Circles - PSAT Math

  1. State the chord-chord power theorem: chords intersect at EE with segments AE,EBAE,EB and CE,EDCE,ED.
    AE⋅EB=CE⋅EDAE\cdot EB=CE\cdot ED. Products of chord segments are equal at intersection.
  2. Find the arc length when r=6r=6 and θ=60∘\theta=60^\circ.
    2π2\pi. s=60360⋅2π(6)=16⋅12π=2πs=\frac{60}{360}\cdot 2\pi(6)=\frac{1}{6}\cdot 12\pi=2\pi.
  3. State the equation of a circle with center (h,k)(h,k) and radius rr in standard form.
    (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2. Standard form shows center coordinates and radius squared.
  4. What is the relationship between diameter dd and radius rr in a circle?
    d=2rd=2r. Diameter is twice the radius.
  5. Find the distance between the centers of two circles with centers (1,2)(1,2) and (4,6)(4,6).
    55. Distance formula: (4−1)2+(6−2)2=9+16=5\sqrt{(4-1)^2+(6-2)^2}=\sqrt{9+16}=5.
  6. What is the measure of an inscribed angle that intercepts an arc of measure mm degrees?
    m2\frac{m}{2}. Inscribed angle theorem: half the intercepted arc.
  7. State the area formula for a circle with radius rr.
    A=πr2A=\pi r^2. Area equals π\pi times radius squared.
  8. Identify the radius of the circle (x+1)2+(y−4)2=49(x+1)^2+(y-4)^2=49.
    77. Radius equals the square root of the constant term.
  9. Identify the center and radius of x2+y2−8x+6y=0x^2+y^2-8x+6y=0.
    Center (4,−3)(4,-3), radius 55. Complete the square: (x−4)2+(y+3)2=25(x-4)^2+(y+3)^2=25.
  10. Find the arc length for r=6r=6 and θ=60∘\theta=60^\circ.
    2π2\pi. s=60360⋅2π(6)=16⋅12π=2πs=\frac{60}{360}\cdot 2\pi(6)=\frac{1}{6}\cdot 12\pi=2\pi.
  11. What is the length of a semicircle arc with radius rr (arc only, not including the diameter)?
    πr\pi r. Half the circumference gives the semicircle arc.
  12. Find the measure of an inscribed angle that intercepts a 110∘110^\circ arc.
    55∘55^\circ. Inscribed angle is half the intercepted arc: 110°2=55°\frac{110°}{2}=55°.
  13. Find the radius if the center is (2,3)(2,3) and a point on the circle is (2,11)(2,11).
    88. Distance from (2,3)(2,3) to (2,11)(2,11) is ∣11−3∣=8|11-3|=8.
  14. State the standard form equation of a circle with center (h,k)(h,k) and radius rr.
    (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2. Standard form shows center coordinates and radius squared.
  15. Find the radius of the circle (x+5)2+(y−7)2=49(x+5)^2+(y-7)^2=49.
    77. r2=49r^2=49, so r=49=7r=\sqrt{49}=7.
  16. Use PT2=PA⋅PBPT^2=PA\cdot PB: if PA=4PA=4 and PB=16PB=16, find PTPT.
    88. PT2=4⋅16=64PT^2=4\cdot 16=64, so PT=64=8PT=\sqrt{64}=8.
  17. What is the diameter of a circle in terms of radius rr?
    d=2rd=2r. Diameter is twice the radius.
  18. State the tangent-secant power theorem from external point PP: tangent PTPT, secant meets circle at AA and BB.
    PT2=PA⋅PBPT^2=PA\cdot PB. Tangent squared equals product of secant segments from P.
  19. What is the circumference formula of a circle with radius rr?
    C=2πrC=2\pi r. Circumference equals 2π2\pi times the radius.
  20. State the standard form of a circle with center (h,k)(h,k) and radius rr.
    (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2. Standard form shows center and radius directly.
  21. State the circumference formula for a circle with radius rr.
    C=2πrC=2\pi r. Circumference equals 2π2\pi times the radius.
  22. What are the center and radius of (x−3)2+(y+2)2=25(x-3)^2+(y+2)^2=25?
    Center (3,−2)(3,-2), radius 55. Read (h,k)(h,k) from (x−h)2+(y−k)2(x-h)^2+(y-k)^2 and rr from r2=25r^2=25.
  23. What is the arc length formula for central angle θ\theta in degrees and radius rr?
    s=θ360⋅2πrs=\frac{\theta}{360}\cdot 2\pi r. Arc length is the fraction of circumference.
  24. Identify the center and radius from (x−3)2+(y+4)2=25(x-3)^2+(y+4)^2=25.
    Center (3,−4)(3,-4), radius 55. Read (h,k)(h,k) from (x−h)2+(y−k)2(x-h)^2+(y-k)^2 and r=25=5r=\sqrt{25}=5.
  25. Find the center of the circle (x+5)2+(y−7)2=49(x+5)^2+(y-7)^2=49.
    (−5,7)(-5,7). Center is (h,k)(h,k) where equation is (x−h)2+(y−k)2(x-h)^2+(y-k)^2.
  26. State the relationship between diameter dd and radius rr.
    d=2rd=2r. Diameter is twice the radius.
  27. What is the area formula of a circle with radius rr?
    A=πr2A=\pi r^2. Area equals π\pi times radius squared.
  28. What is the radius of a circle in terms of diameter dd?
    r=d2r=\frac{d}{2}. Radius is half the diameter.
  29. What is the distance formula used to find a radius from center (h,k)(h,k) to point (x,y)(x,y)?
    r=(x−h)2+(y−k)2r=\sqrt{(x-h)^2+(y-k)^2}. Distance formula gives radius from center to any point.
  30. What is the measure of a central angle that intercepts an arc of measure mm degrees?
    mm. Central angle equals its intercepted arc measure.
  31. Find the area of a sector for r=3r=3 and θ=120∘\theta=120^\circ.
    3π3\pi. A=120360⋅π(3)2=13⋅9π=3πA=\frac{120}{360}\cdot \pi(3)^2=\frac{1}{3}\cdot 9\pi=3\pi.
  32. State the sector area formula for central angle θ\theta (in degrees) and radius rr.
    A=θ360⋅πr2A=\frac{\theta}{360}\cdot \pi r^2. Fraction of full area based on angle ratio.
  33. State the equation of a circle centered at the origin with radius rr.
    x2+y2=r2x^2+y^2=r^2. Center at origin means (h,k)=(0,0)(h,k)=(0,0).
  34. State the arc length formula for central angle θ\theta in degrees and radius rr.
    s=θ360⋅2πrs=\frac{\theta}{360}\cdot 2\pi r. Arc length is the fraction of circumference for given angle.
  35. Use AE⋅EB=CE⋅EDAE\cdot EB=CE\cdot ED: if AE=3AE=3, EB=12EB=12, and CE=6CE=6, find EDED.
    66. 3⋅12=6⋅ED3\cdot 12=6\cdot ED, so ED=366=6ED=\frac{36}{6}=6.
  36. Find the arc length of a 90∘90^\circ sector in a circle of radius 88.
    4π4\pi. Use s=90360⋅2π(8)=14⋅16πs=\frac{90}{360}\cdot 2\pi(8)=\frac{1}{4}\cdot 16\pi.
  37. Which statement is always true about a radius drawn to a point of tangency?
    It is perpendicular to the tangent line. Radius meets tangent at 90°90° angle.
  38. Identify the center and radius of (x−3)2+(y+2)2=25(x-3)^2+(y+2)^2=25.
    Center (3,−2)(3,-2), radius 55. Read (h,k)(h,k) from (x−h)2+(y−k)2(x-h)^2+(y-k)^2; r2=25r^2=25 so r=5r=5.
  39. State the circumference of a circle with diameter dd.
    C=πdC=\pi d. Circumference equals π\pi times diameter.
  40. Find the area of a circle with diameter 1010.
    25π25\pi. Use A=πr2A=\pi r^2 with r=5r=5 (half of diameter).
  41. State the relationship between a tangent and the radius at the point of tangency.
    Tangent is perpendicular to the radius. Forms a 90°90° angle at the point of tangency.
  42. Find the area of a sector when r=10r=10 and θ=90∘\theta=90^\circ.
    25π25\pi. A=90360⋅π(10)2=14⋅100π=25πA=\frac{90}{360}\cdot \pi(10)^2=\frac{1}{4}\cdot 100\pi=25\pi.
  43. What is the sector area formula for central angle θ\theta in degrees and radius rr?
    A=θ360⋅πr2A=\frac{\theta}{360}\cdot \pi r^2. Sector area is the fraction of circle area.
  44. State the tangent property relating a radius to a tangent line at the point of tangency.
    A radius is perpendicular to the tangent: r⊥tangentr\perp \text{tangent}. Radius meets tangent at 90°90° angle.
  45. Identify the radius of (x+1)2+(y−2)2=494(x+1)^2+(y-2)^2=\frac{49}{4}.
    72\frac{7}{2}. r2=494r^2=\frac{49}{4}, so r=72r=\frac{7}{2}.
  46. State the circle equation with center (2,−1)(2,-1) and radius 44.
    (x−2)2+(y+1)2=16(x-2)^2+(y+1)^2=16. Substitute center (h,k)=(2,−1)(h,k)=(2,-1) and r2=16r^2=16.
  47. What is the length of a semicircle arc (not including the diameter) with radius rr?
    πr\pi r. Half the circumference, excluding the diameter.
  48. State the arc length formula for central angle θ\theta (in degrees) and radius rr.
    s=θ360⋅2πrs=\frac{\theta}{360}\cdot 2\pi r. Fraction of full circumference based on angle ratio.
  49. Find the circumference of a circle with diameter 1212.
    12π12\pi. Use C=2πrC=2\pi r with r=6r=6 (half of diameter).
  50. Find the area of a 60∘60^\circ sector of a circle with radius 66.
    6π6\pi. Use A=60360⋅π(6)2=16⋅36πA=\frac{60}{360}\cdot\pi(6)^2=\frac{1}{6}\cdot 36\pi.
  51. State the formula for the circumference of a circle with radius rr.
    C=2πrC=2\pi r. Circumference equals 2π2\pi times the radius.
  52. State the formula for the area of a circle with radius rr.
    A=πr2A=\pi r^2. Area equals π\pi times radius squared.
  53. State the sector area formula for central angle θ\theta in degrees and radius rr.
    A=θ360⋅πr2A=\frac{\theta}{360}\cdot \pi r^2. Sector area is the fraction of circle area for given angle.

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