Applying Laws of Sines and Cosines - Precalculus

  1. Identify the two-triangle condition in SSASSA with acute AA: what inequality using aa, bb, and sin⁡A\sin A gives 22 solutions?
    bsin⁡A<a<bb\sin A<a<b. Side aa can swing to two positions, creating two triangles.
  2. Identify the one-triangle condition in SSASSA with acute AA: what inequality using aa and bb guarantees 11 solution?
    a≥ba\ge b. Longer opposite side to given angle ensures unique triangle.
  3. Identify when the Law of Cosines is most directly applicable: SSSSSS, SASSAS, ASAASA, or AASAAS.
    SSSSSS or SASSAS. Use when you have all sides or two sides with included angle.
  4. Identify when the Law of Sines is most directly applicable: ASAASA, AASAAS, SSASSA, or SASSAS.
    ASAASA, AASAAS, or SSASSA. Use when you have angles and need to find sides.
  5. Find cc using the Law of Cosines: a=5a=5, b=7b=7, and C=60∘C=60^\circ.
    c=52+72−2(5)(7)cos⁡60∘c=\sqrt{5^2+7^2-2(5)(7)\cos 60^\circ}. Apply c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C with given values.
  6. Identify the number of triangles in SSASSA when AA is acute and a=ha=h (with h=bsin⁡Ah=b\sin A).
    11 triangle (right triangle). Side aa exactly reaches to form 90°90° angle.
  7. Which triangle data type typically indicates using the Law of Cosines: AASAAS, ASAASA, SSSSSS, or SASSAS?
    SSSSSS or SASSAS. All sides or two sides with included angle need cosine law.
  8. Identify the number of triangles in SSASSA when AA is acute and a≥ba\ge b (with h=bsin⁡Ah=b\sin A).
    11 triangle. Side aa long enough to reach only one position.
  9. State the Law of Cosines formula for side bb in triangle ABCABC.
    b2=a2+c2−2accos⁡Bb^2=a^2+c^2-2ac\cos B. Same pattern as for side aa, with angle BB opposite side bb.
  10. Identify the number of triangles in SSASSA when AA is acute and a<ha<h (with h=bsin⁡Ah=b\sin A).
    00 triangles. Side aa too short to reach the opposite side.
  11. What is the Law of Sines for triangle ABCABC with opposite sides aa, bb, and cc?
    asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}. Relates each side to the sine of its opposite angle.
  12. What is the Law of Cosines formula for angle AA in terms of aa, bb, and cc?
    cos⁡A=b2+c2−a22bc\cos A=\frac{b^2+c^2-a^2}{2bc}. Rearranges Law of Cosines to solve for angle.
  13. What is the circumradius form of the Law of Sines for triangle ABCABC?
    asin⁡A=bsin⁡B=csin⁡C=2R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R. RR is the circumradius of the triangle.
  14. State the Law of Cosines formula for side cc in triangle ABCABC.
    c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C. Completes the set with angle CC opposite side cc.
  15. What is the angle-sum equation used after finding two angles in a triangle?
    A+B+C=180∘A+B+C=180^\circ. Triangle angles always sum to 180°180° or π\pi radians.
  16. Find aa using the Law of Sines: A=30∘A=30^\circ, B=60∘B=60^\circ, and b=10b=10.
    a=10sin⁡30∘sin⁡60∘a=\frac{10\sin 30^\circ}{\sin 60^\circ}. Apply asin⁡A=bsin⁡B\frac{a}{\sin A}=\frac{b}{\sin B} and solve for aa.
  17. Identify the key construction to start proving the Law of Cosines: what segment is drawn in triangle ABCABC?
    Draw an altitude to form a right triangle and apply the Pythagorean Theorem. Altitude allows coordinate geometry or Pythagorean approach.
  18. What is the area formula that helps prove the Law of Sines using two sides and an included angle?
    K=12bcsin⁡AK=\frac{1}{2}bc\sin A. Area equals half the product of two sides times sine of included angle.
  19. Find sin⁡B\sin B using the Law of Sines: a=8a=8, A=40∘A=40^\circ, and b=10b=10.
    sin⁡B=10sin⁡40∘8\sin B=\frac{10\sin 40^\circ}{8}. Apply asin⁡A=bsin⁡B\frac{a}{\sin A}=\frac{b}{\sin B} and solve for sin⁡B\sin B.
  20. Which triangle data type typically indicates using the Law of Sines: AASAAS, ASAASA, SSSSSS, or SASSAS?
    ASAASA or AASAAS. Two angles known means sine ratios work best.
  21. State the Law of Cosines formula for side aa in triangle ABCABC.
    a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A. Generalizes Pythagorean theorem with cosine term for non-right triangles.
  22. What is the ambiguous case condition for possible two solutions when using the Law of Sines?
    SSASSA data with an acute given angle. Acute angle with two sides can yield 0, 1, or 2 triangles.
  23. Identify the no-triangle condition in SSASSA with acute AA: what inequality using aa, bb, and sin⁡A\sin A gives 00 solutions?
    a<bsin⁡Aa<b\sin A. Side aa too short to reach from BB to form triangle.
  24. Find cos⁡C\cos C from sides using the Law of Cosines: sides aa, bb, cc with angle CC opposite cc.
    cos⁡C=a2+b2−c22ab\cos C=\frac{a^2+b^2-c^2}{2ab}. Rearrange Law of Cosines to isolate cos⁡C\cos C.
  25. Identify the correct step to start proving the Law of Sines: drop an altitude from which vertex?
    Drop an altitude from a vertex to create two right triangles. Any vertex works; altitude creates right triangles for sine ratios.
  26. State the area formula of a triangle using two sides bb, cc and included angle AA.
    K=12bcsin⁡AK=\frac{1}{2}bc\sin A. Half the product of two sides times sine of included angle.
  27. Identify the correct method: Given aa, bb, and included angle CC, which law should you use first?
    Use the Law of Cosines first. SAS requires cosine law to find third side first.
  28. Find BB if A=40∘A=40^\circ, a=8a=8, and b=10b=10 using the Law of Sines.
    B=sin⁡−1 ⁣(10sin⁡40∘8)B=\sin^{-1}\!\left(\frac{10\sin 40^\circ}{8}\right). SSA case: use sine law but check if sin⁡B>1\sin B > 1.
  29. Identify the number of triangles in SSASSA when AA is acute and h<a<bh<a<b (with h=bsin⁡Ah=b\sin A).
    22 triangles. Side aa can swing to two positions between hh and bb.
  30. Identify the number of triangles in SSASSA when AA is obtuse and a>ba>b.
    11 triangle. Obtuse angle requires longest opposite side.
  31. What is the Law of Cosines formula for side bb in triangle ABCABC?
    b2=a2+c2−2accos⁡Bb^2=a^2+c^2-2ac\cos B. Same pattern with bb as the subject side.
  32. State the Law of Sines for triangle ABCABC with opposite sides aa, bb, and cc.
    asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}. Relates ratios of sides to sines of opposite angles in any triangle.
  33. Identify the number of triangles in SSASSA when AA is obtuse and a≤ba\le b.
    00 triangles. Obtuse angle with shorter opposite side is impossible.
  34. What is the Law of Cosines formula for side aa in triangle ABCABC?
    a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A. Generalizes Pythagorean theorem with cosine correction term.
  35. What is the Law of Cosines formula for side cc in triangle ABCABC?
    c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C. Same pattern with cc as the subject side.
  36. Identify the right-triangle condition in SSASSA with acute AA: what equality using aa, bb, and sin⁡A\sin A gives 11 solution?
    a=bsin⁡Aa=b\sin A. Side aa exactly reaches to form right angle at CC.

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