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\( x \)
\( 7 \)
\( = \)

One-Step
Equations

Learn to isolate a variable using a single inverse operation: the foundation of all equation solving.

SSAT Middle Level: Quantitative

What Is an Equation?

An equation is a mathematical statement that says two expressions are equal. The equals sign \( = \) acts like a balance point: whatever is on the left side must have the same value as what is on the right side.

\( x + 3 \)
\( 10 \)
\( = \)

What Is a Variable?

A variable is a letter (like \( x \), \( y \), or \( n \)) that stands in for a number we don't know yet. In a one-step equation, our goal is to figure out what number the variable represents.

\( x + 5 = 12 \)
\( x \) is the variable. What number plus 5 equals 12?
\( 3n = 21 \)
\( n \) is the variable. What number times 3 equals 21?

What Makes It "One-Step"?

A one-step equation requires exactly one operation to isolate the variable. The variable has only one thing "attached" to it: addition, subtraction, multiplication, or division.

Addition
\( x + 4 = 9 \)
Subtraction
\( y - 6 = 2 \)
Multiplication
\( 5n = 35 \)
Division
\( \frac{m}{4} = 3 \)

The Golden Rule of Equations

Whatever you do to one side, you MUST do to the other side. (This keeps the equation balanced.)

Inverse Operations

To isolate the variable, we use the inverse (opposite) operation to undo whatever is being done to it. Each operation has a partner that cancels it out.

Operation Inverse Example
Addition (\( + \)) Subtraction (\( - \)) \( x + 4 = 9 \) → subtract 4
Subtraction (\( - \)) Addition (\( + \)) \( x - 3 = 7 \) → add 3
Multiplication (\( \times \)) Division (\( \div \)) \( 5x = 20 \) → divide by 5
Division (\( \div \)) Multiplication (\( \times \)) \( \frac{x}{6} = 3 \) → multiply by 6

Equations vs Expressions

Students often confuse these two. An expression is a math phrase with no equals sign. An equation always has an equals sign connecting two sides.

Expression
\( 3x + 7 \)
No equals sign. You simplify it, but you cannot "solve" it for a single answer.
Equation
\( 3x + 7 = 22 \)
Has an equals sign. You can solve it to find \( x \).

How to Solve in One Step

1
Identify the operation being done to the variable. Is it addition, subtraction, multiplication, or division?
2
Apply the inverse operation to both sides of the equation. This "undoes" the operation and isolates the variable.
3
Simplify both sides. The variable should now be alone on one side.
4
Check your answer by substituting it back into the original equation. Both sides should be equal.

Example 1: Addition Equation

ORIGINAL EQUATION
\( x + 5 = 12 \)
SUBTRACT 5 FROM BOTH SIDES
\( x + 5 - 5 = 12 - 5 \)
SOLUTION
\( x = 7 \)

Example 2: Subtraction Equation

ORIGINAL EQUATION
\( y - 8 = 15 \)
ADD 8 TO BOTH SIDES
\( y - 8 + 8 = 15 + 8 \)
SOLUTION
\( y = 23 \)

Example 3: Multiplication Equation

ORIGINAL EQUATION
\( 4n = 36 \)
DIVIDE BOTH SIDES BY 4
\( \frac{4n}{4} = \frac{36}{4} \)
SOLUTION
\( n = 9 \)

Example 4: Division Equation

ORIGINAL EQUATION
\( \frac{m}{6} = 5 \)
MULTIPLY BOTH SIDES BY 6
\( \frac{m}{6} \times 6 = 5 \times 6 \)
SOLUTION
\( m = 30 \)

Visualizing \( x + 5 = 12 \)

0 2 4 6 7 8 10 12
\( x = 7 \)
\( +5 \)
\( 12 \)

Common Mistakes

✕ Using the Same Operation
Seeing \( x + 3 = 10 \) and adding 3 to both sides instead of subtracting. Remember: use the inverse operation.
✕ Operating on One Side Only
Subtracting 3 from the left but forgetting to subtract 3 from the right. Both sides must always be treated equally.
✕ Skipping the Check
Finding an answer but not plugging it back in. A quick check catches arithmetic errors before they cost you points.

Quick Reference Summary

If You See Do This Example Answer
\( x + a = b \) Subtract \( a \) \( x + 9 = 14 \) \( x = 5 \)
\( x - a = b \) Add \( a \) \( x - 6 = 11 \) \( x = 17 \)
\( ax = b \) Divide by \( a \) \( 7x = 42 \) \( x = 6 \)
\( \frac{x}{a} = b \) Multiply by \( a \) \( \frac{x}{5} = 8 \) \( x = 40 \)

Question 1 of 5

Solve for \( x \):
\( x + 11 = 25 \)

Question 2 of 5

Solve for \( y \):
\( y - 9 = 17 \)

Question 3 of 5

Solve for \( n \):
\( 6n = 54 \)

Question 4 of 5

Solve for \( k \):
\( \dfrac{k}{7} = 8 \)

Question 5 of 5

A student writes the following to solve \( x + 7 = 20 \):
\( x + 7 + 7 = 20 + 7 \)
What did the student do wrong?