Percent Increase and Decrease - SSAT Upper Level Quantitative

  1. State the formula for the percent change from an original value OO to a new value NN.
    N−OO×100%\frac{N-O}{O}\times 100\%. Calculates the relative change by dividing the difference by the original value and multiplying by 100 to express as a percentage.
  2. A price is discounted 30%30\% and then discounted 20%20\%. What single discount percent is equivalent?
    44%44\%. The equivalent single discount is 100%−(0.7×0.8)×100%100\% - (0.7 \times 0.8) \times 100\%, yielding 44%.
  3. What percent decrease takes 120120 down to 9696?
    20%20\%. Divide the decrease by the original value and multiply by 100 to determine the percentage reduction.
  4. State the multiplier for increasing a value by p%p\%.
    1+p1001+\frac{p}{100}. Represents the factor by which the original value is scaled to include the percentage increase.
  5. A 35%35\% discount is followed by a 35%35\% markup on the discounted price. What is the net percent change?
    −12.25%-12.25\%. The overall multiplier 0.65×1.35=0.87750.65 \times 1.35 = 0.8775 indicates a 12.25% decrease from the original.
  6. What is the percent decrease from 9090 to 7272?
    20%20\%. Divide the decrease by the original value and multiply by 100 to find the percentage change.
  7. What is the final value after increasing 200200 by 15%15\% and then increasing the result by 10%10\%?
    253253. Successive application of multipliers 1.151.15 and 1.11.1 to the original value gives the final result.
  8. What discount percent from original price OO to sale price SS? (Express in terms of OO and SS.)
    O−SO×100%\frac{O-S}{O}\times 100\%. Discount percentage is the reduction relative to the original price, computed as the difference over original times 100%.
  9. What is the percent increase from 5050 to 6565?
    30%30\%. Divide the increase by the original value and multiply by 100 to find the percentage change.
  10. What percent increase takes 4040 up to 5050?
    25%25\%. Divide the increase by the original value and multiply by 100 to determine the percentage growth.
  11. A quantity decreases from yy to 0.6y0.6y. What is the percent decrease?
    40%40\%. The decrease of 0.4y0.4y relative to the original yy corresponds to a 40% change.
  12. A quantity increases from xx to 1.5x1.5x. What is the percent increase?
    50%50\%. The increase of 0.5x0.5x relative to the original xx corresponds to a 50% change.
  13. What is the new value if 8080 is increased by 25%25\%?
    100100. Apply the multiplier 1.251.25 to the original value to compute the increased amount.
  14. A shirt costs $48 after a 20%20\% discount. What was the original price?
    $60. Divide the discounted price by the retention rate 0.80.8 to recover the original price.
  15. What markup percent from cost CC gives selling price SS? (Express in terms of CC and SS.)
    S−CC×100%\frac{S-C}{C}\times 100\%. Markup percentage is the profit relative to cost, computed as the difference over cost times 100%.
  16. A price is increased by 10%10\% and then decreased by 10%10\%. What is the net percent change?
    −1%-1\%. The successive multipliers 1.11.1 and 0.90.9 yield an overall factor of 0.990.99, indicating a 1% decrease.
  17. After a 25%25\% decrease, a value is 150150. What was the original value?
    200200. Divide the decreased value by the retention rate 0.750.75 to find the original value.
  18. A price is increased 30%30\% and then increased 20%20\%. What single increase percent is equivalent?
    56%56\%. The equivalent single increase is (1.3×1.2−1)×100%(1.3 \times 1.2 - 1) \times 100\%, yielding 56%.
  19. What is the overall percent change after increases of 20%20\% and 30%30\% applied successively?
    56%56\%. The combined multiplier 1.2×1.3=1.561.2 \times 1.3 = 1.56 corresponds to a 56% increase from the original.
  20. A value is multiplied by 1.21.2 and then by 0.750.75. What is the overall percent change?
    −10%-10\%. The product of the multipliers 1.21.2 and 0.750.75 is 0.90.9, representing a 10% decrease overall.
  21. A number is decreased by 20%20\% and then increased by 25%25\%. What is the net percent change?
    0%0\%. The multipliers 0.80.8 and 1.251.25 product to 11, resulting in no net percentage change.
  22. What is the new value if 6060 is decreased by 15%15\%?
    5151. Apply the multiplier 0.850.85 to the original value to compute the decreased amount.
  23. A value becomes 8484 after a 40%40\% increase. What was the original value?
    6060. Divide the new value by the growth factor 1.41.4 to find the original value before the increase.
  24. State the multiplier for decreasing a value by p%p\%.
    1−p1001-\frac{p}{100}. Represents the factor by which the original value is scaled to account for the percentage decrease.
  25. What is the overall percent change after decreases of 20%20\% and 30%30\% applied successively?
    −44%-44\%. The combined multiplier 0.8×0.7=0.560.8 \times 0.7 = 0.56 corresponds to a 44% decrease from the original.

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