Properties for Equivalent Expressions - Pre Algebra

  1. Consider the expression 6(a+2b)−4(a+2b)+36(a + 2b) - 4(a + 2b) + 3. A student rewrites this as (6−4)(a+2b)+3=2(a+2b)+3(6 - 4)(a + 2b) + 3 = 2(a + 2b) + 3. Which property primarily justifies this transformation?
    Answer: Distributive property used in reverse, because we factored out the common binomial (a+2b)(a + 2b) The student recognized that both terms 6(a+2b)6(a + 2b) and −4(a+2b)-4(a + 2b) contain the common factor (a+2b)(a + 2b), then factored it out: 6(a+2b)−4(a+2b)=(6−4)(a+2b)6(a + 2b) - 4(a + 2b) = (6 - 4)(a + 2b). This is the distributive property used in reverse (factoring), where xy+xz=x(y+z)xy + xz = x(y + z). Choice A incorrectly describes distribution when we're actually factoring. Choice B misidentifies this as rearranging order rather than factoring. Choice C misidentifies this as regrouping rather than factoring out a common factor.
  2. Which sequence of properties correctly transforms 2x+3y+4x+y2x + 3y + 4x + y into x(2+4)+y(3+1)x(2 + 4) + y(3 + 1)?
    Answer: Commutative and associative properties to group like terms, then distributive property used in reverse to factor Starting with 2x+3y+4x+y2x + 3y + 4x + y, we need to group like terms: 2x+4x+3y+y2x + 4x + 3y + y (commutative property to rearrange), then (2x+4x)+(3y+y)(2x + 4x) + (3y + y) (associative property to regroup). Finally, we factor: x(2+4)+y(3+1)x(2 + 4) + y(3 + 1) (distributive property in reverse). Choice A misses the associative property needed for regrouping. Choice B misses the commutative property needed to rearrange terms first. Choice C incorrectly suggests we're expanding rather than factoring, and misidentifies the final step.
  3. Which expression is equivalent to 2a(3b+4)−6ab+82a(3b + 4) - 6ab + 8 after applying the distributive property and combining like terms?
    Answer: 8a+88a + 8 First apply the distributive property: 2a(3b+4)=6ab+8a2a(3b + 4) = 6ab + 8a. So the expression becomes 6ab+8a−6ab+86ab + 8a - 6ab + 8. Combining like terms: 6ab−6ab+8a+8=0+8a+8=8a+86ab - 6ab + 8a + 8 = 0 + 8a + 8 = 8a + 8. Choice B forgets the constant term 8. Choice C fails to combine the 6ab6ab terms. Choice D forgets the 8a8a term.
  4. The expression 3(x+2y)+4(2x−y)3(x + 2y) + 4(2x - y) can be rewritten as (3+8)x+(6−4)y(3 + 8)x + (6 - 4)y. Which property justifies regrouping the terms in this way?
    Answer: Both distributive and associative properties, since we distributed then regrouped terms with parentheses First, the distributive property gives us 3x+6y+8x−4y3x + 6y + 8x - 4y. To regroup as (3+8)x+(6−4)y(3 + 8)x + (6 - 4)y, we need the associative property to change the grouping from (3x+6y)+(8x−4y)(3x + 6y) + (8x - 4y) to (3x+8x)+(6y−4y)(3x + 8x) + (6y - 4y), which allows us to factor out the variables. While we do rearrange terms (commutative property), the key insight is that we're changing how terms are grouped (associative property). Choice A misses the associative property needed for regrouping. Choice B misses the distributive property needed initially and the associative property for regrouping. Choice D correctly identifies distributive property but misses that regrouping requires the associative property, not just rearranging (commutative).
  5. A student rewrites 4(2x−3)+6(x+1)4(2x - 3) + 6(x + 1) as 8x−12+6x+68x - 12 + 6x + 6, then combines like terms to get 14x−614x - 6. However, another student gets 14x+1814x + 18 for the same original expression. Which statement best explains this discrepancy?
    Answer: The second student incorrectly applied the distributive property to both terms in the expression The first student's work is completely correct: 4(2x−3)+6(x+1)=8x−12+6x+6=14x−64(2x - 3) + 6(x + 1) = 8x - 12 + 6x + 6 = 14x - 6. For the second student to get 14x+1814x + 18, they would need the constant terms to sum to +18 instead of -6, a difference of 24. This suggests they incorrectly applied the distributive property, likely getting 8x+12+6x+6=14x+188x + 12 + 6x + 6 = 14x + 18 by making 4(−3)=+124(-3) = +12 instead of −12-12. Choice A is wrong because the first student combined like terms correctly. Choice B is wrong because the first student applied the distributive property correctly to both terms. Choice D is wrong because the original expression has only one form.
  6. A student claims that 5x+3(2x+4)+x5x + 3(2x + 4) + x simplifies to 6x(2x+4)6x(2x + 4) by 'factoring out x from the first and last terms, then using the distributive property.' What error did the student make?
    Answer: The student incorrectly assumed that 6x+3(2x+4)=6x(2x+4)6x + 3(2x + 4) = 6x(2x + 4) by factoring out terms that don't have a common factor The correct simplification is 5x+3(2x+4)+x=5x+6x+12+x=12x+125x + 3(2x + 4) + x = 5x + 6x + 12 + x = 12x + 12. The student's error is assuming that 6x+3(2x+4)6x + 3(2x + 4) can be factored as 6x(2x+4)6x(2x + 4). This is incorrect because 6x6x and 3(2x+4)=6x+123(2x + 4) = 6x + 12 don't have 6x6x as a common factor—you can't factor 6x6x out of 6x+126x + 12. Choice A is wrong because the distributive property application isn't the issue. Choice B is wrong because 5x+x=6x5x + x = 6x is correct. Choice D is wrong because 5x+x=6x5x + x = 6x is arithmetically correct; the error is in the attempted factoring.
  7. Two students simplify the expression 7x+2(3x+5)+4x7x + 2(3x + 5) + 4x differently. Student A gets 17x+1017x + 10 by distributing first. Student B rearranges to get 7x+4x+2(3x+5)7x + 4x + 2(3x + 5), then 11x+2(3x+5)11x + 2(3x + 5), then 11x+6x+10=17x+1011x + 6x + 10 = 17x + 10. What advantage does Student B's method demonstrate?
    Answer: Student B's method demonstrates that combining like terms first can reduce computational complexity in some cases Student B combined the obvious like terms (7x+4x=11x7x + 4x = 11x) before distributing, which can be computationally simpler and less error-prone than distributing everything first then combining multiple like terms. Both methods are valid and yield the same result. Choice A is incorrect because distribution doesn't need to be the final step. Choice C is incorrect because this doesn't prove one property is more fundamental than another—both are needed. Choice D is incorrect because there's no requirement about which properties must be applied first; the choice depends on efficiency and personal preference.
  8. If P=2(L+W)P = 2(L + W) and Q=2L+2WQ = 2L + 2W, then which statement is true about the relationship between expressions P and Q?
    Answer: P and Q are equivalent because the distributive property shows 2(L+W)=2L+2W2(L + W) = 2L + 2W The expressions P and Q are equivalent. The distributive property states that a(b+c)=ab+aca(b + c) = ab + ac, so 2(L+W)=2⋅L+2⋅W=2L+2W2(L + W) = 2 \cdot L + 2 \cdot W = 2L + 2W. Choice B incorrectly identifies this as the commutative property, which deals with changing order (like a+b=b+aa + b = b + a), not distributing multiplication over addition. Choice C is incorrect because while parentheses do affect order of operations, the distributive property allows us to rewrite the expression equivalently. Choice D is incorrect because the associative property deals with regrouping, and it doesn't prevent distribution—in fact, properties work together to allow such transformations.
  9. A student simplifies 3(x+4)+2(x+4)−(x+4)3(x + 4) + 2(x + 4) - (x + 4) by first writing it as 3A+2A−A3A + 2A - A where A=x+4A = x + 4, then getting 4A4A, and finally substituting back to get 4(x+4)4(x + 4). What is the primary benefit of this approach?
    Answer: It reveals the common factor structure, allowing direct application of combining like terms without full expansion By substituting A=x+4A = x + 4, the student can immediately see that they have 3A+2A−A=(3+2−1)A=4A3A + 2A - A = (3 + 2 - 1)A = 4A, which is combining like terms directly. This avoids the need to expand 3(x+4)+2(x+4)−(x+4)=3x+12+2x+8−x−4=4x+163(x + 4) + 2(x + 4) - (x + 4) = 3x + 12 + 2x + 8 - x - 4 = 4x + 16, then factor back to 4(x+4)4(x + 4). Choice A is wrong because the distributive property is still being used, just in a more efficient way. Choice B is wrong because this isn't primarily about rearranging terms. Choice C is wrong because this isn't primarily about regrouping, but about recognizing common factors.

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