Solving Systems by Substitution - Pre Algebra

  1. In substitution, the variables cancel and leave 0=40 = 4. What does this mean?
    The system has no solution; the lines are parallel.
  2. Solve by substitution: y=3x−1y = 3x - 1 and y=x+5y = x + 5.
    (3,8)(3, 8). Setting 3x−1=x+53x - 1 = x + 5 gives x=3x = 3, and then y=8y = 8.
  3. What are the main steps of the substitution method?
    Solve one equation for one variable, substitute that expression into the other equation, solve, then substitute back to find the other variable.
  4. In substitution, the variables cancel and leave 5=55 = 5. What does this mean?
    The system has infinitely many solutions; the equations describe the same line.
  5. Substituting y=x+3y = x + 3 into 4x+y=134x + y = 13 gives what equation, and what is xx?
    4x+x+3=134x + x + 3 = 13, so 5x=105x = 10 and x=2x = 2.
  6. After finding the value of xx in substitution, how is yy found?
    Substitute the xx-value into the isolated expression or either original equation and solve for yy.
  7. Solve by substitution: y=2xy = 2x and x+y=12x + y = 12.
    (4,8)(4, 8). Substituting gives 3x=123x = 12, so x=4x = 4 and y=8y = 8.
  8. Solve by substitution: y=x+3y = x + 3 and 2x+y=182x + y = 18.
    (5,8)(5, 8). Substituting gives 3x+3=183x + 3 = 18, so x=5x = 5 and y=8y = 8.
  9. Solve 3x−y=43x - y = 4 for yy, as a first substitution step.
    y=3x−4y = 3x - 4. Subtract 3x3x from both sides, then multiply by −1-1.
  10. Solve by substitution: x=2yx = 2y and x+3y=20x + 3y = 20.
    (8,4)(8, 4). Substituting gives 5y=205y = 20, so y=4y = 4 and x=8x = 8.
  11. For x+4y=9x + 4y = 9 and 3x−2y=53x - 2y = 5, which variable is easiest to isolate first?
    xx in the first equation, because its coefficient is 1: x=9−4yx = 9 - 4y.

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