SSAT Middle Level: Quantitative • Number Properties and Integers

Evaluate expressions with exponents.

Learn how exponents let you write and calculate repeated multiplication quickly and accurately.

SSAT Middle Level illustration with a test notebook, quantitative function, and reading book
Inside this lesson 10 sections 5 questions 9 figures

SECTION 1

Where Did Exponents Come From?

Imagine you need to multiply 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2. That's ten twos! Writing all of that out is slow and easy to mess up. Mathematicians faced the same problem hundreds of years ago. They invented exponents (a shorthand for repeated multiplication) so they could write large calculations in a tiny, clear way. Instead of ten twos, you just write 2¹⁰. Let's see how this idea developed over time.

~250 AD • Diophantus of Alexandria

The Greek mathematician Diophantus used special symbols for squares and cubes when solving equations. This was one of the earliest attempts to write repeated multiplication in a shorter way.

1637 • René Descartes Introduces Modern Notation

The French mathematician René Descartes started writing the small raised number we use today. Instead of writing x × x × x, he wrote x³. This is the same notation you use in class right now!

1700s • Euler Expands the Idea

Leonhard Euler, one of the most famous mathematicians ever, explored exponents with fractions, negative numbers, and more. His work showed that exponents are useful far beyond simple repeated multiplication.

Today • Exponents Are Everywhere

Scientists use exponents to describe the size of atoms, the distance to stars, and the speed of computer chips. On the SSAT, you will evaluate expressions that use exponents inside longer math problems.

So here is the big question this lesson answers: How do you read, evaluate, and simplify expressions that contain exponents — especially when other operations like addition, subtraction, and multiplication are mixed in?

SECTION 2

Core Principles of Exponents

Before we start calculating, you need to know a few key ideas. These are the building blocks for every exponent problem you will see on the SSAT.

1

Base and Exponent

In 5³, the base is 5 (the number being multiplied) and the exponent is 3 (how many times you multiply). You read it as "five to the third power."
2

Exponent Means Repeated Multiplication

2⁴ means 2 × 2 × 2 × 2. You are NOT multiplying 2 × 4. The exponent tells you how many copies of the base to multiply together.
3

Special Exponents: 1 and 0

Any number to the first power equals itself: 7¹ = 7. Any nonzero number to the zero power equals 1: 9⁰ = 1. These two rules are easy to forget, so memorize them!
4

Negative Bases Need Parentheses

(−3)² means (−3) × (−3) = 9. But −3² means −(3 × 3) = −9. The parentheses make a huge difference! Watch for this on the SSAT.
5

Order of Operations (PEMDAS)

Exponents come right after Parentheses in PEMDAS. Always evaluate exponents BEFORE you multiply, divide, add, or subtract.
✦

KEY TAKEAWAY

Think of an exponent like a copy machine. The base is the page you want to copy, and the exponent is how many copies you make. Then you multiply all the copies together. So 3⁴ means you make 4 copies of 3 and multiply them: 3 × 3 × 3 × 3 = 81.

SECTION 3

Seeing Exponents in Action

The diagram below shows how quickly numbers grow when you raise them to higher powers. Notice how 2 to the first power is just 2, but 2 to the sixth power is already 64. Exponents make numbers grow very fast!

Powers of 2: How Fast Exponents GrowValueExponent22¹42²82³162⁴322⁵642⁶
Each bar shows the value of 2 raised to the exponent shown on the bottom. Notice how the bar for 2⁶ = 64 is far taller than 2¹ = 2. Exponents cause exponential growth — values get big very quickly.

Look at the jump from 2⁵ = 32 to 2⁶ = 64. Every time the exponent goes up by 1, the value doubles. That's because you are multiplying by one more 2 each time. This is what makes exponents so powerful — and why you need to evaluate them carefully.

SECTION 4

The Rules You Need to Know

Here are the key formulas and rules for evaluating exponents. You do not need a calculator for the SSAT — so practice doing these by hand!

DEFINITION OF AN EXPONENT

an=a×a×a×…×a(ntimes)aⁿ = a × a × a × … × a (n times)

The base a is multiplied by itself n times. Example: 5³ = 5 × 5 × 5 = 125.

ZERO EXPONENT RULE

a0=1(aslongasa≠0)a⁰ = 1 (as long as a ≠ 0)

Any nonzero number raised to the zero power equals 1. Examples: 8⁰ = 1, 100⁰ = 1, (−4)⁰ = 1.

FIRST POWER RULE

a1=aa¹ = a

Any number raised to the first power is just itself. Example: 15¹ = 15.

NEGATIVE BASE — WITH PARENTHESES VS. WITHOUT

(−a)2=a2but−a2=−(a2)(−a)² = a² but −a² = −(a²)

If the negative sign is INSIDE the parentheses, it gets squared too: (−3)² = 9. If the negative sign is OUTSIDE, you square first, then make it negative: −3² = −9.

💡

PEMDAS Reminder

When an expression has several operations, follow this order: Parentheses → Exponents → Multiplication & Division (left to right) → Addition & Subtraction (left to right). Exponents are the second step!

SECTION 5

Common Powers You Should Memorize

Since you cannot use a calculator on the SSAT, knowing the most common powers by heart will save you time. The table and diagram below show the perfect squares, perfect cubes, and a few other handy powers.

ExpressionExpanded FormValue
2² 2 × 24
3²3 × 39
4²4 × 416
5²5 × 525
6²6 × 636
10²10 × 10100
2³2 × 2 × 28
3³3 × 3 × 327
5³5 × 5 × 5125
10³10 × 10 × 101,000

Common powers to memorize for the SSAT

Anatomy of an Exponent: 3⁴ = 8134BASE(the number you multiply)EXPONENT(how many times)Step-by-step evaluation:3⁴ = 3 × 3 × 3 × 33 × 3 = 9first pair→9 × 3 = 27times the next 3→27 × 3 = 81times the last 33⁴ = 81 ✓
This diagram breaks down 3⁴. The base (3) is the number being multiplied, and the exponent (4) tells you to multiply four 3s together: 3 × 3 = 9, then 9 × 3 = 27, then 27 × 3 = 81.

Try to memorize the perfect squares (1² through 12²) and the small perfect cubes (2³, 3³, 4³, 5³). Knowing these from memory means you can solve SSAT problems faster and more confidently.

SECTION 6

Worked Examples: Step by Step

Example 1: Evaluating 3⁴

Evaluate 3⁴

  1. 1

    Step 1 — Identify the Base and Exponent

    The base is 3 and the exponent is 4. This means we need to multiply 3 by itself 4 times.
    3⁴ = 3 × 3 × 3 × 3
  2. 2

    Step 2 — Multiply the First Pair

    Start from the left. Multiply the first two 3s together.
    3 × 3 = 9
  3. 3

    Step 3 — Multiply by the Next 3

    Take the result (9) and multiply by the next 3.
    9 × 3 = 27
  4. 4

    Step 4 — Multiply by the Last 3

    Take the result (27) and multiply by the final 3.
    27 × 3 = 81. So 3⁴ = 81.

Example 2: Order of Operations with Exponents

Evaluate 5 + 2³ × 4 − 1

  1. 1

    Step 1 — Find the Exponents (E in PEMDAS)

    There are no parentheses, so go to Exponents. The only exponent is 2³. We need to evaluate that first. 2³ = 2 × 2 × 2 = 8.
    The expression becomes: 5 + 8 × 4 − 1
  2. 2

    Step 2 — Do Multiplication (M in PEMDAS)

    Next, handle multiplication and division from left to right. We have 8 × 4.
    8 × 4 = 32. The expression becomes: 5 + 32 − 1
  3. 3

    Step 3 — Do Addition and Subtraction (left to right)

    Finally, go left to right doing addition and subtraction. First: 5 + 32 = 37. Then: 37 − 1 = 36.
    5 + 2³ × 4 − 1 = 36

Example 3: Negative Base with Parentheses

Evaluate (−2)⁴ and compare to −2⁴

  1. 1

    Step 1 — Evaluate (−2)⁴

    The parentheses tell us the entire (−2) is the base. Multiply (−2) by itself 4 times: (−2) × (−2) × (−2) × (−2).
    (−2) × (−2) = 4 (negative × negative = positive)
  2. 2

    Step 2 — Continue Multiplying

    Now take 4 × (−2) = −8. Then (−8) × (−2) = 16.
    (−2)⁴ = 16 (positive, because we had an even number of negatives)
  3. 3

    Step 3 — Now Evaluate −2⁴ (no parentheses around the negative)

    Without parentheses, the exponent only applies to 2. First calculate 2⁴ = 2 × 2 × 2 × 2 = 16. Then apply the negative sign in front.
    −2⁴ = −16 (negative, because the minus sign is not part of the base)
  4. 4

    Step 4 — Compare

    (−2)⁴ = 16, but −2⁴ = −16. They are NOT the same! Always check whether the negative sign is inside or outside the parentheses.
    (−2)⁴ = 16 ≠ −2⁴ = −16

SECTION 7

Common Mistakes and How to Avoid Them

Exponent problems aren't usually hard — but they are full of traps! Here are the most common mistakes students make, and how to dodge them.

Common MistakeWhat Students Do WrongThe Correct Approach
Multiplying instead of raisingThink 2⁴ = 2 × 4 = 82⁴ = 2 × 2 × 2 × 2 = 16
Forgetting PEMDAS orderIn 3 + 2², add first: 5² = 25Exponents first: 3 + 4 = 7
Ignoring parentheses with negativesThink −3² = 9−3² = −9. Only (−3)² = 9
Getting 0 exponent wrongThink 5⁰ = 05⁰ = 1 (any nonzero number to the zero power is 1)

Watch out for these traps on the SSAT!

⚠️

REMEMBER THIS

The number one mistake is thinking 2⁴ means 2 × 4. It does NOT! Think of it like this: if someone says "clap 4 times," you don't clap once and multiply — you actually clap four separate times. An exponent tells you to multiply the base that many separate times.

SECTION 8

Connection to More Advanced Math

Right now you are working with small whole-number exponents, like 2³ or 5⁴. But as you move into higher math, exponents will show up in many new ways. Here is a preview of what's ahead.

What You Know NowWhat You'll Learn LaterExample
Positive whole-number exponents (2³ = 8)Negative exponents (means "1 divided by")2⁻³ = 1/8
Squaring a number (5² = 25)Square roots (the reverse of squaring)√25 = 5
Evaluating one exponent at a timeExponent rules for multiplying and dividing powers2³ × 2⁴ = 2⁷
Small numbers like 3⁴ = 81Scientific notation for huge and tiny numbers3.5 × 10⁶ = 3,500,000

Exponents grow with you through math class!

You don't need to worry about these advanced topics for the SSAT Middle Level. But knowing that exponents are a building block for future math should motivate you to master them now. Everything you learn here will make those future topics much easier!

SECTION 9

Practice Problems

Try these five problems on your own. They get harder as you go. No calculator — just like the real SSAT! After you pick your answer, read the full explanation.

Question 1: CONCEPTUAL

What does 4³ mean? (A) 4 × 3 = 12 (B) 4 + 4 + 4 = 12 (C) 4 × 4 × 4 = 64 (D) 3 × 3 × 3 × 3 = 81 (E) 4 + 3 = 7
Show answer
The correct answer is (C). The expression 4³ means "multiply 4 by itself 3 times." That is 4 × 4 × 4. First, 4 × 4 = 16. Then 16 × 4 = 64. Choice (A) is a common mistake — it multiplies the base by the exponent, which is not what exponents mean. Choices (B) and (E) confuse exponents with addition.

Question 2: BASIC CALCULATION

What is the value of 2⁵? (A) 10 (B) 16 (C) 25 (D) 32 (E) 64
Show answer
The correct answer is (D). 2⁵ means 2 × 2 × 2 × 2 × 2. Work through it step by step: 2 × 2 = 4, then 4 × 2 = 8, then 8 × 2 = 16, then 16 × 2 = 32. Choice (A) is the result of multiplying 2 × 5, which is wrong. Choice (B) is 2⁴ = 16, which is one step short. Choice (E) is 2⁶ = 64, which is one step too many.

Question 3: INTERMEDIATE

What is the value of 3 × 2³ + 5? (A) 17 (B) 21 (C) 29 (D) 53 (E) 197
Show answer
The correct answer is (C). Follow PEMDAS. First, evaluate the exponent: 2³ = 2 × 2 × 2 = 8. Next, do the multiplication: 3 × 8 = 24. Finally, do the addition: 24 + 5 = 29. Choice (A) results from incorrectly computing 2³ as 2 × 3 = 6, then 3 × 6 + 5 = 23 — which doesn't even match, showing the importance of careful work. Choice (D) would come from adding before multiplying (3 × 2³ + 5 ≠ 3 × 13).

Question 4: APPLIED

A bacteria colony doubles every hour. If there are 3 bacteria at the start, the number after 4 hours is 3 × 2⁴. How many bacteria are there after 4 hours? (A) 12 (B) 24 (C) 36 (D) 48 (E) 81
Show answer
The correct answer is (D). First, evaluate the exponent: 2⁴ = 2 × 2 × 2 × 2 = 16. Then multiply by 3: 3 × 16 = 48. So there are 48 bacteria after 4 hours. Choice (A) comes from the mistake of computing 2⁴ as 2 × 4 = 8, then 3 × 8/2 = 12. Choice (C) comes from 3 × 12 = 36, another error. This problem shows how exponents appear in real-world growth situations.

Question 5: CRITICAL THINKING

What is the value of (−3)³ + 4² − 2⁰? (A) −44 (B) −12 (C) −10 (D) 42 (E) −20
Show answer
The correct answer is (B). Evaluate each exponent one at a time. First: (−3)³ = (−3) × (−3) × (−3). Start with (−3) × (−3) = 9, then 9 × (−3) = −27. Second: 4² = 4 × 4 = 16. Third: 2⁰ = 1 (any nonzero number to the zero power is 1). Now combine: −27 + 16 − 1 = −27 + 16 = −11, then −11 − 1 = −12. This problem tests three concepts at once: negative bases with odd exponents give negative results, squaring gives a positive result, and the zero exponent rule.

SUMMARY

Lesson Summary

Summary

An exponent is a shorthand for repeated multiplication. In the expression aⁿ, the base (a) is the number being multiplied, and the exponent (n) tells you how many times. Remember that any nonzero number to the zero power equals 1, and any number to the first power equals itself.

When you see exponents mixed with other operations, always follow PEMDAS: evaluate what's inside parentheses first, then exponents, then multiplication and division left to right, and finally addition and subtraction left to right. Watch out for negative bases — (−3)² = 9, but −3² = −9. Parentheses make all the difference! Memorize your common perfect squares and cubes to save time on the SSAT.

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