Average Problems - SSAT Middle Level Quantitative

  1. State the formula for the average of nn numbers with sum SS.
    A=SnA=\frac{S}{n}. The average is computed by dividing the total sum SS by the number of elements nn.
  2. State the weighted average formula for values a,ba,b with counts m,nm,n.
    ma+nbm+n\frac{ma+nb}{m+n}. The formula weights each value by its count, summing the products and dividing by total count m+nm+n.
  3. How much does the average change if one value xx is increased by 55 in a set of nn numbers?
    Increase of 5n\frac{5}{n}. Increasing one value by 55 raises the total sum by 55, so the average increases by 5/n5/n.
  4. What is the average of consecutive integers k,k+1,k+2,k+3,k+4k,k+1,k+2,k+3,k+4?
    k+2k+2. For five consecutive integers, the average is the middle term, which is k+2k+2.
  5. What is the average of two numbers aa and bb?
    a+b2\frac{a+b}{2}. The average of two numbers is their sum divided by 22.
  6. What is the new average if the average of 1010 numbers is 1212 and one number 2222 is removed?
    989\frac{98}{9}. Original sum is 10×12=12010 \times 12 = 120; subtract 2222 to get 9898, then divide by 99 for new average.
  7. Find the missing number: the average of 6,10,x6,10,x is 99.
    x=11x=11. Set up (6+10+x)/3=9(6 + 10 + x)/3 = 9, solve for xx by multiplying both sides by 33 and subtracting 1616.
  8. What is the new average if the average of 88 numbers is 99 and a number 1717 is added?
    899\frac{89}{9}. Original sum is 8×9=728 \times 9 = 72; add 1717 to get 8989, then divide by 99 for new average.
  9. What is the average of 12,18,2012,18,20?
    503\frac{50}{3}. Sum the numbers 12+18+20=5012 + 18 + 20 = 50 and divide by 33 to find the average.
  10. What is the average of 55 numbers if their sum is 6565?
    1313. Divide the total sum 6565 by the count 55 to compute the average.
  11. Find the combined average: 44 students average 8080 and 66 students average 7070.
    7474. Compute total sum as (4×80)+(6×70)=740(4 \times 80) + (6 \times 70) = 740, then divide by 1010 for combined average.
  12. State the formula for the sum SS of nn numbers with average AA.
    S=nAS=nA. The sum is obtained by multiplying the average AA by the number of elements nn.
  13. What is the average of 66 numbers if adding 33 to each number increases the average to 1414?
    1111. Adding 33 to each number increases the average by 33, so subtract 33 from 1414 to find the original average.
  14. How many numbers are in a set with sum 9696 and average 1212?
    88. Divide the sum 9696 by the average 1212 to determine the number of elements.
  15. Identify the correct expression for the average of nn numbers: sum SS divided by what quantity?
    Divide by nn. The average is the total sum SS divided by the number of elements nn.
  16. What is the average of 77 numbers if multiplying each number by 22 makes the new average 1818?
    99. Multiplying each number by 22 multiplies the average by 22, so divide 1818 by 22 to find the original average.
  17. Find xx: the average of xx and 1414 is 1010.
    x=6x=6. Set up (x+14)/2=10(x + 14)/2 = 10, multiply both sides by 22, and subtract 1414 to solve for xx.
  18. What is the total sum of scores if 55 tests have an average of 8484?
    420420. Multiply the average 8484 by the number of tests 55 to find the total sum.
  19. If the average of 44 numbers is 1111, what is the average after each number is decreased by 22?
    99. Decreasing each number by 22 decreases the average by 22, so subtract from 1111.
  20. What is the sum of 88 numbers if their average is 1515?
    120120. Multiply the average 1515 by the count 88 to determine the total sum.
  21. If the average of 99 numbers is 66, what is their sum?
    5454. Multiply the average 66 by the count 99 to compute the total sum.
  22. Find the combined average: 33 items average 1010 and 22 items average 1616.
    625\frac{62}{5}. Compute total sum as (3×10)+(2×16)=62(3 \times 10) + (2 \times 16) = 62, then divide by 55 for combined average.
  23. Find the missing number: the average of 44 numbers is 77 and three are 5,6,85,6,8.
    99. Calculate required sum as 4×7=284 \times 7 = 28, then subtract known sum 5+6+8=195 + 6 + 8 = 19 to find the missing value.
  24. Find the missing score: average of 55 tests is 9090; four scores are 88,92,85,9588,92,85,95.
    9090. Required sum is 5×90=4505 \times 90 = 450; subtract known sum 88+92+85+95=36088 + 92 + 85 + 95 = 360 to find missing score.
  25. If 55 numbers have average 88, what must the 66th number be to make the new average 99?
    1414. Original sum is 5×8=405 \times 8 = 40; new sum needed is 6×9=546 \times 9 = 54, so subtract to find the sixth number.

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