Solving Right Triangles: Pythagorean Theorem, Trigonometry
Precalculus · Flashcards
PRECALCULUS · FLASHCARDS
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QUESTION
Which option correctly rewrites
cos
(
20
∘
)
\cos(20^\circ)
cos
(
2
0
∘
)
using sine of a complementary angle?
QUESTION
What is
sin
(
90
∘
−
θ
)
\sin(90^\circ-\theta)
sin
(
9
0
∘
−
θ
)
equal to in terms of
θ
\theta
θ
?
QUESTION
If
cos
(
θ
)
=
0.35
\cos(\theta)=0.35
cos
(
θ
)
=
0.35
and
θ
\theta
θ
is acute, what is
sin
(
90
∘
−
θ
)
\sin(90^\circ-\theta)
sin
(
9
0
∘
−
θ
)
?
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ANSWER
sin
(
90
∘
−
θ
)
=
0.35
\sin(90^\circ-\theta)=0.35
sin
(
9
0
∘
−
θ
)
=
0.35
. By the complementary angle identity,
sin
(
90
°
−
θ
)
=
cos
(
θ
)
\sin(90°-\theta)=\cos(\theta)
sin
(
90°
−
θ
)
=
cos
(
θ
)
.
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