Constructing Inverse Trigonometric Functions
Precalculus · Flashcards · Application
PRECALCULUS · FLASHCARDS
Card 1
of 6
0 got it
0 to review
Current
Got it
Still learning
Not seen
QUESTION
Evaluate
arccos
(
−
1
2
)
\arccos\left(-\frac{1}{2}\right)
arccos
(
−
2
1
)
using the principal range of
arccos
\arccos
arccos
.
QUESTION
What is the simplified value of
arctan
(
tan
(
3
π
4
)
)
\arctan\left(\tan\left(\frac{3\pi}{4}\right)\right)
arctan
(
tan
(
4
3
π
)
)
?
QUESTION
What is the simplified value of
arccos
(
cos
(
5
π
3
)
)
\arccos\left(\cos\left(\frac{5\pi}{3}\right)\right)
arccos
(
cos
(
3
5
π
)
)
?
Tap to flip before you grade
ANSWER
π
3
\frac{\pi}{3}
3
π
.
cos
(
5
π
3
)
=
1
2
\cos(\frac{5\pi}{3})=\frac{1}{2}
cos
(
3
5
π
)
=
2
1
, and
arccos
(
1
2
)
=
π
3
\arccos(\frac{1}{2})=\frac{\pi}{3}
arccos
(
2
1
)
=
3
π
in range.
Swipe → got it · swipe ← still learning
Got it
Still learning
Flip Card
Previous card
Next card