Linear Equation Word Problems - Pre Algebra

  1. A taxi company charges an initial fee when you get in the cab, plus a rate per mile traveled. The total cost for a 8-mile trip is $19.20, and the total cost for a 15-mile trip is $30.30. What is the cost per mile?
    Answer: $1.58 Let ff = initial fee and rr = rate per mile. We have: f+8r=19.20f + 8r = 19.20 and f+15r=30.30f + 15r = 30.30. Subtracting the first equation from the second: 7r=30.30−19.20=11.107r = 30.30 - 19.20 = 11.10. Therefore r=11.10÷7=1.585...r = 11.10 ÷ 7 = 1.585... which rounds to $1.58. Choice A ($1.45) might result from incorrectly calculating 11.10÷811.10 ÷ 8. Choice B ($1.50) might come from rounding 11.10÷711.10 ÷ 7 incorrectly. Choice D ($1.62) might result from a calculation error in the subtraction step.
  2. A tutoring service charges a registration fee plus a rate per hour of tutoring. The total cost for 8 hours of tutoring is $156, and the total cost for 12 hours is $204. A student wants to prepay for exactly enough hours so that their average cost per hour (including the registration fee) is $15.00. How many hours should they purchase?
    Answer: 20 hours Let rr = registration fee and hh = hourly rate. We have: r+8h=156r + 8h = 156 and r+12h=204r + 12h = 204. Subtracting: 4h=484h = 48, so h=12h = 12. Then r=156−96=60r = 156 - 96 = 60. For average cost of $15 per hour over nn hours: 60+12nn=15\frac{60 + 12n}{n} = 15. Solving: 60+12n=15n60 + 12n = 15n, so 60=3n60 = 3n, giving n=20n = 20. Choice A (16 hours) gives average cost 60+19216=15.75\frac{60 + 192}{16} = 15.75. Choice B (18 hours) gives 60+21618=15.33\frac{60 + 216}{18} = 15.33. Choice D (22 hours) gives 60+26422=14.73\frac{60 + 264}{22} = 14.73.
  3. A gym membership has a one-time enrollment fee plus a monthly charge. After 4 months, the total amount paid is $290. After 9 months, the total amount paid is $490. What will be the total amount paid after exactly 1 year of membership?
    Answer: $610 Let ee = enrollment fee and mm = monthly charge. We have: e+4m=290e + 4m = 290 and e+9m=490e + 9m = 490. Subtracting: 5m=2005m = 200, so m=40m = 40. Then e=290−160=130e = 290 - 160 = 130. After 12 months: 130+12(40)=130+480=610130 + 12(40) = 130 + 480 = 610. Choice B ($630) might result from miscounting months or calculation errors. Choice C ($650) might come from using an incorrect monthly rate. Choice D ($670) might result from adding the enrollment fee twice.
  4. Marcus has been saving money for a new bike. He started with some initial amount and saves the same amount each week. After 6 weeks, he had $127. After 10 weeks, he had $167. How much money did he start with?
    Answer: $67 Let ss = initial amount and ww = weekly savings. We have: s+6w=127s + 6w = 127 and s+10w=167s + 10w = 167. Subtracting the first from the second: 4w=404w = 40, so w=10w = 10. Substituting back: s+6(10)=127s + 6(10) = 127, so s=127−60=67s = 127 - 60 = 67. Choice B ($70) might result from a calculation error. Choice C ($73) might come from using the wrong equation setup. Choice D ($77) might result from adding instead of subtracting when solving for the initial amount.

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