Solve Linear Equations - Praxis Core Math

  1. If 4x+13−2=x\frac{4x+1}{3} - 2 = x, what is the value of xx?
    Answer: 5 To solve this equation, first eliminate the fraction by multiplying every term by 3: 3(4x+13)−3(2)=3(x)3(\frac{4x+1}{3}) - 3(2) = 3(x). This simplifies to 4x+1−6=3x4x+1 - 6 = 3x. Combine the constant terms on the left: 4x−5=3x4x - 5 = 3x. To solve for xx, subtract 3x3x from both sides: x−5=0x - 5 = 0. Finally, add 5 to both sides: x=5x = 5.
  2. If 12x+13x+14x=26 \frac{1}{2}x + \frac{1}{3}x + \frac{1}{4}x = 26 , what is the value of xx?
    Answer: 24 To solve for xx, first find a common denominator for the fractions, which is 12. Rewrite the equation with the common denominator: 612x+412x+312x=26\frac{6}{12}x + \frac{4}{12}x + \frac{3}{12}x = 26. Combine the terms on the left: 1312x=26\frac{13}{12}x = 26. To isolate xx, multiply both sides by the reciprocal of 1312\frac{13}{12}, which is 1213\frac{12}{13}: x=26×1213x = 26 \times \frac{12}{13}. Since 26/13=226/13 = 2, the equation becomes x=2×12=24x = 2 \times 12 = 24.
  3. What is the value of yy that satisfies the equation 4(y−1)=2(2y+3)4(y - 1) = 2(2y + 3)?
    Answer: There is no solution. Begin by distributing on both sides of the equation: 4y−4=4y+64y - 4 = 4y + 6. Next, attempt to isolate the variable yy. Subtract 4y4y from both sides: −4=6-4 = 6. This results in a statement that is false. A false statement like this indicates that there is no value of yy that can make the original equation true. Therefore, the equation has no solution.
  4. For what value of kk does the equation 3(x+2)=3x+k3(x + 2) = 3x + k have infinitely many solutions?
    Answer: 6 An equation has infinitely many solutions if it is an identity, meaning the expressions on both sides are equivalent for all values of xx. First, distribute the 3 on the left side of the equation: 3x+6=3x+k3x + 6 = 3x + k. For the two sides to be identical, the constant terms must be equal. Therefore, kk must be equal to 6.
  5. A cell phone plan costs $30 per month and includes 2 gigabytes (GB) of data. Each additional gigabyte of data costs $10. If a customer's bill was $75 for one month, not including taxes, how many total gigabytes of data did the customer use?
    Answer: 6.5 GB Let gg be the number of additional gigabytes used. The cost for additional data is 10g10g. The total bill is the base cost plus the additional data cost: 30+10g=7530 + 10g = 75. To find gg, first subtract 30 from both sides: 10g=4510g = 45. Then divide by 10: g=4.5g = 4.5. This represents the additional gigabytes. The question asks for the total gigabytes used, which is the included 2 GB plus the additional 4.5 GB. Total data = 2+4.5=6.52 + 4.5 = 6.5 GB.
  6. Two angles are supplementary. One angle measures (4x+20)(4x + 20) degrees and the other measures (2x+10)(2x + 10) degrees. What is the measure of the larger angle?
    Answer: 120 degrees Supplementary angles add up to 180 degrees. So, we set up the equation: (4x+20)+(2x+10)=180(4x + 20) + (2x + 10) = 180. Combine like terms: 6x+30=1806x + 30 = 180. Subtract 30 from both sides: 6x=1506x = 150. Divide by 6: x=25x = 25. This is the value of xx, not the angle measure. Substitute x=25x = 25 into both expressions to find the angles: 4(25)+20=100+20=1204(25) + 20 = 100 + 20 = 120 degrees, and 2(25)+10=50+10=602(25) + 10 = 50 + 10 = 60 degrees. The larger of the two angles is 120 degrees.
  7. What is the solution to the equation 23y+5=12y−1\frac{2}{3}y + 5 = \frac{1}{2}y - 1?
    Answer: -36 To eliminate the fractions, multiply the entire equation by the least common denominator of 3 and 2, which is 6. This gives: 6(23y)+6(5)=6(12y)−6(1)6(\frac{2}{3}y) + 6(5) = 6(\frac{1}{2}y) - 6(1). Simplifying, we get 4y+30=3y−64y + 30 = 3y - 6. To solve for yy, subtract 3y3y from both sides: y+30=−6y + 30 = -6. Then, subtract 30 from both sides: y=−36y = -36.
  8. At a community bake sale, pies sell for $15 and cookies sell for $2. A total of 50 items were sold, generating a revenue of $360. How many pies were sold?
    Answer: 20 Let pp be the number of pies sold. Since a total of 50 items were sold, the number of cookies sold is 50−p50 - p. The total revenue is the sum of the revenue from pies and cookies: 15p+2(50−p)=36015p + 2(50 - p) = 360. Distribute the 2: 15p+100−2p=36015p + 100 - 2p = 360. Combine like terms: 13p+100=36013p + 100 = 360. Subtract 100 from both sides: 13p=26013p = 260. Divide by 13: p=20p = 20. Thus, 20 pies were sold.
  9. If 7k−11=3k+57k - 11 = 3k + 5, what is the value of the expression 2k+12k + 1?
    Answer: 9 This is a two-step problem. First, solve the linear equation for kk. Subtract (3k) from both sides: 4k−11=54k - 11 = 5. Add 11 to both sides: 4k=164k = 16. Divide by 4: k=4k = 4. Second, substitute this value of kk into the expression 2k+12k + 1. This gives 2(4)+1=8+1=92(4) + 1 = 8 + 1 = 9. The value of the expression is 9.
  10. What is the solution to the equation z−43=z+25\frac{z-4}{3} = \frac{z+2}{5}?
    Answer: 13 To solve this proportion, cross-multiply: 5(z−4)=3(z+2)5(z-4) = 3(z+2). Distribute on both sides: 5z−20=3z+65z - 20 = 3z + 6. Next, get the variable terms on one side by subtracting 3z3z from both sides: 2z−20=62z - 20 = 6. Then, isolate the variable term by adding 20 to both sides: 2z=262z = 26. Finally, divide by 2: z=13z = 13.
  11. The perimeter of a triangle is 50 inches. The first side is 6 inches longer than the second side. The third side is twice the length of the second side. What is the length of the longest side?
    Answer: 22 inches Let the length of the second side be xx. Then the first side is x+6x+6, and the third side is 2x2x. The perimeter is the sum of the sides: x+(x+6)+2x=50x + (x+6) + 2x = 50. Combine like terms: 4x+6=504x + 6 = 50. Subtract 6 from both sides: 4x=444x = 44. Divide by 4: x=11x = 11. This is the length of the second side. The lengths of the sides are: second side = 11 inches, first side = 11+6=1711+6=17 inches, and third side = 2(11)=222(11)=22 inches. The longest side is 22 inches.
  12. Half of a number increased by 10 is equal to five less than the number. What is the number?
    Answer: 30 Let the number be nn. Translating the sentence into a mathematical equation gives: 12n+10=n−5\frac{1}{2}n + 10 = n - 5. To solve for nn, first gather the nn terms on one side. Subtract 12n\frac{1}{2}n from both sides: 10=12n−510 = \frac{1}{2}n - 5. Next, add 5 to both sides: 15=12n15 = \frac{1}{2}n. Finally, multiply both sides by 2 to isolate nn: 30=n30 = n. The number is 30.
  13. If a number is doubled and then decreased by 7, the result is the same as if the number were increased by 5. What is the number?
    Answer: 12 Let the number be xx. Translating the words into an equation gives: 2x−7=x+52x - 7 = x + 5. To solve for xx, subtract xx from both sides: x−7=5x - 7 = 5. Then, add 7 to both sides: x=12x = 12. The number is 12.
  14. The equation for converting temperature from Celsius (CC) to Fahrenheit (FF) is F=95C+32F = \frac{9}{5}C + 32. Which of the following equations correctly expresses CC in terms of FF?
    Answer: C=59(F−32)C = \frac{5}{9}(F - 32) To solve the equation F=95C+32F = \frac{9}{5}C + 32 for CC, we must isolate CC. First, subtract 32 from both sides: F−32=95CF - 32 = \frac{9}{5}C. Next, to get CC by itself, multiply both sides by the reciprocal of 95\frac{9}{5}, which is 59\frac{5}{9}. This gives 59(F−32)=C\frac{5}{9}(F - 32) = C. Thus, C=59(F−32)C = \frac{5}{9}(F - 32).
  15. The sum of three consecutive odd integers is 141. What is the largest of these three integers?
    Answer: 49 Let the three consecutive odd integers be nn, n+2n + 2, and n+4n + 4. Their sum is n+(n+2)+(n+4)=141n + (n + 2) + (n + 4) = 141. Combine like terms: 3n+6=1413n + 6 = 141. Subtract 6 from both sides: 3n=1353n = 135. Divide by 3: n=45n = 45. This is the smallest of the three integers. The integers are 45, 47, and 49. The question asks for the largest integer, which is 49.
  16. The equation A=P(1+rt)A = P(1+rt) gives the total amount AA in an account with principal PP, annual interest rate rr, and time in years tt. If an account grows to $5,250 in 10 years with an initial principal of $3,000, what is the value of rr?
    Answer: 0.075 Substitute the given values into the equation: 5250=3000(1+r⋅10)5250 = 3000(1 + r \cdot 10). First, divide both sides by 3000: 52503000=1+10r\frac{5250}{3000} = 1 + 10r. The fraction simplifies to 1.751.75. So, 1.75=1+10r1.75 = 1 + 10r. Next, subtract 1 from both sides: 0.75=10r0.75 = 10r. Finally, divide by 10 to solve for rr: r=0.7510=0.075r = \frac{0.75}{10} = 0.075.
  17. An investment of $1,200 earns simple interest. After 5 years, the total value of the investment is $1,500. Using the simple interest formula I=PrtI = Prt, where II is interest, PP is principal, rr is the annual rate, and tt is time in years, what was the annual interest rate?
    Answer: 5% First, calculate the total interest earned (II) by subtracting the principal (PP) from the final amount: I=$1,500−$1,200=$300I = \$1,500 - \$1,200 = \$300. Now, use the formula I=PrtI = Prt with I=300I=300, P=1200P=1200, and t=5t=5. The equation is 300=1200×r×5300 = 1200 \times r \times 5. Simplify the right side: 300=6000r300 = 6000r. To find the rate rr, divide both sides by 6000: r=3006000=360=120=0.05r = \frac{300}{6000} = \frac{3}{60} = \frac{1}{20} = 0.05. To express this as a percentage, multiply by 100. The annual interest rate is 5%.
  18. If 10−2(3x−1)=4x10 - 2(3x - 1) = 4x, what is the value of xx?
    Answer: 1.2 First, distribute the -2 to both terms inside the parentheses: 10−6x+2=4x10 - 6x + 2 = 4x. Be careful with the signs; −2×−1=+2-2 \times -1 = +2. Combine the constant terms on the left side: 12−6x=4x12 - 6x = 4x. To isolate the xx term, add 6x6x to both sides: 12=10x12 = 10x. Finally, divide both sides by 10: x=1210=1.2x = \frac{12}{10} = 1.2.
  19. What is the solution to the equation 4[x−2(x−3)]=84[x - 2(x-3)] = 8?
    Answer: 4 To solve this equation, work from the inside out. First, distribute the -2 inside the brackets: 4[x−2x+6]=84[x - 2x + 6] = 8. Combine the xx terms inside the brackets: 4[−x+6]=84[-x + 6] = 8. Next, distribute the 4: −4x+24=8-4x + 24 = 8. Subtract 24 from both sides: −4x=−16-4x = -16. Finally, divide by -4: x=4x = 4. Alternatively, one could divide both sides by 4 first: x−2(x−3)=2x - 2(x-3) = 2, which leads to the same result.
  20. Maria is twice as old as her brother, Sam. In 6 years, the sum of their ages will be 39. How old is Sam now?
    Answer: 9 Let Sam's current age be SS. Then Maria's current age is 2S2S. In 6 years, Sam's age will be S+6S+6 and Maria's age will be 2S+62S+6. The sum of their ages in 6 years will be 39, so (S+6)+(2S+6)=39(S+6) + (2S+6) = 39. Combine like terms: 3S+12=393S + 12 = 39. Subtract 12 from both sides: 3S=273S = 27. Divide by 3: S=9S = 9. Sam is currently 9 years old.

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