Solving Trigonometric Equations in Context - Precalculus

  1. What is the principal range of arcsin⁡(x)\arcsin(x)?
    [−π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right]. Arcsin outputs angles from −90°-90° to 90°90° (quadrants I and IV).
  2. What is the general solution to sin⁡(x)=sin⁡(θ)\sin(x)=\sin(\theta)?
    x=θ+2πkx=\theta+2\pi k or x=π−θ+2πkx=\pi-\theta+2\pi k. Sine repeats every 2π2\pi with supplementary angle symmetry.
  3. Find all solutions on [0,2π)[0,2\pi): cos⁡(x)=−22\cos(x)=-\frac{\sqrt{2}}{2}.
    x=3π4,5π4x=\frac{3\pi}{4},\frac{5\pi}{4}. Negative cosine occurs in quadrants II and III.
  4. Identify the inverse-trig step: Solve sin⁡(x)=0.5\sin(x)=0.5 for the principal value of xx.
    x=arcsin⁡(0.5)=π6x=\arcsin(0.5)=\frac{\pi}{6}. Apply arcsin to isolate xx in the principal range.
  5. Find all solutions on [0,2π)[0,2\pi): tan⁡(x)=−3\tan(x)=-\sqrt{3}.
    x=2π3,5π3x=\frac{2\pi}{3},\frac{5\pi}{3}. Negative tangent occurs in quadrants II and IV.
  6. Identify the inverse-trig step to isolate xx in Asin⁡(Bx+C)+D=yA\sin(Bx+C)+D=y.
    x=arcsin⁡(y−DA)−CBx=\frac{\arcsin\left(\frac{y-D}{A}\right)-C}{B} (principal value). Subtract DD, divide by AA, apply arcsin, then solve for xx.
  7. What is the general solution to tan⁡(x)=tan⁡(θ)\tan(x)=\tan(\theta)?
    x=θ+πkx=\theta+\pi k. Tangent repeats every π\pi radians.
  8. What domain restriction must be checked before using arcsin⁡\arcsin or arccos⁡\arccos in an equation?
    −1≤x≤1-1\le x\le 1. Sine and cosine only output values between −1-1 and 11.
  9. What is the general solution to cos⁡(x)=cos⁡(θ)\cos(x)=\cos(\theta)?
    x=θ+2πkx=\theta+2\pi k or x=−θ+2πkx=-\theta+2\pi k. Cosine repeats every 2π2\pi with even function symmetry.
  10. What is the midline of y=Asin⁡(Bx+C)+Dy=A\sin(Bx+C)+D (or Acos⁡(Bx+C)+DA\cos(Bx+C)+D)?
    y=Dy=D. The vertical shift DD determines the horizontal midline.
  11. What general solution form solves cos⁡(θ)=cos⁡(α)\cos(\theta)=\cos(\alpha)?
    θ=±α+2πk\theta=\pm\alpha+2\pi k. Cosine has same value at ±α\pm\alpha, plus periodic repeats every 2π2\pi.
  12. Identify the inverse-trig step: Solve cos⁡(x)=12\cos(x)=\frac{1}{2} for the principal value of xx.
    x=arccos⁡(12)=π3x=\arccos\left(\frac{1}{2}\right)=\frac{\pi}{3}. Apply arccos to find the principal angle.
  13. What is the amplitude of y=Asin⁡(Bx+C)+Dy=A\sin(Bx+C)+D or y=Acos⁡(Bx+C)+Dy=A\cos(Bx+C)+D?
    ∣A∣|A|. Amplitude is the absolute value of the coefficient AA.
  14. Identify the correct solutions in [0,2π)[0,2\pi) if arcsin⁡(0.8)=α\arcsin(0.8)=\alpha is used for sin⁡(θ)=0.8\sin(\theta)=0.8.
    θ=α\theta=\alpha and θ=π−α\theta=\pi-\alpha. Arcsin gives acute angle; also need supplementary angle π−α\pi-\alpha.
  15. What is the principal range of arctan⁡(x)\arctan(x)?
    (−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right). Arctan outputs angles strictly between −90°-90° and 90°90°.
  16. What are all solutions in [0,2π)[0,2\pi) to sin⁡(θ)=12\sin(\theta)=\frac{1}{2}?
    θ=π6,5π6\theta=\frac{\pi}{6},\frac{5\pi}{6}. Reference angle π6\frac{\pi}{6}; sine positive in quadrants I and II.
  17. What is the vertical-range check for real solutions in Acos⁡(⋅)+D=yA\cos(\cdot)+D=y?
    D−∣A∣≤y≤D+∣A∣D-|A|\le y\le D+|A|. Output range is midline ±\pm amplitude.
  18. Solve on [0,2π)[0,2\pi): 2sin⁡(x)−1=02\sin(x)-1=0.
    x=π6,5π6x=\frac{\pi}{6},\frac{5\pi}{6}. First isolate sin⁡(x)=12\sin(x)=\frac{1}{2}, then find all angles.
  19. What is the period of y=Asin⁡(Bx+C)+Dy=A\sin(Bx+C)+D (or Acos⁡(Bx+C)+DA\cos(Bx+C)+D) in radians?
    2π∣B∣\frac{2\pi}{|B|}. Period formula divides 2π2\pi by the absolute value of frequency BB.
  20. Find all solutions on [0,2π)[0,2\pi): sin⁡(x)=12\sin(x)=\frac{1}{2}.
    x=π6,5π6x=\frac{\pi}{6},\frac{5\pi}{6}. Reference angle π6\frac{\pi}{6} occurs in quadrants I and II.
  21. What is the domain of arctan⁡(x)\arctan(x)?
    x∈(−∞,∞)x\in(-\infty,\infty). Tangent can take any real value as input.
  22. Interpret feasibility: If a model gives sin⁡(θ)=1.2\sin(\theta)=1.2, what conclusion is correct?
    No real solution because 1.2∉[−1,1]1.2\notin\left[-1,1\right]. Sine values must be in [−1,1][-1,1] for real solutions.
  23. What are all solutions in [0,2π)[0,2\pi) to tan⁡(θ)=3\tan(\theta)=\sqrt{3}?
    θ=π3,4π3\theta=\frac{\pi}{3},\frac{4\pi}{3}. Reference angle π3\frac{\pi}{3}; tangent positive in quadrants I and III.
  24. What is the vertical-range check for real solutions in Asin⁡(⋅)+D=yA\sin(\cdot)+D=y?
    D−∣A∣≤y≤D+∣A∣D-|A|\le y\le D+|A|. Output range is midline ±\pm amplitude.
  25. What general solution form solves tan⁡(θ)=tan⁡(α)\tan(\theta)=\tan(\alpha)?
    θ=α+πk\theta=\alpha+\pi k. Tangent repeats every π\pi radians (half the period of sine/cosine).
  26. What is the period of y=Atan⁡(Bx+C)+Dy=A\tan(Bx+C)+D?
    π∣B∣\frac{\pi}{|B|}. Tangent's period is half that of sine/cosine with same BB.
  27. Identify the inverse-trig step to isolate xx in Acos⁡(Bx+C)+D=yA\cos(Bx+C)+D=y.
    x=arccos⁡(y−DA)−CBx=\frac{\arccos\left(\frac{y-D}{A}\right)-C}{B} (principal value). Subtract DD, divide by AA, apply arccos, then solve for xx.
  28. What contextual filtering is required after solving a trig model for time tt?
    Keep only tt values in the stated interval and with correct units. Discard solutions outside domain or with wrong units for the context.
  29. What is the principal range of arccos⁡(x)\arccos(x)?
    [0,π]\left[0,\pi\right]. Arccos outputs angles from 0°0° to 180°180° (quadrants I and II).
  30. Identify the inverse-trig step: Solve tan⁡(x)=1\tan(x)=1 for the principal value of xx.
    x=arctan⁡(1)=π4x=\arctan(1)=\frac{\pi}{4}. Apply arctan to find the principal angle.
  31. What general solution form solves sin⁡(θ)=sin⁡(α)\sin(\theta)=\sin(\alpha)?
    θ=α+2πk\theta=\alpha+2\pi k or θ=π−α+2πk\theta=\pi-\alpha+2\pi k. Sine has same value at supplementary angles, plus periodic repeats.
  32. What is the domain of arcsin⁡(x)\arcsin(x) and arccos⁡(x)\arccos(x)?
    x∈[−1,1]x\in\left[-1,1\right]. Sine and cosine values range from −1-1 to 11.
  33. What are all solutions in [0,2π)[0,2\pi) to cos⁡(θ)=−12\cos(\theta)=-\frac{1}{2}?
    θ=2π3,4π3\theta=\frac{2\pi}{3},\frac{4\pi}{3}. Reference angle π3\frac{\pi}{3}; cosine negative in quadrants II and III.
  34. What is the period of y=Asin⁡(Bx+C)+Dy=A\sin(Bx+C)+D or y=Acos⁡(Bx+C)+Dy=A\cos(Bx+C)+D?
    2π∣B∣\frac{2\pi}{|B|}. Period formula divides 2π2\pi by the absolute value of BB.
  35. What is the amplitude of y=Asin⁡(Bx+C)+Dy=A\sin(Bx+C)+D (or Acos⁡(Bx+C)+DA\cos(Bx+C)+D)?
    ∣A∣|A|. Amplitude is the absolute value of the coefficient AA.

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