Quadratic Equations - PSAT Math

  1. What is the discriminant for ax2+bx+c=0ax^2+bx+c=0?
    b2−4acb^2-4ac. The expression under the square root in the quadratic formula.
  2. What is the vertex of y=a(x−h)2+ky=a(x-h)^2+k?
    (h,k)(h,k). The vertex is the point where the parabola reaches its extreme value.
  3. What is the discriminant of 3x2−6x+1=03x^2-6x+1=0?
    2424. Δ=(−6)2−4(3)(1)=36−12=24\Delta = (-6)^2 - 4(3)(1) = 36 - 12 = 24.
  4. What is the product of the solutions of ax2+bx+c=0ax^2+bx+c=0 in terms of aa and cc?
    r1r2=car_1r_2=\frac{c}{a}. Another application of Vieta's formulas.
  5. What is the factored form of a quadratic with zeros r1r_1 and r2r_2?
    y=a(x−r1)(x−r2)y=a(x-r_1)(x-r_2). Each factor equals zero when xx equals a root.
  6. What is the vertex xx-coordinate of y=ax2+bx+cy=ax^2+bx+c?
    −b2a-\frac{b}{2a}. The xx-value where the parabola reaches its maximum or minimum.
  7. What condition on b2−4acb^2-4ac gives no real solutions?
    b2−4ac<0b^2-4ac<0. Negative discriminant means no real square root exists.
  8. What condition on b2−4acb^2-4ac gives exactly two distinct real solutions?
    b2−4ac>0b^2-4ac>0. Positive discriminant means the square root yields two different values.
  9. State the quadratic formula for solutions of ax2+bx+c=0ax^2+bx+c=0.
    x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Derived by completing the square on the general quadratic equation.
  10. What is the yy-intercept of y=ax2+bx+cy=ax^2+bx+c?
    (0,c)(0,c). Found by substituting x=0x=0 into the equation.
  11. Find the axis of symmetry of y=2x2−8x+1y=2x^2-8x+1.
    x=2x=2. Use x=−b2a=−−82(2)=84=2x=-\frac{b}{2a} = -\frac{-8}{2(2)} = \frac{8}{4} = 2.
  12. What is the vertex form of a quadratic function?
    y=a(x−h)2+ky=a(x-h)^2+k. Shows the vertex at (h,k)(h,k) and vertical stretch/compression by aa.
  13. What is the direction of opening for y=ax2+bx+cy=ax^2+bx+c when a<0a<0?
    Opens downward. Negative leading coefficient creates an inverted U-shape.
  14. Identify the solutions of x2−5x+6=0x^2-5x+6=0.
    x=2x=2 and x=3x=3. Factor as (x−2)(x−3)=0(x-2)(x-3)=0, so x=2x=2 or x=3x=3.
  15. What is the sum of the solutions of ax2+bx+c=0ax^2+bx+c=0 in terms of aa and bb?
    r1+r2=−bar_1+r_2=-\frac{b}{a}. From Vieta's formulas for quadratic equations.
  16. Identify the yy-intercept of y=ax2+bx+cy=ax^2+bx+c.
    (0,c)(0,c). Found by setting x=0x=0 in the equation.
  17. What condition on b2−4acb^2-4ac gives exactly one real solution (a double root)?
    b2−4ac=0b^2-4ac=0. Zero discriminant makes ±0=0\pm\sqrt{0} = 0, giving one repeated solution.
  18. What does Δ<0\Delta<0 tell you about the solutions of ax2+bx+c=0ax^2+bx+c=0?
    No real solutions (two complex solutions). Negative under square root means no real solutions exist.
  19. What is the discriminant of ax2+bx+c=0ax^2+bx+c=0?
    Δ=b2−4ac\Delta=b^2-4ac. The expression under the square root in the quadratic formula.
  20. Identify the direction the parabola opens for y=ax2+bx+cy=ax^2+bx+c when a>0a>0.
    Opens upward. Positive leading coefficient creates a U-shaped parabola.
  21. What is the direction of opening for y=ax2+bx+cy=ax^2+bx+c when a>0a>0?
    Opens upward. Positive leading coefficient creates a U-shaped parabola.
  22. Identify the direction the parabola opens for y=ax2+bx+cy=ax^2+bx+c when a<0a<0.
    Opens downward. Negative leading coefficient creates an inverted U-shape.
  23. Solve for xx: 2x2+3x−2=02x^2+3x-2=0.
    x=12x=\frac{1}{2} or x=−2x=-2. Factor as (2x−1)(x+2)=0(2x-1)(x+2)=0, giving these solutions.
  24. What is the axis of symmetry for y=2x2−8x+5y=2x^2-8x+5?
    x=2x=2. Use x=−b2a=−−82(2)=84=2x = -\frac{b}{2a} = -\frac{-8}{2(2)} = \frac{8}{4} = 2.
  25. Solve for xx: x2−5x+6=0x^2-5x+6=0.
    x=2x=2 or x=3x=3. Factor as (x−2)(x−3)=0(x-2)(x-3)=0, so x=2x=2 or x=3x=3.
  26. What is the standard form of a quadratic equation in one variable?
    ax2+bx+c=0ax^2+bx+c=0, where a≠0a\ne 0. Must have a≠0a \ne 0 to ensure the equation is quadratic, not linear.
  27. What is the factored form of a quadratic with zeros r1r_1 and r2r_2?
    y=a(x−r1)(x−r2)y=a(x-r_1)(x-r_2). Each factor equals zero when xx equals a root.
  28. What is the xx-coordinate of the vertex for y=ax2+bx+cy=ax^2+bx+c?
    x=−b2ax=-\frac{b}{2a}. Found by completing the square or using calculus to find the minimum/maximum.
  29. What is the vertex form of a quadratic function?
    y=a(x−h)2+ky=a(x-h)^2+k. Shows the vertex at (h,k)(h,k) and vertical stretch/compression by aa.
  30. Identify the solutions of 2x2+3x−2=02x^2+3x-2=0.
    x=12x=\frac{1}{2} and x=−2x=-2. Factor as (2x−1)(x+2)=0(2x-1)(x+2)=0, so x=12x=\frac{1}{2} or x=−2x=-2.
  31. What does Δ=0\Delta=0 tell you about the solutions of ax2+bx+c=0ax^2+bx+c=0?
    One real solution (a repeated root). Zero discriminant makes ±0=0\pm\sqrt{0} = 0, giving one solution.
  32. What is the quadratic formula for solutions to ax2+bx+c=0ax^2+bx+c=0?
    x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Derived by completing the square on the general quadratic equation.
  33. Find the discriminant of 3x2−4x+1=03x^2-4x+1=0.
    44. Calculate b2−4ac=(−4)2−4(3)(1)=16−12=4b^2-4ac = (-4)^2-4(3)(1) = 16-12 = 4.
  34. What does Δ>0\Delta>0 tell you about the solutions of ax2+bx+c=0ax^2+bx+c=0?
    Two distinct real solutions. Positive discriminant means the square root yields two different values.
  35. Find the vertex of y=(x−3)2−5y=(x-3)^2-5.
    (3,−5)(3,-5). In vertex form y=a(x−h)2+ky=a(x-h)^2+k, the vertex is (h,k)(h,k).
  36. What is the standard form of a quadratic equation in one variable?
    ax2+bx+c=0ax^2+bx+c=0 with a≠0a\ne 0. Must have a≠0a \ne 0 to ensure the equation is quadratic, not linear.

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