Quadratic Equations - SAT Math

  1. Find the vertex of y=−x2+4x−3y = -x^2 + 4x - 3.
    Vertex: (2,1)(2, 1). Use x=−b2a=2x = -\frac{b}{2a} = 2, then y=−(4)+8−3=1y = -(4) + 8 - 3 = 1.
  2. Factor x2−9x^2 - 9.
    (x−3)(x+3)(x - 3)(x + 3). Difference of squares: a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).
  3. What is the minimum value of y=x2−6x+9y = x^2 - 6x + 9?
    Minimum: 00. This is (x−3)2(x-3)^2, so minimum occurs at vertex (3,0)(3,0).
  4. What is the standard form of a quadratic equation?
    ax2+bx+c=0ax^2 + bx + c = 0. General form where a≠0a \neq 0 determines parabola shape.
  5. Solve for xx: x2+2x−8=0x^2 + 2x - 8 = 0.
    x=2,x=−4x = 2, x = -4. Factor as (x−2)(x+4)=0(x-2)(x+4) = 0 or use the quadratic formula.
  6. What is the discriminant of ax2+bx+c=0ax^2 + bx + c = 0?
    b2−4acb^2 - 4ac. The expression under the square root in the quadratic formula.
  7. For y=x2+4x+4y = x^2 + 4x + 4, what is the vertex?
    Vertex: (−2,0)(-2, 0). This is (x+2)2(x+2)^2, so vertex is at x=−2x = -2, y=0y = 0.
  8. What is the product of the roots of ax2+bx+c=0ax^2 + bx + c = 0?
    ca\frac{c}{a}. By Vieta's formulas relating coefficients to roots.
  9. Determine the parabola direction for y=5x2−3x+2y = 5x^2 - 3x + 2.
    Opens upwards. Positive coefficient of x2x^2 means parabola opens upward.
  10. How do you determine the number of real roots using the discriminant?
    If b2−4ac>0b^2 - 4ac > 0, 2 real roots; =0=0, 1 real root; <0<0, no real roots. The discriminant determines whether roots are real or complex.
  11. Identify the axis of symmetry for y=ax2+bx+cy = ax^2 + bx + c.
    x=−b2ax = \frac{-b}{2a}. Derived from completing the square or using calculus.
  12. What is the quadratic formula?
    x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Derived from completing the square on the general quadratic equation.
  13. What type of parabola does y=−x2y = -x^2 represent?
    A downward-opening parabola. Negative coefficient of x2x^2 makes the parabola open downward.
  14. What is the standard form of a quadratic equation?
    ax2+bx+c=0ax^2 + bx + c = 0. The general form where a≠0a \neq 0 defines a parabola.
  15. What is the vertex of y=2(x−1)2+3y = 2(x-1)^2 + 3?
    Vertex: (1,3)(1, 3). In vertex form y=a(x−h)2+ky = a(x-h)^2 + k, vertex is (h,k)(h,k).
  16. Find the x-intercepts of y=x2−4y = x^2 - 4.
    x=−2,x=2x = -2, x = 2. Set y=0y = 0: x2−4=0x^2 - 4 = 0, so x2=4x^2 = 4.
  17. State the zero-product property.
    If ab=0ab = 0, then a=0a = 0 or b=0b = 0. If a product equals zero, at least one factor must be zero.
  18. Convert y=x2−4x+4y = x^2 - 4x + 4 to vertex form.
    y=(x−2)2y = (x-2)^2. This is (x−2)2(x-2)^2 expanded, so vertex form shows vertex (2,0)(2,0).
  19. Write x2+8x+16x^2 + 8x + 16 as a square.
    (x+4)2(x + 4)^2. Perfect square trinomial with a=xa = x, b=4b = 4.
  20. Find the roots of x2−5x+6=0x^2 - 5x + 6 = 0.
    x=2,x=3x = 2, x = 3. Factor as (x−2)(x−3)=0(x-2)(x-3) = 0 to find roots.
  21. What is the axis of symmetry for y=ax2+bx+cy = ax^2 + bx + c?
    x=−b2ax = \frac{-b}{2a}. The xx-coordinate of the vertex, found by calculus or completing the square.
  22. What does a positive discriminant indicate about roots?
    Two distinct real roots. When b2−4ac>0b^2 - 4ac > 0, parabola crosses x-axis twice.
  23. Convert y=x2+6x+8y = x^2 + 6x + 8 to vertex form.
    y=(x+3)2−1y = (x+3)^2 - 1. Complete the square: (x+3)2=x2+6x+9(x+3)^2 = x^2 + 6x + 9, so subtract 1.
  24. What is the effect of increasing aa in y=ax2y = ax^2 on the parabola?
    Narrower parabola. Larger ∣a∣|a| values compress the parabola horizontally.
  25. What is the vertex form of a quadratic equation?
    y=a(x−h)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and vertical shift directly.
  26. Identify the yy-intercept of y=2x2+3x+1y = 2x^2 + 3x + 1.
    Intercept: (0,1)(0, 1). Set x=0x = 0 to find where the parabola crosses the yy-axis.
  27. State the quadratic formula.
    x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Solves any quadratic by substituting coefficients aa, bb, and cc.
  28. Find the vertex of y=x2−4x+3y = x^2 - 4x + 3.
    Vertex: (2,−1)(2, -1). Use x=42=2x = \frac{4}{2} = 2, then y=4−8+3=−1y = 4 - 8 + 3 = -1.
  29. Find the discriminant for 2x2−4x+2=02x^2 - 4x + 2 = 0.
    Discriminant: 00. Calculate b2−4ac=16−16=0b^2 - 4ac = 16 - 16 = 0.
  30. What is the discriminant in the quadratic formula?
    b2−4acb^2 - 4ac. Expression under the square root that determines root types.
  31. Which term in ax2+bx+cax^2 + bx + c affects the parabola's direction?
    The coefficient aa. Positive aa opens up, negative aa opens down.
  32. Simplify: (x+2)2(x + 2)^2.
    x2+4x+4x^2 + 4x + 4. Apply the perfect square formula (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2.
  33. Which method can solve any quadratic equation?
    The quadratic formula. Works for any quadratic, unlike factoring or square roots.
  34. Identify the vertex form of a quadratic equation.
    y=a(x−h)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and vertical stretch/compression factor aa.
  35. Find the roots of x2−5x+6=0x^2 - 5x + 6 = 0.
    x=2,x=3x = 2, x = 3. Factor as (x−2)(x−3)=0(x-2)(x-3) = 0 or use the quadratic formula.
  36. State the condition for a perfect square trinomial.
    b2=4acb^2 = 4ac. When discriminant equals zero, the quadratic is a perfect square.
  37. What is the sum of the roots of ax2+bx+c=0ax^2 + bx + c = 0?
    −ba-\frac{b}{a}. By Vieta's formulas relating coefficients to roots.
  38. Find the axis of symmetry for y=3x2+6x+1y = 3x^2 + 6x + 1.
    x=−1x = -1. Use x=−b2a=−62(3)=−1x = -\frac{b}{2a} = -\frac{6}{2(3)} = -1.
  39. Convert y=2(x−3)2+4y = 2(x-3)^2 + 4 to standard form.
    y=2x2−12x+22y = 2x^2 - 12x + 22. Expand (x−3)2=x2−6x+9(x-3)^2 = x^2 - 6x + 9, then distribute and combine.
  40. Solve 3x2−12=03x^2 - 12 = 0.
    x=2,x=−2x = 2, x = -2. Divide by 3: x2−4=0x^2 - 4 = 0, so x=±2x = \pm 2.

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