(A or B)=P(A)+P(B)−□P(A\text{ or }B)=P(A)+P(B)-\square to avoid double counting?
    P(A and B)P(A\text{ and }B). Overlap is counted in both P(A)P(A) and P(B)P(B).
  13. Find P(A or B)P(A\text{ or }B) if A⊆BA\subseteq B, P(A)=0.20P(A)=0.20, and P(B)=0.60P(B)=0.60.
    0.600.60. Since A⊆BA\subseteq B, A∪B=BA\cup B=B.
  14. Choose the correct statement: If A⊆BA\subseteq B, what is P(A or B)P(A\text{ or }B) equal to?
    P(B)P(B). If AA is subset of BB, union equals BB.
  15. Find P(A or B)P(A\text{ or }B) given P(A)=0.25P(A)=0.25, P(B)=0.50P(B)=0.50, and P(A and B)=0.05P(A\text{ and }B)=0.05.
    0.700.70. Apply: 0.25+0.50−0.05=0.700.25+0.50-0.05=0.70.
  16. Find P(A and B)P(A\text{ and }B) if P(A)=0.48P(A)=0.48, P(B)=0.52P(B)=0.52, and P(A or B)=0.80P(A\text{ or }B)=0.80.
    0.200.20. 0.48+0.52−0.80=0.200.48+0.52-0.80=0.20 by rearranging.
  17. Find P(B)P(B) given P(A)=0.35P(A)=0.35, P(A and B)=0.15P(A\text{ and }B)=0.15, and P(A or B)=0.65P(A\text{ or }B)=0.65.
    0.450.45. Rearrange: P(B)=0.65−0.35+0.15=0.45P(B)=0.65-0.35+0.15=0.45.
  18. Find P(A or B)P(A\text{ or }B) given P(A)=0.40P(A)=0.40, P(B)=0.30P(B)=0.30, and P(A and B)=0.10P(A\text{ and }B)=0.10.
    0.600.60. Apply: 0.40+0.30−0.10=0.600.40+0.30-0.10=0.60.
  19. Find P(A or B)P(A\text{ or }B) if P(A)=0.40P(A)=0.40, P(B)=0.35P(B)=0.35, and P(A and B)=0.10P(A\text{ and }B)=0.10.
    0.650.65. 0.40+0.35−0.10=0.650.40+0.35-0.10=0.65 by Addition Rule.
  20. Find P(A and B)P(A\text{ and }B) if AA and BB are independent with P(A)=0.20P(A)=0.20 and P(B)=0.50P(B)=0.50.
    0.100.10. Independent events: multiply 0.20(0.50)=0.100.20(0.50)=0.10.
  21. What is the meaning of P(A or B)P(A \text{ or } B) in words (inclusive or)?
    Probability that at least one of AA or BB occurs. Union includes either or both events.
  22. What is the formula for P(A or B)P(A \text{ or } B) when AA and BB are mutually exclusive?
    P(A or B)=P(A)+P(B)P(A\text{ or }B)=P(A)+P(B). No overlap when events can't occur together.
  23. Find P(A or B)P(A\text{ or }B) given counts: ∣A∣=30|A|=30, ∣B∣=25|B|=25, ∣A∩B∣=10|A\cap B|=10, total N=100N=100.
    0.450.45. Count unique: (30+25−10)/100=45/100=0.45(30+25-10)/100=45/100=0.45.
  24. Find P(A and B)P(A\text{ and }B) given P(A)=0.60P(A)=0.60, P(B)=0.50P(B)=0.50, and P(A or B)=0.80P(A\text{ or }B)=0.80.
    0.300.30. Rearrange: P(A and B)=0.60+0.50−0.80=0.30P(A\text{ and }B)=0.60+0.50-0.80=0.30.
  25. Find P(A)P(A) given P(B)=0.55P(B)=0.55, P(A and B)=0.20P(A\text{ and }B)=0.20, and P(A or B)=0.75P(A\text{ or }B)=0.75.
    0.400.40. Rearrange: P(A)=0.75−0.55+0.20=0.40P(A)=0.75-0.55+0.20=0.40.
  26. Find P(A and B)P(A\text{ and }B) if P(A)=35P(A)=\frac{3}{5}, P(B)=12P(B)=\frac{1}{2}, and P(A or B)=45P(A\text{ or }B)=\frac{4}{5}.
    310\frac{3}{10}. 35+12−45=6+5−810=310\frac{3}{5}+\frac{1}{2}-\frac{4}{5}=\frac{6+5-8}{10}=\frac{3}{10}.
  27. Interpretation check: If P(A or B)=0.72P(A\text{ or }B)=0.72, what does 0.720.72 represent in context?
    Chance that at least one of AA or BB occurs. Probability that event AA or event BB happens.
  28. What condition on probabilities indicates that AA and BB are mutually exclusive?
    P(A and B)=0P(A\text{ and }B)=0. Events cannot occur together when mutually exclusive.
  29. Find P(A∪B)P(A\cup B) from a table where P(A)=0.52P(A)=0.52, P(B)=0.27P(B)=0.27, and P(A∩B)=0.12P(A\cap B)=0.12.
    0.670.67. Apply: 0.52+0.27−0.12=0.670.52+0.27-0.12=0.67.
  30. What is the complement form for P(A or B)P(A\text{ or }B) using P(Ac and Bc)P(A^c\text{ and }B^c)?
    P(A or B)=1−P(Ac and Bc)P(A\text{ or }B)=1-P(A^c\text{ and }B^c). By De Morgan's law: at least one occurs = not both fail.
  31. What is the meaning of P(A and B)P(A \text{ and } B) in words?
    Probability that both AA and BB occur. The intersection of events AA and BB.
  32. Find P(A or B)P(A\text{ or }B) if P(A)=0.20P(A)=0.20, P(B)=0.50P(B)=0.50, and AA and BB are mutually exclusive.
    0.700.70. 0.20+0.50−0=0.700.20+0.50-0=0.70 since mutually exclusive.
  33. Find P(A or B)P(A\text{ or }B) if AA and BB are independent with P(A)=0.30P(A)=0.30 and P(B)=0.40P(B)=0.40.
    0.580.58. Apply: 0.30+0.40−0.30(0.40)=0.580.30+0.40-0.30(0.40)=0.58.
  34. What is the formula for P(A and B)P(A \text{ and } B) rewritten from the Addition Rule?
    P(A and B)=P(A)+P(B)−P(A or B)P(A\text{ and }B)=P(A)+P(B)-P(A\text{ or }B). Rearrange the Addition Rule by solving for P(A and B)P(A\text{ and }B).
  35. Find P(A or B)P(A\text{ or }B) if P(A)=0.15P(A)=0.15, P(B)=0.10P(B)=0.10, and P(A and B)=0P(A\text{ and }B)=0.
    0.250.25. 0.15+0.10−0=0.250.15+0.10-0=0.25 for disjoint events.
  36. Identify the correct expression for P(A or B)P(A\text{ or }B) when AA and BB are independent.
    P(A or B)=P(A)+P(B)−P(A)P(B)P(A\text{ or }B)=P(A)+P(B)-P(A)P(B). For independent events, P(A and B)=P(A)P(B)P(A\text{ and }B)=P(A)P(B).
  37. Find and correct the error: P(A or B)=P(A)+P(B)+P(A and B)P(A\text{ or }B)=P(A)+P(B)+P(A\text{ and }B).
    Correct: P(A or B)=P(A)+P(B)−P(A and B)P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B). Should subtract, not add, the intersection term.
  38. Find P(A or B)P(A\text{ or }B) if P(A)=0.90P(A)=0.90, P(B)=0.30P(B)=0.30, and P(A and B)=0.25P(A\text{ and }B)=0.25.
    0.950.95. 0.90+0.30−0.25=0.950.90+0.30-0.25=0.95 by Addition Rule.
  39. Find P(A or B)P(A\text{ or }B) from counts: n(A)=25n(A)=25, n(B)=30n(B)=30, n(A∩B)=10n(A\cap B)=10, total n=60n=60.
    34\frac{3}{4}. 25+30−1060=4560=34\frac{25+30-10}{60}=\frac{45}{60}=\frac{3}{4}.
  40. Which inequality must always be true for valid events: P(A or B)≤ ?P(A\text{ or }B)\leq \ ?
    P(A or B)≤1P(A\text{ or }B)\leq 1. Probability cannot exceed 1 (certainty).

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