Checking Reasonableness - Pre Algebra

  1. How do you check a solution to an equation?
    Substitute it into the original equation. The solution is correct only if both sides come out equal.
  2. A student finds that 0.5%0.5\% of 200 is 100. What is the correct value?
    1. Since 0.5%=0.0050.5\% = 0.005, the answer is 0.005×200=10.005 \times 200 = 1; 100 would be 50%50\% of 200.
  3. When a positive number is divided by a number between 0 and 1, how does the quotient compare to the original number?
    The quotient is greater than the original number. For example, 6÷0.5=126 \div 0.5 = 12.
  4. Using a compatible number, what is a good estimate of 25\frac{2}{5} of 598?
    About 240, since 598 is close to 600 and 25\frac{2}{5} of 600 is 240.
  5. How does estimation help check a calculated answer?
    Rounding the numbers gives a quick approximate answer. A result far from the estimate signals an error.
  6. A student calculates a person's height as 170 meters. Which unit would make 170 a reasonable height?
    Centimeters. 170 cm is about 1.7 m, a typical adult height.
  7. A student says 48≈6.93\sqrt{48} \approx 6.93. Between which two whole numbers must 48\sqrt{48} lie?
    6 and 7, because 36<48<4936 < 48 < 49. So 6.93 is reasonable.
  8. Which addition checks the subtraction 82−47=3582 - 47 = 35?
    35+47=8235 + 47 = 82. Adding the difference back to the number subtracted should give the starting number.
  9. What value do both sides of 3x−7=2x+113x - 7 = 2x + 11 equal when x=18x = 18 is substituted?
    47 on each side, since 54−7=4754 - 7 = 47 and 36+11=4736 + 11 = 47. Equal sides confirm the solution.
  10. A student says the mean of 72, 85 and 90 is 95. Why must this be wrong?
    A mean must lie between the least and greatest values, and 95 is greater than 90. The mean is actually 82.33.
  11. When a positive number is multiplied by a number between 0 and 1, how does the product compare to the original number?
    The product is less than the original number. For example, 8×0.25=28 \times 0.25 = 2.
  12. A student computes 19.8×5.1=1009.819.8 \times 5.1 = 1009.8. What estimate shows the decimal point is misplaced?
    20×5=10020 \times 5 = 100, so the product must be near 100. The correct product is 100.98.

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